Please wait...
/
-
Directions for Below Question :
What approximate value should come in place of question mark (?) in the following equation?
Question :
32.05% of 259.99 + 49.73% of 789.853 =?
? = 32.05% of 259.99 + 49.73% of 789.853
= 32% of 260 + 50% of 790 = 83.2 + 395 = 478.2 ≈ 478
4.78% of 1255 + 3.24% of 4400 = 2.5% of ?
=> 2.5% of ? = 202.54900
=> ? = 200 x 100/2.5 = 8000
35.0555% of 3365.00012 + 8900.0043 ÷ 41.99903 = ?
? = 35.0555% of 3365.00012 + 8900.0043 ÷ 41.99903
= 35% of 3365 + 8900/42
= 1177.75 + 211.904762
= 1389.65476
≈ 1390
(385% of 463) ÷179 + (485% of 837) ÷ 164 = ?
? = (385% of 463) ÷179 + (485% of 837) ÷ 164
= 9.96 + 24.75
= 34.71
≈ 35
84.04% of 18.45 + 23.97% of 17.05 0= ?
? = 84.04% of 18.45 + 23.97% of 17.05 = 19.59 = 20
What should come in place of the question mark (?) in the following series ?
29 110 ? 223 259 284
29 + 92 = 110
110 + 82 = 174
174 + 72 = 223
223 + 62 = 259
259 + 52 = 284
0 3 9 21 45 93 ?
0 + 3 = 3
3 + 6 = 9
9 + 12 = 21
21 + 24 = 45
45 + 48 = 93
? = 93 + 96 = 189
10 17 48 165 688 3475 ?
10*1 + 1*7 = 17
17*2 + 2*7 = 48
48*3 + 3*7 = 165
165*4 + 4*7 = 688
688*5 + 5*7 = 3475
? = 3475*6 + 6*7 = 20892
5 15 120 1800 43200 1512000 ?
5*(0+3) = 15
15 *(0+ 3 + 5) = 120
120*(0+ 3 + 5 + 7) = 1800
1800*(0+ 3 + 5 + 7 + 9) =43200
43200*(0+ 3 + 5 + 7 + 9 + 11) = 1512000
? = 1512000*(0+ 3 + 5 + 7 + 9 + 11 + 13) = 72576000
3, 2, 14, 35, 107, ?
3 + 1³ – 2 = 2
2 + 2³ + 4 = 14
14 + 3³ – 6 = 35
35 + 4³ + 8 = 107
107 + 5³ - 10 = 222
In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x² = 64
II. y² – 30y + 225 = 0
x² = 64
=> x = 8, – 8
y² – 30y + 225 = 0
=> y = 15
So, X < Y
I. 3x² + 5x – 2 = 0
II. 5y² – 18y + 9 = 0
3x² + 5x – 2 = 0
=> x = 0.33, -2
5y² – 18y + 9 = 0
=> y = 3, 0.6
I. x² – 20x – 525 = 0
II. y² + 40y + 391 = 0
x² – 20x – 525 = 0
=> x = 35, -15
y² + 40y + 391 = 0
=> y = -23, -17
So, X > Y
I. (x – 2)(x – 3) = (x – 4)(x – 5)
II. (y – 6)(y – 5) = (y – 4)(y – 3)
(x – 2)(x – 3) = (x – 4)(x – 5)
=> 4x = 14
=> x = 3.5
(y – 6)(y – 5) = (y – 4)(y – 3)
=> 4y = 18;
=> y = 4.5
I. 2x² + x – 300 = 0
II. y² – 45y + 324 = 0
2x² + x – 300 = 0
=> x = 12, -12.5
y² – 45y + 324 = 0
=> y = 36, 9
So, relation cannot be established
Pankaj and Chahat enter into a partnership investing Rs. 24000 and Rs. 32000 respectively. After 8 months, Rajan also joins the business with capital of Rs. 30000. The share of Rajan in a profit of Rs. 91200 after 2 years will be:
Ratio of profit Pankaj, Chahat and Rajan
= 24000 × 24 : 32000 × 24 : 30000 × 16 = 6 : 8 : 5
Hence, Share of Rajan in profit = 5/19 × 91200 = Rs. 24000
In a co-education school there are 20 more girls than boys. If the number of girls is increased by 20% and the number of boys is also increased by 32%, there would be 18 more girls than boys. What is the number of students in the school?
