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RRB NTPC Aptitude Test - 60
Result
RRB NTPC Aptitude Test - 60

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  • Question 1/10
    1 / -0

    Find the factors of (x2 – x – 182)

    Solutions

    Upon solving the equation

    x2 - x - 182= 0

    x2-14x+13x-182= 0

    x (x – 14) + 13 (x – 14) = 0

    (x – 14) (x + 13) = 0

     

  • Question 2/10
    1 / -0

    √32 - √50 + √98 = ?

    Solutions

    √32-√50+√98 = √2(4-5+7)

    = 6√2

     

  • Question 3/10
    1 / -0

    The standard deviation of all the six students who got the same marks will be (consider their marks as y)

    Solutions

    Since standard deviation = √variance2

    Variance 2= (reading – mean) 2/number of readings

    Here variance =0

    Hence standard deviation =0

     

  • Question 4/10
    1 / -0

    Rishab bought a dozen of pens for Rs 156 and sold a pack of 4 pens for Rs 64 each. What is his gain?

    Solutions

    A dozen of pens cost Rs 156.

    1 pen will cost = 156/12= 13

    4 Pen will cost = 4x 13= 52

    His gain = 64 – 52 = 12

    Gain % = 12/52x100 = 23.08%

     

  • Question 5/10
    1 / -0

    What is the ratio of simple interest earned on certain amount at the rate of 13.5% p.a for 12 years and that for 22 years and 6 months?

    Solutions

    SI = 13.5 x 12xP/100

    SI2= 13.5x45xP/200

    SI/SI2 = 24/45= 8:15

     

  • Question 6/10
    1 / -0

    Find the area of the trapezium? (All measurements are in cm)

    Solutions

    Sum of the parallel sides = 20 + 15+15+20= 70

    In ∆ CED

    Distance between the two parallel sides = 20

    Hence area of the trapezium = ½ x (sum of the parallel sides) x distance between them

    = ½ x(70)x20

    = 700

     

  • Question 7/10
    1 / -0

    In RRB NTPC examination, there were a total of 100 questions, the marks obtained by me was 72. Find the total number of questions I did wrong in the exam, if for every wrong answer 1/3 marks is deducted?

     (Consider I have attempted all the questions)

    Solutions

    Let the number of questions correctly attempted by me = x

    And the questions I did wrong = y

    Then total number of questions = x + y…………1)

    Marks obtained by me is 72, hence

    X – y/3= 72

    =3x – y = 216………..2)

    Solving the equations we will get x=79

    Hence y = 100- 79 = 21

     

  • Question 8/10
    1 / -0

    Arvind purchased a chair for Rs 8000, and sold it for Rs 10,500. Find his gain in percentage?

    Solutions

    Gain = 10,500-8000= 2500

    Gain% = 2500/8000x100=31.25%

     

  • Question 9/10
    1 / -0

    The value of (cotx + cosecx)2=

    Solutions

    (cotx + cosecx)2= cot2x + cosec2x + 2 cotx . cosecx

    Adding and subtracting 1

    =1+ cot2x + cosec2x + 2 cotx. cosecx -1

    =2 cosec2x +2cosx. cosec2x -1

    =2 cosec2x(1+ cosx)-1

     

  • Question 10/10
    1 / -0

    How many numbers are there from 100 to 200 that have both their tens digits and units digits same?

    Solutions

    Since from 100 to 200 is mentioned we have to include both the end points,

    Hence there are 11 numbers from 100 to 200 that have the same unit and tens digits same.

     

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