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RRB Officer Scale I 2017 : Prelim Mock Test 3
Result
RRB Officer Scale I 2017 : Prelim Mock Test 3
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  • Question 1/41
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    Directions for Below Question :

    What approximate value should come in place of question mark (?) in the following equation?

    Question :

    32.05% of 259.99 + 49.73% of 789.853 =?

    Solutions

    ? = 32.05% of 259.99 + 49.73% of 789.853

    = 32% of 260 + 50% of 790 = 83.2 + 395 = 478.2 ≈ 478

  • Question 2/41
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    Directions for Below Question :

    What approximate value should come in place of question mark (?) in the following equation?

    Question :

    4.78% of 1255 + 3.24% of 4400 = 2.5% of ?

    Solutions

    4.78% of 1255 + 3.24% of 4400 = 2.5% of ?

    => 2.5% of ? = 202.54900

    => ? = 200 x 100/2.5 = 8000

     

  • Question 3/41
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    Directions for Below Question :

    What approximate value should come in place of question mark (?) in the following equation?

    Question :

    35.0555% of 3365.00012 + 8900.0043 ÷ 41.99903 = ?

    Solutions

    ? = 35.0555% of 3365.00012 + 8900.0043 ÷ 41.99903

    = 35% of 3365 + 8900/42

    = 1177.75 + 211.904762

    = 1389.65476

    ≈ 1390

     

  • Question 4/41
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    Directions for Below Question :

    What approximate value should come in place of question mark (?) in the following equation?

    Question :

    (385% of 463) ÷179 + (485% of 837) ÷ 164 = ?

    Solutions

    ? = (385% of 463) ÷179 + (485% of 837) ÷ 164

    = 9.96 + 24.75

    = 34.71

    ≈ 35

  • Question 5/41
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    Directions for Below Question :

    What approximate value should come in place of question mark (?) in the following equation?

    Question :

    84.04% of 18.45 + 23.97% of 17.05 0= ?

     

    Solutions

    ? = 84.04% of 18.45 + 23.97% of 17.05 = 19.59 = 20

  • Question 6/41
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    Directions for Below Question :

    What should come in place of the question mark (?) in the following series ?

    Question :

    29 110 ? 223 259 284

    Solutions

    29 + 92 = 110

    110 + 82 = 174

    174 + 72 = 223

    223 + 62 = 259

    259 + 52 = 284

     

  • Question 7/41
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    Directions for Below Question :

    What should come in place of the question mark (?) in the following series ?

    Question :

    0 3 9 21 45 93 ?

    Solutions

    0 + 3 = 3

    3 + 6 = 9

    9 + 12 = 21

    21 + 24 = 45

    45 + 48 = 93

    ? = 93 + 96 = 189

     

  • Question 8/41
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    Directions for Below Question :

    What should come in place of the question mark (?) in the following series ?

    Question :

    10 17 48 165 688 3475 ?

    Solutions

    10*1 + 1*7 = 17

    17*2 + 2*7 = 48

    48*3 + 3*7 = 165

    165*4 + 4*7 = 688

    688*5 + 5*7 = 3475

    ? = 3475*6 + 6*7 = 20892

     

  • Question 9/41
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    Directions for Below Question :

    What should come in place of the question mark (?) in the following series ?

    Question :

    5 15 120 1800 43200 1512000 ?

    Solutions

    5*(0+3) = 15

    15 *(0+ 3 + 5) = 120

    120*(0+ 3 + 5 + 7) = 1800

    1800*(0+ 3 + 5 + 7 + 9) =43200

    43200*(0+ 3 + 5 + 7 + 9 + 11) = 1512000

    ? = 1512000*(0+ 3 + 5 + 7 + 9 + 11 + 13) = 72576000

     

  • Question 10/41
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    Directions for Below Question :

    What should come in place of the question mark (?) in the following series ?

    Question :

    3, 2, 14, 35, 107, ?