Let number of boys = b
Then, number of girls = b + 20
New number of girls = (b + 20) x 1.2
Then, number of boys = b x 1.32
From the question,
(b + 20) x 1.2 = 18 + b x 1.32
=> 1.2b + 24 = 18 + 1.32b
=> 0.12b = 6
=> b = 6/0.12 = 50
So, number of girls = b + 20 = 70
Hence, the number of students in the school = 70 + 50 = 120
Mr. Gyan Chand spends 23% of an amount of money on an insurance policy, 33% on food, 19% on children’s education and 16% on recreation. He deposits the remaining amount of Rs. 504 in bank. How much total amount does he spend on food and insurance policy together?
Let the total amount of money be ‘x’
x – (23+33+19+16) * x/100 = 504
=> x * 9/100 = 504
=> x = 50400/9
=> x = 5600
Amount spend on food & Insurance = (23+33) * 5600/100 = 3136
A rectangular courtyard 3.78 m long and 5.25 m broad is to be paved exactly with square tiles, all of the same size. What will be the minimum number of such tiles?
Length of the rectangle = 3.78 m = 378 cm ≡378 = 2 * 3 * 3 * 3 * 7
Breadth of the rectangle = 5.25 m = 525 cm ≡ 525 = 3 * 5 * 5 * 7
Highest Common Factor(HCF) of (378 and 525)= 3 * 7 = 21
Size of largest square tile = 0.21 m x 0.21 m
Minimum Number of tiles = (3.78 * 5.25)/(0.21 * 0.21) = 450
A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1 hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 6 hours when the inlet pipe is plugged. If there is a leakage also which is capable of draining out the water from the tank at half of the rate of the outlet pipe, then what is the time taken to fill the empty tank when both the pipes are opened?
Inlet pipe Efficiency = 100/(8/6) = 75%
Outlet pipe Efficiency = 100/(6) = 16.66%
Efficiency of leakage = half of the rate of the outlet pipe = 8.33%
Net Efficiency = 75 – (16.66 + 8.33) = 50%
Required time = 100/50 = 2 hours
Study the following graph and answer the questions below. Table shows the population and percentage increase/decrease of three cities in year 2001 and 2002.
What was the population (in Lakhs) of Shimla in 2001?
Population of Shimla in 2001 = 1.5 * 100/110 = 1.36 Lakhs
The population of Nainital in 2002 was same as that of of Shimla in 2001, then find average of total population of three cities over 2001 and 2002?
The population of Nainital in 2002 = Population of Shimla in 2001 = 1.36 lakh
So, Population of Nainital in 2001 = 1.36 * 100/92 = 1.48 Lakhs
Average = (1.36 + 1.50 + 3 + 4 + 1.48 + 1.36)/6 = 12.7/6=2.12 Lakhs
What is the percentage increase in the population of Ooty from 2001 to 2002?
The percentage increase in the population of Ooty from 2001 to 2002 = (4 x 100/3) – 100 = 33 1/3%
If in Shimla, population increases by 10% every year, then what was the population (approximately) of Shimla in 2005?
Population of Shimla in 2002 = 1.5 Lakhs
Population of Shimla in 2005 = 1.5* (110/100) * (110/100) * (110/100) = 1.9965 ≈ 2 Lakhs
The population of Shimla in 2001 is what percent less than population of Ooty in 2002?
The population of Shimla in 2001 = 1.5 * 100/110 = 1.36 Lakhs
The population of Ooty in 2002 = 4 lakhs
Required % = (4 – 1.36)/4 * 100 = 66%
Study the following radar graph carefully to answer the questions that follow : Number of seats won by various political parties in the legislative assemblies of different states
The total number of seats won by the C is what per cent more or less than that by the D in all states together?
The total number of seats won by the C = 5 + 10 + 30 + 20 + 10 + 20 + 10 + 15 = 120
The total number of seats won by the D = 15 + 30 + 25 + 15 + 20 + 5 + 15 + 5 = 130
So, required % = (130 - 120)/130 x 100 = 7.69% less
What is the ratio of the total number of seats won by the A to the total number of seats won by the B in all states together?
The total number of seats won by the A in all states together = 30 + 5 + 15 + 10 + 25 + 25 + 30 + 20 = 160
The total number of seats won by the B in all states together = 20 + 15 + 5 + 25 + 30 + 10 + 25 + 10 = 140
So, required ratio = 160 : 140 = 8 : 7
If 30% seats of the Maharashtra legislative assembly are won the females and 40% seats of the Gujarat legislative assembly are won by the females, then the male members of the Maharashtra legislative assembly are what per cent more or less than the male members of the Gujarat legislative assembly?
