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SSC CGL Maths Test 125
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SSC CGL Maths Test 125

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  • Question 1/10
    1 / -0
    When 0.151515.....is converted into a fraction, then the result is
    Solutions
    Given expression is: y = 0.151515... ----------(i)
    Multiplying with 100 on both sides, we get
    100y = 15.1515…. ----------(ii)
    Subtracting these two equations, we get
    99y = 15
    ⇒ y = 15/99 = 5/33
  • Question 2/10
    1 / -0
    Three persons whose speed is in the ratio 4:3:5 are walking. find the ratio of the time in which they reach their destination.
    Solutions
    ratio of speed=4:3:5
    ratio of time=1/4:1/3:1/5=15:20:12
  • Question 3/10
    1 / -0
    The cost price of 50 cups is equal to the selling price of 40 cups. The percentage of profit in the transaction is:
    Solutions
    Short Trick:

    50CP = 40SP

    ⇒ CP/SP = 4/5

    Profit % = (1/4) × 100 = 25%

    Alternate Method:
    C.P. of 50 cups = S.P. of 40 Cups = m 

    Hence, C.P. of 1 cup = m/50

    And S.P. of 1 cup = m/40

    So, profit of 1 cup = m/40 – m/50 = 10m/2000 = m/200

    Hence, Profit % = (Profit/C.P. of 1 cup) × 100 

    Profit % = [(m/200)/(m/50)] × 100

    = (50 × 100 × m)/(200 × m) 

    = 25%.
  • Question 4/10
    1 / -0
    A's salary is 50% more than that of B's. Then B's salary is less than that of A by:
    Solutions
    Let the salary of B = Rs. 100,

    then the salary of A = Rs. 150

    ∴     B’s salary is less than that of A by .
  • Question 5/10
    1 / -0
    Δ XYZ is right angled at Y. If ∠Z = 30 °. What is the length of YZ (in cm), if ZX = 9 cm?
    Solutions

  • Question 6/10
    1 / -0
    The average marks obtained by a student in 6 subjects is 88. On subsequent verification it was found that the marks obtained by him in a subject was wrongly copied as 86 instead of 68. The correct average of the marks obtained by him is:
    Solutions
    Required average:
  • Question 7/10
    1 / -0
    A bag contains Rs 240 in coins of denominations of 50 paise, 25 paise and 10 paise are in the ratio of 5:6:8. Find the number of 25 paise coin is.
    Solutions
    Let the number of coin of 50 paise, 25 paise and 10 paise are 5x , 6x and 8x respectively.
    A.T.Q

    = 240
    96 X = 240 × 20
    ∴X = 50
    Required ans is = 6×50 = 300
  • Question 8/10
    1 / -0
    ABCD is a square. draw an equilateral triangle PBC on side BC considering BC is a base and an equilateral triangle QAC on diagonal AC considering AC is a base. Find the value of
    Solutions

    Side of square = x units
    Diagonal of square
    =units

    =
  • Question 9/10
    1 / -0
    In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, then the dividend is
    Solutions
    Divisor = 5 × Remainder
    Quotient
    ∴ Dividend = Divisor × Quotient + Remainder
  • Question 10/10
    1 / -0
    H.C.F. and L.C.M. of two numbers are 14 and 462, If one number is 42 then what is other number?
    Solutions
    Let second number be x:
    1st number x 2nd number = L.C.M x H.C.F
    2nd number =
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