    Solutions

    3 + 1³ – 2 = 2

    2 + 2³ + 4 = 14

    14 + 3³ – 6 = 35

    35 + 4³ + 8 = 107

    107 + 5³ - 10 = 222

  • Question 11/41
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    Directions for Below Question :

    In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.

    Question :

    I. x² = 64

    II. y² – 30y + 225 = 0

     

    Solutions

    x² = 64

    => x = 8, – 8

    y² – 30y + 225 = 0

    => y = 15

    So, X < Y

     

  • Question 12/41
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    Directions for Below Question :

    In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.

    Question :

    I. 3x² + 5x – 2 = 0

    II. 5y² – 18y + 9 = 0

     

    Solutions

    3x² + 5x – 2 = 0

    => x = 0.33, -2

    5y² – 18y + 9 = 0

    => y = 3, 0.6

    So, X < Y

     

  • Question 13/41
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    Directions for Below Question :

    In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.

    Question :

    I. x² – 20x – 525 = 0

    II. y² + 40y + 391 = 0

     

    Solutions

    x² – 20x – 525 = 0

    => x = 35, -15

    y² + 40y + 391 = 0

    => y = -23, -17

    So, X > Y

  • Question 14/41
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    Directions for Below Question :

    In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.

    Question :

    I. (x – 2)(x – 3) = (x – 4)(x – 5)

    II. (y – 6)(y – 5) = (y – 4)(y – 3)

     

    Solutions

    (x – 2)(x – 3) = (x – 4)(x – 5)

    => 4x = 14

    => x = 3.5

    (y – 6)(y – 5) = (y – 4)(y – 3)

    => 4y = 18;

    => y = 4.5

    So, X < Y

     

  • Question 15/41
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    Directions for Below Question :

    In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.

    Question :

    I. 2x² + x – 300 = 0

    II. y² – 45y + 324 = 0

    Solutions

    2x² + x – 300 = 0

    => x = 12, -12.5

    y² – 45y + 324 = 0

    => y = 36, 9

    So, relation cannot be established

     

  • Question 16/41
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    Pankaj and Chahat enter into a partnership investing Rs. 24000 and Rs. 32000 respectively. After 8 months, Rajan also joins the business with capital of Rs. 30000. The share of Rajan in a profit of Rs. 91200 after 2 years will be:

    Solutions

    Ratio of profit Pankaj, Chahat and Rajan

    = 24000 × 24 : 32000 × 24 : 30000 × 16 = 6 : 8 : 5

    Hence, Share of Rajan in profit = 5/19 × 91200 = Rs. 24000

     

  • Question 17/41
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    In a co-education school there are 20 more girls than boys. If the number of girls is increased by 20% and the number of boys is also increased by 32%, there would be 18 more girls than boys. What is the number of students in the school?

    Solutions

    Let number of boys = b

    Then, number of girls = b + 20

    New number of girls = (b + 20) x 1.2

    Then, number of boys = b x 1.32

    From the question,

    (b + 20) x 1.2 = 18 + b x 1.32

    => 1.2b + 24 = 18 + 1.32b

    => 0.12b = 6

    => b = 6/0.12 = 50

    So, number of girls = b + 20 = 70

    Hence, the number of students in the school = 70 + 50 = 120

     

  • Question 18/41
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    Mr. Gyan Chand spends 23% of an amount of money on an insurance policy, 33% on food, 19% on children’s education and 16% on recreation. He deposits the remaining amount of Rs. 504 in bank. How much total amount does he spend on food and insurance policy together?

    Solutions

    Let the total amount of money be ‘x’

    x – (23+33+19+16) * x/100 = 504

    => x * 9/100 = 504

    => x = 50400/9

    => x = 5600

    Amount spend on food & Insurance = (23+33) * 5600/100 = 3136

     

  • Question 19/41
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    A rectangular courtyard 3.78 m long and 5.25 m broad is to be paved exactly with square tiles, all of the same size. What will be the minimum number of such tiles?