The male members of the Maharashtra legislative assembly = (30 + 20 + 5 + 15) x 70/100 = 49
The male members of the Gujarat legislative assembly = (25 + 10 + 20 + 5) x 60/100 = 36
So, required % = (49 - 36)/36 x 100 = 36.11% more
40% members of the Haryana legislative assembly and 50% members of the UP legislative assembly are charge sheeted for involvement in crimes. Among these, 50% and 20% are females in the Haryana and UP legislative assembly respectively. Then the number of male members of the Haryana legislative assembly who are charge sheeted is what percentage more or less than the number of female members of the UP legislative assembly who are charge sheeted?
The number of male members of the Haryana legislative assembly who are charge sheeted
= (20 + 10 + 15 + 5) x 40/100 x 50/100 = 10
The number of female members of the UP legislative assembly who are charge sheeted
= (10 + 25 + 20 + 15) x 50/100 x 20/100 = 7
So, required % = (10 - 7)/7 x 100 = 42.86% more
Which political party won the highest number of seats in the given eight states?
The total number of seats won by the C in all states together = 5 + 10 + 30 + 20 + 10 + 20 + 10 + 15 = 120
The total number of seats won by the D in all states together = 15 + 30 + 25 + 15 + 20 + 5 + 15 + 5 = 130
In how many ways, the letters of word ASSASSINATION can be arranged so that the words always start with A and end with N.
Anwar, Barnwaal and Singh start at the same time in the same direction to run around a circular stadium. Anwar completes a round in 126 seconds, Barnwaal in 154 seconds and Singh in 99 seconds, all starting at the same point. After what time will they again at the starting point?
LCM of 126, 154 and 99 = 1386
So, Anwar, Barnwaal and Singh will again meet at the starting point in
= 1386 sec = 1386/60 min = 23 min 6 sec
Chetak borrowed a sum of Rs. 2300 from Akash at the simple rate of 6% per annum for 3 yr. Then, he added some more money to the borrowed sum and lent it to Dhayanchand for the same time at 18% per annum at simple interest. If Chetak gains Rs. 274.95 by way of interest on borrowed sum as well as his own amount from the whole transaction, then what is the approximate sum lent by him to Dhayanchand?
Let Rs. P be the sum lent by Chetak to Dhayanchand.
According to the question,
(P x 3 x 18)/100 – (2300 x 3 x 6)/100 = 274.95
=> 54P – 41400 = 27495
=> 54P = 27495 + 41400 = 68895
=> P = 68895/54 = Rs. 1275(approx)
When A and B are working alone, they can complete a piece of work in 8 days and 12 days respectively. On day 1, B started the work and A Joined B from day 3 on-wards. Find approximately after how many days will the work be completed?
Fraction of work completed by B on day 1 and day 2 = 2* 1/12 = 1/6
Fraction of work left after 2 days = 1 – 1/6 = 5/6
Fraction of work completed by Both = 1/8 + 1/12 = 5/24
Number of days after day 2 to complete work = 5/6 x 24/5 = 4 days
So after 2+4 = 6 days works will be completed
The average height of 18 girls is 117 13/18 cm. The average height of 21 boys is 104 13/21 cm. What is the overall average height of all the students together in the class?
Average height of the class
= [18 * (117 * 18 + 13)/18 + 21 * (104 * 21 + 13)/21]/(18 + 21)
= (2119 + 2197)/ 39 = 4316/ 39 = 332/3 = 110 2/3 cm
What should come in place of the question mark in each of the following number series?
2, 4, 9, 19, ?, 62
2 + 2 = 4
4 + (2 + 3) = 9
9 + (5 + 5) = 19
19 + (10 + 7) = 36
36 + (17 + 9) = 62
5, 6, 14, 45, 184, ?
5 x 1 + 1 = 6
6 x 2 + 2 = 14
14 x 3 + 3 = 45
45 x 4 + 4 = 184
184 x 5 + 5 = 925
42, 45, 53, 66, 84, ?
42 + 3 = 45
45 + (3 + 5) = 53
53 + (8 + 5) = 66
66 + (13 + 5) = 84
84 + (18 + 5) = 107
8, 4, 4, 8, 32, ?
8 x 0.5 = 4
4 x 1 = 4
4 x 2 = 8
8 x 4 = 32
32 x 8 = 256
12, 15, 21, 33, ?, 105
The pattern of the series is:
12 + 3 = 15
15 + 6 = 21
21 + 12 = 33
33 + 24 = 57
57 + 48 = 105
Correct (-)
Wrong (-)
Skipped (-)