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LCM & HCF Test 472
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LCM & HCF Test 472
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  • Question 1/10
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    The ratio of two numbers is 5 : 7 and their HCF is 3. Their LCM is:
    Solutions

    The ratio of two numbers = 5 : 7

    HCF = 3

    LCM = 5 × 3 × 7 = 105

    Hence, option B is the correct answer.

  • Question 2/10
    1 / -0.25

    Let x be a number between 1420 and 1780 such that when x is divided by 10, 15, 24 and 32, the remainder in each case is 7. The sum of the digits of x is:

    Solutions

    10 = 2 × 5

    15 = 3 × 5

    24 = 23 × 3

    32 = 25

    LCM of 10, 15, 24 and 32 = 25 × 3 × 5 = 480

    Required number = 3 × 480 + 7 = 1440 + 7 = 1447 = x

    Sum of digits of x = 1 + 4 + 4 + 7 = 16

  • Question 3/10
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    The greatest number that on dividing 2675 and 2320 leaves the reminders 5 and 6, respectively, is:
    Solutions

    2675 – 5 = 2670 = 2 × 3 × 5 × 89

    2320 – 6 = 2314 = 2 × 13 × 89

    Required number = HCF of 2670 and 2314 = 2 × 89 = 178

  • Question 4/10
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    The greatest number that will divide 398, 437 and 5425 leaving 7, 12 and 2 as remainders, respectively, is:
    Solutions

    398 – 7 = 391 = 17 × 23

    437 – 12 = 425 = 52 × 17

    5425 – 2 = 5423 = 11 × 17 × 29

    Required number = HCF of 391, 425 and 5423 = 17

  • Question 5/10
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    The least number of square tiles required to pave the ceiling of a room, 12 m 95 cm long and 3 m 85 cm broad, is:
    Solutions

    For least number of square tiles, we will take HCF of given dimensions 12 m 95 cm and 3 m 85 cm.

    HCF of 1295 and 385 = 35

    Therefore, the tiles should be of dimension 35 cm × 35 cm.

    Required least no. of tiles =  = 407

  • Question 6/10
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    The HCF and LCM of two numbers are 8 and 224, respectively. If the ratio of the two numbers is 4 : 7, then the greater of the two numbers is:
    Solutions

    Let the greater number be 7x.

    Then, smaller number = (7x) ×  = 4x

    Now, we know that multiplication of HCF and LCM of two numbers is equal to multiplication of these numbers.

    Therefore,

    HCF × LCM = Multiplication of numbers

    8 × 224 = (4x) × (7x)

    28x2 = 1792

    x2 = 1792/28

    x2 = 64

    x =  = 8

    Therefore, greater number = 7x = 7 × 8 = 56

    Hence, option D is the correct answer.

  • Question 7/10
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    If X is a three digits number when divided by 33852 and 22965 leaves same remainder in each case, then find the value of x?
    Solutions

    The number will be difference of 33852 and 22965 or factor of it = 33852- 22965 = 10887

    Factors of 10887 = 3×19×191

    So, possible three digit numbers are 191 and 191×3.

    Therefore, two numbers 191 and 573 are possible.

  • Question 8/10
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    What will be the ratio of Highest common Factor and Least Common Multiple of two numbers 14 and 18?
    Solutions

    We will find common factor and common multiple of 14 and 18 respectively.

    14 = 2 × 7 and 18 = 3 × 3 × 2

    HCF = 2 and

    LCM = 2 × 7 × 9 = 126

    HCF : LCM = 2 : 126 = 1 : 63

  • Question 9/10
    1 / -0.25

    What is the Highest Common Factor of 23 × 35 and 33 × 52?
    Solutions

    Highest common factor of 23 × 35 and 33 × 52

    Here only 33 is common.

    Therefore, the Highest Common Factor of 23 × 35 and 33 × 52 is 33.

  • Question 10/10
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    The HCF of two numbers is 11 and their LCM is 693. If one of the numbers is 77, find the other.

    Solutions
    We know that,

    First number × second number = LCM × HCF

    77 × second number = 693 × 11

    second number = 99

    Hence, option B is the correct answer.

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