    Solutions

    Length of the rectangle = 3.78 m = 378 cm ≡378 = 2 * 3 * 3 * 3 * 7

    Breadth of the rectangle = 5.25 m = 525 cm ≡ 525 = 3 * 5 * 5 * 7

    Highest Common Factor(HCF) of (378 and 525)= 3 * 7 = 21

    Size of largest square tile = 0.21 m x 0.21 m

    Minimum Number of tiles = (3.78 * 5.25)/(0.21 * 0.21) = 450

     

  • Question 20/41
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    A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1 hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 6 hours when the inlet pipe is plugged. If there is a leakage also which is capable of draining out the water from the tank at half of the rate of the outlet pipe, then what is the time taken to fill the empty tank when both the pipes are opened?

     

    Solutions

    Inlet pipe Efficiency = 100/(8/6) = 75%

    Outlet pipe Efficiency = 100/(6) = 16.66%

    Efficiency of leakage = half of the rate of the outlet pipe = 8.33%

    Net Efficiency = 75 – (16.66 + 8.33) = 50%

    Required time = 100/50 = 2 hours

     

  • Question 21/41
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    Directions for Below Question :

    Study the following graph and answer the questions below. 
    Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002.

    Question :

    What was the population (in Lakhs) of Shimla in 2001?

    Solutions

    Population of Shimla in 2001 = 1.5 * 100/110 = 1.36 Lakhs

  • Question 22/41
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    Directions for Below Question :

    Study the following graph and answer the questions below. 
    Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002.

    Question :

    The population of Nainital in 2002 was same as that of of Shimla in 2001, then find average of total population of three cities over 2001 and 2002?

     

    Solutions

    The population of Nainital in 2002 = Population of Shimla in 2001 = 1.36 lakh

    So, Population of Nainital in 2001 = 1.36 * 100/92 = 1.48 Lakhs

    Average = (1.36 + 1.50 + 3 + 4 + 1.48 + 1.36)/6 = 12.7/6=2.12 Lakhs

  • Question 23/41
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    Directions for Below Question :

    Study the following graph and answer the questions below. 
    Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002.

    Question :

    What is the percentage increase in the population of Ooty from 2001 to 2002?

     

    Solutions

    The percentage increase in the population of Ooty from 2001 to 2002 = (4 x 100/3) – 100 = 33 1/3%

  • Question 24/41
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    Directions for Below Question :

    Study the following graph and answer the questions below. 
    Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002.

    Question :

    If in Shimla, population increases by 10% every year, then what was the population (approximately) of Shimla in 2005?

     

    Solutions

    Population of Shimla in 2002 = 1.5 Lakhs

    Population of Shimla in 2005 = 1.5* (110/100) * (110/100) * (110/100) = 1.9965 ≈ 2 Lakhs

  • Question 25/41
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    Directions for Below Question :

    Study the following graph and answer the questions below. 
    Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002.

    Question :

    The population of Shimla in 2001 is what percent less than population of Ooty in 2002?

     

    Solutions

    The population of Shimla in 2001 = 1.5 * 100/110 = 1.36 Lakhs

    The population of Ooty in 2002 = 4 lakhs

    Required % = (4 – 1.36)/4 * 100 = 66%

  • Question 26/41
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    Directions for Below Question :

    Study the following radar graph carefully to answer the questions that follow :
    Number of seats won by various political parties in the legislative assemblies of different states 

    Question :

    The total number of seats won by the C is what per cent more or less than that by the D in all states together?

    Solutions

    The total number of seats won by the C = 5 + 10 + 30 + 20 + 10 + 20 + 10 + 15 = 120

    The total number of seats won by the D = 15 + 30 + 25 + 15 + 20 + 5 + 15 + 5 = 130

    So, required % = (130 - 120)/130 x 100 = 7.69% less

     

  • Question 27/41
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    Directions for Below Question :

    Study the following radar graph carefully to answer the questions that follow :
    Number of seats won by various political parties in the legislative assemblies of different states 

    Question :

    What is the ratio of the total number of seats won by the A to the total number of seats won by the B in all states together?

