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Arithmetic Mix Test 147
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Arithmetic Mix Test 147
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  • Question 1/10
    1 / -0.25

    In a class of 60 students, 60% are boys. If 25% of the girls come to school by bicycle. Find the number of girls who don’t come cycling to school?
    Solutions

    Total students = 60

    Number of boys =

    Number of girls = 60 – 36 = 24

    25% of the girls come to school by bicycle.

    There are 75% girls who don’t come cycling to school.

    Hence, Number of girls who don’t come cycling to school =

  • Question 2/10
    1 / -0.25

    The efficiencies of A, B and C are in the ratio 2:5:7 working together, they can complete a work in 10 days. In how many days will A alone be able to complete 30% of that work?
    Solutions

    Let the efficiency of A, B and C are 2x,5x and 7x units per day respectively.

    (A+B+C)’s efficiency together

    =  = 14 units per day

    They can complete a work in 10 days.

    Then, total work =  units

    A complete 30% of that work alone.

    So, work done by A =

    = units

    Time taken by A =

  • Question 3/10
    1 / -0.25

    Shyam invested 2,00,000 in a fixed deposit scheme at the rate of 10% per annum at CI. But he has to pay 20% tax on the CI. Find the sum after three years.
    Solutions

    The rate of interest which is charged

    Hence, the net value after three years



    Detailed Solution:

    Interest of 1 year = 10% of Rs.2,00,000 = Rs.20,000
    Tax on Interest = 20% of Rs.20,000 = Rs.4,000
    So, Amount after tax deduction = 2,00,000 + 20,000 − 4,000
    = Rs.2,16,000

    Again Interest of 1 year = 10% of Rs.2,16,000 = Rs.21,600
    Tax on Interest = 20% of Rs.21,600 = Rs.4,320
    So, Amount after tax deduction = 2,16,000 + 21,600 − 4,320
    = Rs.2,33,280

    Again Interest of 1 year = 10% of Rs.2,33,280 = Rs.23,328
    Tax on Interest = 20% of Rs.23,328 = Rs.4665.60
    So, Amount after tax deduction = 2,33,280 + 23,328 − 4,665.60
    = Rs.2,51,942.40

    Thus, the amount will become Rs.2,51,942.40 after 3 years.

  • Question 4/10
    1 / -0.25

    Three persons A, B and C can complete one round of circular track in 8, 15 and 20 minutes respectively. If they start together at 8 A.M from a certain point, at which time will they be together again at the starting point?
    Solutions

    Three persons A, B and C can complete one round of circular track in 8, 15 and 20 minutes respectively.

    In such questions we will first evaluate LCM of in 8, 15 and 20 minutes.

    LCM of (8,15,20) = 120

    Hence, we can say that they be together again at the starting point after 120 minutes.

    120 minutes = 2 hours

    Hence, if they start together at 8 A.M from a certain point, they will be together again at the starting point at 10 A.M.

  • Question 5/10
    1 / -0.25

    Two train A and B of length 200 meter and 150 meters respectively, running with 96 km/h and 66 km/h respectively in the same direction. If a man is sitting on the coach A3 of train A. The time in which, the man will cross the train B is?
    Solutions

    Length to be crossed meters

    Relative speed  km/h  m/s

    Time  second

  • Question 6/10
    1 / -0.25

    Rs 15000 is divided among P, Q and R. P’s share and Q’s share is in the ratio 2 : 1 and Q’s share and R’s share in the ratio 4 : 3 . How much amount (in Rs) will Q receive?
    Solutions

    Given That,

    Total money =Rs. 15000

    P : Q =2 : 1

    Q :R = 4 : 3

    By making Q equal,

    P : Q = 2×4 : 1×4

    P : Q = 8 : 4

    So,

    P=8x

    Q=4x

    R=3x

    Total money=15000

    P+Q+R=15000

    8x+4x+3x=15000

    15x=15000

    x=1000

    Q got 4×1000= Rs. 4000

    Therefore, option D is the right answer.

  • Question 7/10
    1 / -0.25

    36 men and 48 women can do a certain work in one day whereas 6 men and 12 women can do it in 5 days. The number of women required to do the same work in 8 days is:

    Solutions

    Time taken by 36 men and 48 women  to complete a task = 1 day

    Time taken by 6 Men  and 12 women  to complete the task = 5 days

    ⇒ (36 M + 48 W ) = 5 ( 6M + 12 W )

    ⇒ (36 M + 48 W ) = 30M + 60 W

    ⇒ M/W = 2/1

    Total work = 5 [6(2) +12(1)]

                          = 120

    Total work = number of Person × Number of days

    120 =  Number of Person × 8

    Number of women required to do the same work = 15  

  • Question 8/10
    1 / -0.25

    What is the largest 3 digit number which when divided by 6, 14 and 21 give a remainder of 5 in each case?
    Solutions
    LCM of 6, 14 and 21 = 42
    All the multiples of 42 are completely divisible by 6, 14 and 21.
    Largest three digit number multiple of 42 is 966.
    To get a remainder of 5, adding 5 to this value which gives 971.
  • Question 9/10
    1 / -0.25

    The marked price of an article is Rs 8480.If a discount of 12.5% is given, then what will be the selling price (in Rs) of the article ?
    Solutions
    Marked price =8480
    Discount percentage =12.5% =1/8
    Selling price =× marked price = 7/8 of marked price
    So selling price =
  • Question 10/10
    1 / -0.25

    A train travelling at the speed of x km/h crossed a 300 m long platform in 30 seconds, and overtook a man walking in the same direction at 6 km/h in 20 seconds. What is the value of x ?
    Solutions

    A train travelling at the speed of x km/h crossed a 300 m long platform in 30 seconds.

    Let length of train = L meters

    We know that , Distance = Speed× Time

    .………………………..(1)

    Also, train overtook a man walking in the same direction at 6 km/h in 20 seconds.

    .…………………..(2)

    From (1) and (2)

    x = 96

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