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IBPS - Coding - Decoding and Inequalities Test - 1
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IBPS - Coding - Decoding and Inequalities Test - 1

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  • Question 1/10
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    Directions For Questions

    Direction: Study the following information carefully and answer the questions based on it.

    In a certain code language,

    ‘justice beyond layout school’ is written as ‘UK9 EA4 FI9 MR4’. 

    ‘havoc righty colleges nonstop’ is written as ‘ZQ1 QM4 TB9 DG4’. 

    ‘solo you dream geek’ is written as ‘VX4 LF4 PR4 NC4’. 

    ‘than ochrea presenting flow’ is written as ‘OS1 XE1 HO9 BN9’.

    ...view full instructions

    Which of the following is the code for ‘zenith’?

    Solutions

    In this code language, there are some letters given we have to find the exact code used for them. 

    Example- Presenting 

    Step I- first decrement the first alphabet i.e. ‘o’ and the increment the last alphabet i.e. ‘h’. 

    Step II- then exchange the incremented and decremented alphabets i.e. ‘o’ is exchanged with ‘h’. The ‘OH’ is exchanged with ‘HO’ 

    Step III- then count the number of vowels in the whole word, i.e. ‘3’ and square the number i.e. ‘9’. 

    So, ‘presenting’ is coded as ‘HO9’. 

    So, ‘zenith’ is coded like above rule- ‘IY4’

  • Question 2/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions based on it.

    In a certain code language,

    ‘justice beyond layout school’ is written as ‘UK9 EA4 FI9 MR4’. 

    ‘havoc righty colleges nonstop’ is written as ‘ZQ1 QM4 TB9 DG4’. 

    ‘solo you dream geek’ is written as ‘VX4 LF4 PR4 NC4’. 

    ‘than ochrea presenting flow’ is written as ‘OS1 XE1 HO9 BN9’.

    ...view full instructions

    Which of the following is the code for ‘tangible’?

    Solutions

    In this code language, there are some letters given we have to find the exact code used for them. 

    Example- Presenting 

    Step I- first decrement the first alphabet i.e. ‘o’ and the increment the last alphabet i.e. ‘h’. 

    Step II- then exchange the incremented and decremented alphabets i.e. ‘o’ is exchanged with ‘h’. The ‘OH’ is exchanged with ‘HO’. 

    Step III- then count the number of vowels in the whole word, i.e. ‘3’ and square the number i.e. ‘9’. 

    So, ‘presenting’ is coded as ‘HO9’. 

    So, ‘tangible’ is coded like above rule- ‘FS9’.

  • Question 3/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions based on it.

    In a certain code language,

    ‘justice beyond layout school’ is written as ‘UK9 EA4 FI9 MR4’. 

    ‘havoc righty colleges nonstop’ is written as ‘ZQ1 QM4 TB9 DG4’. 

    ‘solo you dream geek’ is written as ‘VX4 LF4 PR4 NC4’. 

    ‘than ochrea presenting flow’ is written as ‘OS1 XE1 HO9 BN9’.

    ...view full instructions

    In the given code language, what does the code ‘NO9’ stand for?

    Solutions

    In this code language, there are some letters given we have to find the exact code used for them. 

    Example- Presenting 

    Step I- first decrement the first alphabet i.e. ‘o’ and the increment the last alphabet i.e. ‘h’. 

    Step II- then exchange the incremented and decremented alphabets i.e. ‘o’ is exchanged with ‘h’. The ‘OH’ is exchanged with ‘HO’. 

    Step III- then count the number of vowels in the whole word, i.e. ‘3’ and square the number i.e. ‘9’. 

    So, ‘presenting’ is coded as ‘HO9’. 

    So, ‘paradigm’ is coded like above rule- ‘NO9’

     

  • Question 4/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions based on it.

    In a certain code language,

    ‘justice beyond layout school’ is written as ‘UK9 EA4 FI9 MR4’. 

    ‘havoc righty colleges nonstop’ is written as ‘ZQ1 QM4 TB9 DG4’. 

    ‘solo you dream geek’ is written as ‘VX4 LF4 PR4 NC4’. 

    ‘than ochrea presenting flow’ is written as ‘OS1 XE1 HO9 BN9’.

    ...view full instructions

    Which of the following is the code for ‘vague quarrel nostalgic’?

    Solutions

    In this code language, there are some letters given we have to find the exact code used for them. 

