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SSC CGL Maths Special Test 140
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SSC CGL Maths Special Test 140

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  • Question 1/10
    1 / -0.25
    What is the value of ?
    Solutions
    .

    .

    .

  • Question 2/10
    1 / -0.25
    A mixture of 40 litres of milk and water contains 10% water. How much water must be added to the mixture so that there is 20% water in the new mixture?
    Solutions
    Amount of water in the original mixture = 4 litre
    Let x amount of water is added. Then

    Check from options now. No need to solve the equation. 5 satisfies the equation and hence is the answer.
  • Question 3/10
    1 / -0.25
    In the given figure PQRS is a maximum size square based on hypotenuse in a right angle Δ ABC. Find the area of shaded portion (appx.) if the length of perpendicular, base and hypotenuse are 15, 8 and 17 respectively .
    Solutions
    We can find the side of maximum size square by given formula-

    Required area


    (appx.).
  • Question 4/10
    1 / -0.25
    The following table shows the number of children in each house of a society.

    What is the average number of children per house?
    Solutions


    From the table, the average number of children per house = 43/32
    = 1.34
  • Question 5/10
    1 / -0.25
    The base of a prism is a trapezium. The lengths of the parallel sides of the trapezium are 15 cm and 18 cm respectively and the distance between the parallel sides is 10 cm. If the volume of the prism is 1485 cm3, then the height of the prism is:
    Solutions


    Volume of Prism = height of Prism × Area of Base
    ⇒1485 = height × 165 
    Height = 9cm
  • Question 6/10
    1 / -0.25
    From two points on the ground and lying on a straight line through the foot of a pillar the two angles of elevation of the top of the pillar are complementary to each other. If the distances of the two points from the foot of the pillar are 9 meters and 16 meters and the two points lie on the same side of the pillar, then the height of the pillar is
    Solutions

    AB =h, BC=9 and BD=16
    Angle ADB = , Angle ACB = 90-
    From Triangle ABC, tan (90 - ) = AB/BC -> cot = h/9
    From Triangle ABD, tan = h/16
    Multiplying both the equations we get h2/144 = 1
    h=12 metre
  • Question 7/10
    1 / -0.25
    is.
    Solutions

  • Question 8/10
    1 / -0.25
    Simplify 437bxaz / 23ab.
    Solutions
    437bxaz / 23ab
    = 19xz
  • Question 9/10
    1 / -0.25
    IF x is increased by 20%, it becomes equal to 60% of y. Find the ratio of x:y.
    Solutions
    120% of x = 60% of y
    ⇒ 2x = y
    ∴ x : y = 1 : 2
  • Question 10/10
    1 / -0.25
    In the afternoon, a student read 100 pages at the rate of 60 pages per hour. In the evening, when she was tired, she read 100 more pages at the rate of 40 pages per hour. What was her average rate of reading, in pages per hour?
    Solutions
    The required average rate of reading= total pages/total time taken 

    pages/hour
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