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Ages Test 3
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Ages Test 3
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  • Question 1/10
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    A father said to his son,“ At the time of your birth, I was as old as you are at present . If the father’s age is 38 years now, the son’s age five years back was:

    Solutions

    Let son's age be x years. Then,

    (38-x)=x ⇔ 2x=38 ⇔ x=19.

    ∴ Son's age 5 years back = (19-5)years=14 years

     

  • Question 2/10
    1 / -0

    The ages of two persons differ by 16 years. If 6 years ago, the elder one is 3 times as old as the younger one, find their present ages.

    Solutions

     

  • Question 3/10
    1 / -0

    The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be.

    Solutions

    Let the present ages of son and father be x and (60 -x) years respectively.

    Then, (60 - x) - 6 = 5(x - 6)

    ⇒54 - x = 5x - 30

    ⇒6x = 84

    x = 14.

    Son's age after 6 years = (x+ 6) = 20 years..

     

  • Question 4/10
    1 / -0

    The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child ?

    Solutions

     

  • Question 5/10
    1 / -0

    The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be double of the sum of the ages of his sons. The father’s present age is?

    Solutions

    Let the sum of present ages of the two sons be x years,

    Then, father’s present age = 3x years, (3x + 5) = 2 (x + 10)

    ⇔ 3x + 5 = 2x +20 ⇔ x =

    Hence, father’s present age = 45 years.

     

  • Question 6/10
    1 / -0

    At present, the sum of ages of R and S is 63 years.The ratio of their ages after 7 years will be 7:4 , what is the present age of R ?

    Solutions

     

  • Question 7/10
    1 / -0

    Tanya’s Grandfather was 7 times older to her 8 years ago. He would be 3 times of her age 8 years from now. what was the ratio of Tanya’s age to that of her grandfather?

    Solutions

    Equation for first situation

    7(T-8)=G-8

    Equation for second condition

    3(T+8)=G+8 

    on solving the two equations we get T=16 and G=64 and their ratio = 1:4

     

  • Question 8/10
    1 / -0

    A is as much younger to B as he is elder to C. If the sum of the ages of B and C is 48 years, what is the age of A in years?

    Solutions

    B - A = A - C

    2A = B +  C 

    B +  C = 48 (Given)

    2A = 48

    A = 24.

     

  • Question 9/10
    1 / -0

    The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is?

    Solutions

    Let the ages of father and son 10 years ago be 3x and x years respectively. 

    Then, (3x+10)+10=2 [(x+10)+10] ⇔ 3x+ 20

    = 2x + 40 ⇔ x =20

    Required ratio = (3x+10):(x+10)=70:30

    =7:3

     

  • Question 10/10
    1 / -0

    The average age of a family of five persons is 20 years. If the youngest member is 8 years old then, what was the average age of the family at the birth time of the youngest member. 

    Solutions

     

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