    Example- Presenting 

    Step I- first decrement the first alphabet i.e. ‘o’ and the increment the last alphabet i.e. ‘h’. 

    Step II- then exchange the incremented and decremented alphabets i.e. ‘o’ is exchanged with ‘h’. The ‘OH’ is exchanged with ‘HO’. 

    Step III- then count the number of vowels in the whole word, i.e. ‘3’ and square the number i.e. ‘9’. 

    So, ‘presenting’ is coded as ‘HO9’. 

    So, ‘vague quarrel nostalgic’ is coded like above rule- ‘MP9 DM9 FU9’

  • Question 5/10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the questions based on it.

    In a certain code language,

    ‘justice beyond layout school’ is written as ‘UK9 EA4 FI9 MR4’. 

    ‘havoc righty colleges nonstop’ is written as ‘ZQ1 QM4 TB9 DG4’. 

    ‘solo you dream geek’ is written as ‘VX4 LF4 PR4 NC4’. 

    ‘than ochrea presenting flow’ is written as ‘OS1 XE1 HO9 BN9’.

    ...view full instructions

    Which of the following is the code for ‘Degust’?

    Solutions

    In this code language, there are some letters given we have to find the exact code used for them. 

    Example- Presenting 

    Step I- first decrement the first alphabet i.e. ‘o’ and the increment the last alphabet i.e. ‘h’. 

    Step II- then exchange the incremented and decremented alphabets i.e. ‘o’ is exchanged with ‘h’. The ‘OH’ is exchanged with ‘HO’. 

    Step III- then count the number of vowels in the whole word, i.e. ‘3’ and square the number i.e. ‘9’. 

    So, ‘presenting’ is coded as ‘HO9’. 

    So, ‘degust’ is coded like above rule- ‘UC4’

     

  • Question 6/10
    1 / -0

    Direction: In each of the following questions, assuming the given statements to be true, find which of the following options holds true:

    Statements: 

    Z<S≥F< H, F=N 

    Conclusions: 

    I. N≤S 

    II. S>H

    Solutions

    Z<S≥F< H, F=N 

    Conclusions: 
    I. N≤S ------------ S≥F = N ------- Hence, S≥N is true. 

    II. S>H ------- S≥F< H -------- There is opposite sign between S & H, so relation cannot be established. 

    Hence, the conclusion I is true.

  • Question 7/10
    1 / -0

    Direction: In each of the following questions, assuming the given statements to be true, find which of the following options holds true:

    Statements: 
    A≥Q, G<Q, O ≤ A, G=J 

    Conclusions: 
    I. A ≥ J 
    II. Q>J

    Solutions

    A≥Q, G<Q, O ≤ A, G=J 

    Conclusions: 

    I. A ≥ J ----------- A≥Q>G=J ------ so, A ≥ J is false. 

    II. Q>J ----------- Q>G=J ------ so, Q>J is true.
    Hence, conclusion II is true

     

  • Question 8/10
    1 / -0

    Direction: In each of the following questions, assuming the given statements to be true, find which of the following options holds true:

    Statements: 
    F ≥ H, A ≤ C, G ≥ H, H > C 

    Conclusions: 
    I. G > H 
    II. G > C

    Solutions

    F≥H, A≤C, G≥H, H>C 

    Conclusions: 

    I. G>H ------ but we know G≥H ---- so, G>H is not definitely true, hence this conclusion is false. 

    II. G>C ------ G≥H>C ------ so, G>C is true.

    Hence, conclusion II is true.

     

  • Question 9/10
    1 / -0

    Direction: In each of the following questions, assuming the given statements to be true, find which of the following options holds true:

    Statements: 

    J ≤ K, S > D < T, E ≥ S, E = G 

    Conclusions: 

    I. D < E 
    II. S < G

    Solutions

    J≤K, S>D<T, E ≥S, E=G 

    Hence, D < S < E = G

    .Conclusions: 

    I. D < E (TRUE)

    II. S < G (FALSE)
    Hence, conclusion I is true.

  • Question 10/10
    1 / -0

    Direction: In each of the following questions, assuming the given statements to be true, find which of the following options holds true:

    Statements: 
    T ≥ M, M < K, C = K, P < M

    Conclusions:  
    I. P < C
    II. P < T

    Solutions

    Given statements: T ≥ M, M < K, C = K, P < M

    Conclusions:  

    I. P < C - True (P < M < K = C).
    II. P < T - True (T ≥ M > P).

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