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Quant - Arithmetic Test 583
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Quant - Arithmetic Test 583

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  • Question 1/5
    1 / -0.25
    If the speed of a boat downstream is double the speed of the boat upstream, then find the ratio of speed of boat in still water to speed upstream.
    Solutions
    Let the speed of the boat in still water be X and speed of stream be Y.

    Speed of the boat downstream = X + Y

    Speed of the boat upstream = X – Y

    = 2 (As given in the question)

    X+Y = 2X – 2Y

    X = 3Y

    Speed of the boat in still water = X

    Speed of the boat upstream = X – Y = 3Y – Y = 2Y

    Ratio of speed of boat in still water to speed upstream = 3Y: 2Y = 3: 2
  • Question 2/5
    1 / -0.25
    The ratio of father’s age to his son’s age is 9:5. The product of their age is 1620. The ratio of their ages after 6 years will be
    Solutions
    Given, ratio of father’s age to his son’s age is 9:5.
    Let their ages be 9x and 5x respectively.
    Given, product of their age is 1620.
    ∴9x × 5x = 1620
    ⇒x2 = 36
    ⇒x = 6
    Father’s present age = 9 × 6 = 54
    Son’s present age = 5 × 6 = 30
    Ratio of their ages after 6 years = (60/36) = 5 : 3
  • Question 3/5
    1 / -0.25
    A group of college girls planned for a trip & thus each girl contributed the amount equal to seven times the number of girls up for the trip. The total collection came out to be Rs 19663. How many girls were there in the group?
    Solutions

    Let number of girls be x. Each contributed = 7x
    Total contribution = 7x2= 19663     ⇒ x2 = 2809 ⇒ x = 53

  • Question 4/5
    1 / -0.25
    A tap can fill a tank in 16 hours whereas another tap can empty the tank it in 8 hours. If in a three fourth filled tank both the taps are opened, then how long will it take to empty the tank in this scenario?
    Solutions
    Let the capacity of the tank be C
    Speed of inlet tap = C/16
    Speed of outlet tap = C/8
    Difference in speed = C/8 – C/16 = C/16 hours
    Time to empty 3/4th of the tank = (3C/ 4)/ C/16 = 3C/4 * 16/C = 12 hours
  • Question 5/5
    1 / -0.25
    In 1 kg mixture of stone and rice, 20% is rice. How much stone should be added so that the proportion of rice becomes 10%?
    Solutions
    In 1 kg mixture quantity of rice = 200 gm
    Let x gm stone should be added, then
    10% of (1000+ x) = 200
    x = 1000 gm = 1kg
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