    Solutions

    The total number of seats won by the A in all states together = 30 + 5 + 15 + 10 + 25 + 25 + 30 + 20 = 160

    The total number of seats won by the B in all states together = 20 + 15 + 5 + 25 + 30 + 10 + 25 + 10 = 140

    So, required ratio = 160 : 140 = 8 : 7

  • Question 28/41
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    Directions for Below Question :

    Study the following radar graph carefully to answer the questions that follow :
    Number of seats won by various political parties in the legislative assemblies of different states 

    Question :

    If 30% seats of the Maharashtra legislative assembly are won the females and 40% seats of the Gujarat legislative assembly are won by the females, then the male members of the Maharashtra legislative assembly are what per cent more or less than the male members of the Gujarat legislative assembly?

    Solutions

    The male members of the Maharashtra legislative assembly = (30 + 20 + 5 + 15) x 70/100 = 49

    The male members of the Gujarat legislative assembly = (25 + 10 + 20 + 5) x 60/100 = 36

    So, required % = (49 - 36)/36 x 100 = 36.11% more

     

  • Question 29/41
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    Directions for Below Question :

    Study the following radar graph carefully to answer the questions that follow :
    Number of seats won by various political parties in the legislative assemblies of different states 

    Question :

    40% members of the Haryana legislative assembly and 50% members of the UP legislative assembly are charge sheeted for involvement in crimes. Among these, 50% and 20% are females in the Haryana and UP legislative assembly respectively. Then the number of male members of the Haryana legislative assembly who are charge sheeted is what percentage more or less than the number of female members of the UP legislative assembly who are charge sheeted?

    Solutions

    The number of male members of the Haryana legislative assembly who are charge sheeted

    = (20 + 10 + 15 + 5) x 40/100 x 50/100 = 10

    The number of female members of the UP legislative assembly who are charge sheeted

    = (10 + 25 + 20 + 15) x 50/100 x 20/100 = 7

    So, required % = (10 - 7)/7 x 100 = 42.86% more

     

  • Question 30/41
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    Directions for Below Question :

    Study the following radar graph carefully to answer the questions that follow :
    Number of seats won by various political parties in the legislative assemblies of different states 

    Question :

    Which political party won the highest number of seats in the given eight states?

    Solutions

    The total number of seats won by the A in all states together = 30 + 5 + 15 + 10 + 25 + 25 + 30 + 20 = 160

    The total number of seats won by the B in all states together = 20 + 15 + 5 + 25 + 30 + 10 + 25 + 10 = 140

    The total number of seats won by the C in all states together = 5 + 10 + 30 + 20 + 10 + 20 + 10 + 15 = 120

    The total number of seats won by the D in all states together = 15 + 30 + 25 + 15 + 20 + 5 + 15 + 5 = 130

     

  • Question 31/41
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    In how many ways, the letters of word ASSASSINATION can be arranged so that the words always start with A and end with N.

  • Question 32/41
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    Anwar, Barnwaal and Singh start at the same time in the same direction to run around a circular stadium. Anwar completes a round in 126 seconds, Barnwaal in 154 seconds and Singh in 99 seconds, all starting at the same point. After what time will they again at the starting point?

    Solutions

    LCM of 126, 154 and 99 = 1386

    So, Anwar, Barnwaal and Singh will again meet at the starting point in

    = 1386 sec = 1386/60 min = 23 min 6 sec

     

  • Question 33/41
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    Chetak borrowed a sum of Rs. 2300 from Akash at the simple rate of 6% per annum for 3 yr. Then, he added some more money to the borrowed sum and lent it to Dhayanchand for the same time at 18% per annum at simple interest. If Chetak gains Rs. 274.95 by way of interest on borrowed sum as well as his own amount from the whole transaction, then what is the approximate sum lent by him to Dhayanchand?

