Given:

1. A sits 5^th to the right of R, who sits 7^th to the right of D.

2. 6 people sit between A and O, who sits 2^nd to the left of D.

3. T, who sits immediately between O and D, sits 2^nd to the right of J, who sits beside E.

4. I, who sits beside D, has 4 people sitting between him and M.

5. P sits to the immediate right of K, who sits 6^th to the right of B, who sits beside R.

6. C sits beside H, who sits beside M.

7. S sits to the immediate right of N, who sits 3^rd to the left of H.

8. F sits 3^rd to the left of U, who does not sit near A.

9. Q sits beside A

10. L sits between Q and G.

Thus, 21 people are sitting around the table.

Given:

1. A sits 5th to the right of R, who sits 7th to the right of D.

2. 6 people sit between A and O, who sits 2nd to the left of D.

3. T, who sits immediately between O and D, sits 2nd to the right of J, who sits beside E.

4. I, who sits beside D, has 4 people sitting between him and M.

5. P sits to the immediate right of K, who sits 6th to the right of B, who sits beside R.

6. C sits beside H, who sits beside M.

7. S sits to the immediate right of N, who sits 3rd to the left of H.

8. F sits 3rd to the left of U, who does not sit near A.

9. Q sits beside A

10. L sits between Q and G.

G and Q sit beside L.

In the case of G, N sits 7th to the left of G.

In the case of Q, C sits 7th to the left of Q.

Hence, either R or H sits 3rd to the right of the one who sits 7th to the left of the ones who sit beside L.

Given:

1. A sits 5th to the right of R, who sits 7th to the right of D.

2. 6 people sit between A and O, who sits 2nd to the left of D.

3. T, who sits immediately between O and D, sits 2nd to the right of J, who sits beside E.

4. I, who sits beside D, has 4 people sitting between him and M.

5. P sits to the immediate right of K, who sits 6th to the right of B, who sits beside R.

6. C sits beside H, who sits beside M.

7. S sits to the immediate right of N, who sits 3rd to the left of H.

8. F sits 3rd to the left of U, who does not sit near A.

9. Q sits beside A

10. L sits between Q and G.

A sits 11th to the left of N.

Hence, F sits to the immediate right of A.

Given:

1. A sits 5th to the right of R, who sits 7th to the right of D.

2. 6 people sit between A and O, who sits 2nd to the left of D.

3. T, who sits immediately between O and D, sits 2nd to the right of J, who sits beside E.

4. I, who sits beside D, has 4 people sitting between him and M.

5. P sits to the immediate right of K, who sits 6th to the right of B, who sits beside R.

6. C sits beside H, who sits beside M.

7. S sits to the immediate right of N, who sits 3rd to the left of H.

8. F sits 3rd to the left of U, who does not sit near A.

9. Q sits beside A

10. L sits between Q and G.

Hence, R sits between M and B.

Given:-

Luxury Bus B - start from City S to reach City A

Luxury Bus Z - start from City U to reach City A

Now,

Journey of Bus B:

1) Bus B starts moving 12 km in the south direction to reach town R then takes a right turn and moves 18 km to reach town P, then takes a left turn and moves 6 km to reach city A. Bus B starts moving from city S 12 km in the south direction.

2) Towns P, Q, and R lie in the same line, and the distance between P and Q is half of the distance between towns Q and R. 

It means PR = PQ + QR and PQ = QR/2. Also PR = 18 km. So,

18 = QR/2 + QR

18 = (QR + 2QR)/2

36 = 3QR

QR = 36/3 = 12 km.

PQ = QR/2 = 12/2 = 6 km.

Journey of Bus Z:

1) Bus Z starts to move 18 km toward the south and reaches town W, then takes a left turn and moves 2 km more than the distance between towns Q and R to reach city A. Bus Z starts moving from city U 18 km in the south direction. Distance between Q ad R = 12 km. 2 km more means 12 + 2 = km is the distance between town W and city A. 

2) Town V lies between U and W. It means UW = UV + VW

3) The distance between V and W is double the distance between U and V. It means VW = 2(UV)

So, UW = UV + 2(UV)

18 = 3(UV)

UV = 6 km

VW = 12 km

Combining the  journey of bus B and Z, we get,

Bus Z when reached city A was facing the East direction.

Hence, the correct answer is East.

Given:-

Luxury Bus B - start from City S to reach City A

Luxury Bus Z - start from City U to reach City A

Now, 

Journey of Bus B:

1) Bus B starts moving 12 km in the south direction to reach town R then takes a right turn and moves 18 km to reach town P, then takes a left turn and moves 6 km to reach city A. Bus B starts moving from city S 12 km in the south direction.

