Please wait...

Mixture & Alligation Test 169
Result
Mixture & Alligation Test 169

  • /

    Score

  • -

    Rank
Time Taken: -
  • Question 1/10
    1 / -0.25
    The amount of water (in ml) that should be added to convert 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is?
    Solutions
    Initial ratio, Alcohol: Water = 50%:50% = 1:1
    Alcohol = Water = 4.5 ml
    New ratio, Alcohol: Water = 30%:70% = 3:7
    .
    .
  • Question 2/10
    1 / -0.25
    Rs. 146/kg tea is mixed with Rs. 149/kg tea in the respective ratio 3:4 then what is cost price of one kg mixture?
    Solutions
    Let weight of both types of tea be 3x and 4x kg
    Total price of mixture =
    Required average =
  • Question 3/10
    1 / -0.25
    A milk solution of 100 liters contain 80% milk. How many liters of another milk solution containing 75% milk should be added to make a 78% milk solution?
    Solutions

    ∴So the required liters of another milk solution x = 2 × = 200/3 liters
  • Question 4/10
    1 / -0.25
    A man pays Rs. 6.40 per liter of milk. He adds water and sells the mixture at Rs. 8 per liter, thereby making 37.5% profit. The proportion of water to milk received by the customers is -
    Solutions
    C.P of mixture



    Required ratio     = 0.58 : 5.82 = 1 : 10
  • Question 5/10
    1 / -0.25
    In what proportion must a grocer mix sugar at Rs.12/kg and Rs.7/kg so as to make a mixture worth Rs.8/kg?
    Solutions
    By the rule of Alligation,



    ∴     Required ratio = 1 : 4
  • Question 6/10
    1 / -0.25
    Two types of tea costing 180/kg and 280/kg should be mixed in the ratio so that the mixture obtained sold at 320/kg. to earn a profit of 20% is?
    Solutions
    Let the total cost of the mixture = Rs. x /kg

    ⟹     S.P = x ×

    ⟹     320 = x ×

    ⟹     x = Rs.800/3

    ⟹ 40 : 260 = 2 : 13
    ∴ The required ratio is 2 : 13
  • Question 7/10
    1 / -0.25
    The ratio of petrol and kerosene in the container is 3:2. When 10 liters of the mixture is taken out and is replaced by the kerosene, the ratio become 2:3. Then total quantity of the mixture in the container is:
    Solutions
    Let the total quantity of mixture = x
    petrol : kerosene
          3 : 2(initially)
          2 : 3(after replacement)

    = 

    ⇒ 

    ⇒ 
  • Question 8/10
    1 / -0.25
    A car agency has 108 cars. He sold some cars at 10 % profit and some cars at 19 % profit. If the overall profit on the sale of cars is 16%, then find the number of cars sold at 19% profit.
    Solutions
    Using allegation-

    10%           19%

             16%

    3         :        6
    1         :        2

    so, Cars sold at 10% profit : Cars sold at 19% profit = [19-16] : [16-10] = 3:6 = 1:2

    Let it be - x and 2x

    Total cars = 3x = 108

    Cars at 19% profit = 2x = 108/3 × 2 = 72

  • Question 9/10
    1 / -0.25
    A vessel contains 240 litres of mixture containing milk and water in the ratio of 5: x, respectively. 48 litres of mixture is taken out from this vessel and put into another vessel P. When 12 litres of water is added in vessel P then ratio of milk to water is found to be 2: 1, respectively. Find the value of x.

    Solutions

    Amount of milk in 48 litres of mixture =  litres

    So, amount of water in 48 litres of mixture =  litres

    According to the question,



    SHORT TRICK:

    After adding 12 litre of water in vessel P (which has 48 litres of mixture in it),
    So, the mixture now in vessel P = 60 litre
    Milk : water =  2 : 1. (Given)

    So, Milk = 40 litre and   Water = 20 litre
    12 litres was added, so the initial amount of water was 20 -12 = 8 litres
    And, the initial ratio was 5 : x
    40/8 = 5/x
    So, x =1


  • Question 10/10
    1 / -0.25
    A mixture is composed of 11 parts of pure milk and 2 parts of water. If 35 litres of water was added to the mixture then the new mixture will contain twice as much pure milk as water, then how many litres of pure milk does the original mixture contain?
    Solutions
    Let the pure milk = 11x
    and water = 2x

    As per question 11x = 2(2x+35)
    ⇒ 7x = 70
    ⇒ x = 10
    Pure milk = 11x = 11×10 = 110 L
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Click on Allow to receive notifications
×
Open Now