    Solutions

    Let Rs. P be the sum lent by Chetak to Dhayanchand.

    According to the question,

    (P x 3 x 18)/100 – (2300 x 3 x 6)/100 = 274.95

    => 54P – 41400 = 27495

    => 54P = 27495 + 41400 = 68895

    => P = 68895/54 = Rs. 1275(approx)

     

  • Question 34/41
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    When A and B are working alone, they can complete a piece of work in 8 days and 12 days respectively. On day 1, B started the work and A Joined B from day 3 on-wards. Find approximately after how many days will the work be completed?

    Solutions

    Fraction of work completed by B on day 1 and day 2 = 2* 1/12 = 1/6

    Fraction of work left after 2 days = 1 – 1/6 = 5/6

    Fraction of work completed by Both = 1/8 + 1/12 = 5/24

    Number of days after day 2 to complete work = 5/6 x 24/5 = 4 days

    So after 2+4 = 6 days works will be completed

     

  • Question 35/41
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    The average height of 18 girls is 117 13/18 cm. The average height of 21 boys is 104 13/21 cm. What is the overall average height of all the students together in the class?

    Solutions

    Average height of the class

    = [18 * (117 * 18 + 13)/18 + 21 * (104 * 21 + 13)/21]/(18 + 21)

    = (2119 + 2197)/ 39 = 4316/ 39 = 332/3 = 110 2/3 cm

     

  • Question 36/41
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    Directions for Below Question :

    What should come in place of the question mark in each of the following number series?

    Question :

    2, 4, 9, 19, ?, 62

    Solutions

    2 + 2 = 4

    4 + (2 + 3) = 9

    9 + (5 + 5) = 19

    19 + (10 + 7) = 36

    36 + (17 + 9) = 62

  • Question 37/41
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    Directions for Below Question :

    What should come in place of the question mark in each of the following number series?

    Question :

    5, 6, 14, 45, 184, ?

    Solutions

    5 x 1 + 1 = 6

    6 x 2 + 2 = 14

    14 x 3 + 3 = 45

    45 x 4 + 4 = 184

    184 x 5 + 5 = 925

     

  • Question 38/41
    1 / -0

    Directions for Below Question :

    What should come in place of the question mark in each of the following number series?

    Question :

    42, 45, 53, 66, 84, ?

    Solutions

    42 + 3 = 45

    45 + (3 + 5) = 53

    53 + (8 + 5) = 66

    66 + (13 + 5) = 84

    84 + (18 + 5) = 107

     

  • Question 39/41
    1 / -0

    Directions for Below Question :

    What should come in place of the question mark in each of the following number series?

    Question :

    8, 4, 4, 8, 32, ?

    Solutions

    8 x 0.5 = 4

    4 x 1 = 4

    4 x 2 = 8

    8 x 4 = 32

    32 x 8 = 256

     

     

  • Question 40/41
    1 / -0

    Directions for Below Question :

    What should come in place of the question mark in each of the following number series?

    Question :

    12, 15, 21, 33, ?, 105

    Solutions

    The pattern of the series is:

    12 + 3 = 15

    15 + 6 = 21

    21 + 12 = 33

    33 + 24 = 57

    57 + 48 = 105

  • Question 41/41
    1 / -0

    Chetak borrowed a sum of Rs. 2300 from Akash at the simple rate of 6% per annum for 3 yr. Then, he added some more money to the borrowed sum and lent it to Dhayanchand for the same time at 18% per annum at simple interest. If Chetak gains Rs. 274.95 by way of interest on borrowed sum as well as his own amount from the whole transaction, then what is the approximate sum lent by him to Dhayanchand?

    Solutions

    Let Rs. P be the sum lent by Chetak to Dhayanchand.

    According to the question,

    (P x 3 x 18)/100 – (2300 x 3 x 6)/100 = 274.95

    => 54P – 41400 = 27495

    => 54P = 27495 + 41400 = 68895

    => P = 68895/54 = Rs. 1275(approx)

     

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