2) Towns P, Q, and R lie in the same line, and the distance between P and Q is half of the distance between towns Q and R. 

It means PR = PQ + QR and PQ = QR/2. Also PR = 18 km. So,

18 = QR/2 + QR

18 = (QR + 2QR)/2

36 = 3QR

QR = 36/3 = 12 km.

PQ = QR/2 = 12/2 = 6 km.

Journey of Bus Z:

1) Bus Z starts to move 18 km toward the south and reaches town W, then takes a left turn and moves 2 km more than the distance between towns Q and R to reach city A. Bus Z starts moving from city U 18 km in the south direction. Distance between Q ad R = 12 km. 2 km more means 12 + 2 = km is the distance between town W and city A. 

2) Town V lies between U and W. It means UW = UV + VW

3) The distance between V and W is double the distance between U and V. It means VW = 2(UV)

So, UW = UV + 2(UV)

18 = 3(UV)

UV = 6 km

VW = 12 km

Combining the  journey of bus B and Z, we get,

If town T lies between U and S exactly midway, then

Distance between T and the starting point of bus B = Distance between T and S = 16 km.

Hence, the correct answer is 16 km.

Given:-

Luxury Bus B - start from City S to reach City A

Luxury Bus Z - start from City U to reach City A

Now, 

Journey of Bus B:

1) Bus B starts moving 12 km in the south direction to reach town R then takes a right turn and moves 18 km to reach town P, then takes a left turn and moves 6 km to reach city A. Bus B starts moving from city S 12 km in the south direction.

2) Towns P, Q, and R lie in the same line, and the distance between P and Q is half of the distance between towns Q and R. 

It means PR = PQ + QR and PQ = QR/2. Also PR = 18 km. So,

18 = QR/2 + QR

18 = (QR + 2QR)/2

36 = 3QR

QR = 36/3 = 12 km.

PQ = QR/2 = 12/2 = 6 km.

Journey of Bus Z:

1) Bus Z starts to move 18 km toward the south and reaches town W, then takes a left turn and moves 2 km more than the distance between towns Q and R to reach city A. Bus Z starts moving from city U 18 km in the south direction. Distance between Q ad R = 12 km. 2 km more means 12 + 2 = km is the distance between town W and city A. 

2) Town V lies between U and W. It means UW = UV + VW

3) The distance between V and W is double the distance between U and V. It means VW = 2(UV)

So, UW = UV + 2(UV)

18 = 3(UV)

UV = 6 km

VW = 12 km

Combining the  journey of bus B and Z, we get,

The shortest route from the following from town V to city A -

1) Back to town W then go to city A from there → VW + WA = 12 + 14 = 26 km

2) From town V he should go 14 km in the east direction and then move south to reach city A → 14 + 6 + 6 = 26 km

3) From town V he should go north to reach point U from there, he should reach town S, then town R, then P, and then city A. → 6 + 32 + 12 + 18 + 6 = 74 km.

Both 1) and 2) are equal and shortest routes.

Hence, the correct answer is BBack to town W then go to city A from there.

Given statements: O > F ≥ E; K < L ≤ Q; P = L; E > P; Z ≥ Q

On combining: Z ≥ Q ≥ L = P > K; O > F ≥ E > L = P

Conclusions:

I. K < O → True (O > F ≥ E > L = P and L = P > K → O > K)

II. F > P → True (F ≥ E > L = P → F > P)

III. O ≤ Z → False (Z ≥ Q ≥ L = P and O > F ≥ E > L = P → relation between O and Z cannot be determined.)

Thus, both conclusions I and II are true.

Given statements: R ≤ D ≤ X; K > V ≥ I; R = O ≥ K      

On combining: X ≥ D ≥ R = O ≥ K > V ≥ I

Conclusions:

I. D ≤ V → False (D > R = O ≥ K > V → D > V)

II. X > K → False (X ≥ D > R = O ≥ K → X > K)

III. I < O → True (O ≥ K > V ≥ I → O > I)

Thus, Only III is True.

Given statements: Y > Z ≤ X; W > V ≥ U; U = X

On combining: W > V ≥ U = X ≥ Z; Y > Z

Conclusions:

I. U ≥ Z → True (U = X ≥ Z → U ≥ Z)

II. Y < V → False (Y > Z and V ≥ U = X ≥ Z → relation between Y and V cannot be determined.)

III. W > X → True (W > V ≥ U = X → W > X)

Thus, both conclusions I and III are true.