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Profit & Loss Test 178
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Profit & Loss Test 178

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  • Question 1/10
    1 / -0.25
    A merchant bought 100 eggs, out of which 19 eggs were broken. He sold the remaining eggs at rate of Rs. 4.80 per dozen and thus gained 8%. His total investment is:
    Solutions
    Let C.P. of 100 eggs be Rs. X
    19 eggs are broken
    S.P. of remaining (100-19)
    = 81 eggs
    =
    =
    108% 0f x = 32.4


    X = Rs. 30
  • Question 2/10
    1 / -0.25
    A man sells 320 mangoes at the cost price of 400 mangoes. His gain per cent is
    Solutions
    Required gain per cent =
  • Question 3/10
    1 / -0.25
    A bought a computer system for ₹ 40,000 and sold it to B at a loss of 4%. If B sold it to C for ₹ 40,320, profit percent for B is
    Solutions
    Cost price of computer for A= ₹ 40000
    A sold it to B at a loss of 4 % i.e. at 96% of its cost price.
    ⇒ C.P. for B = 40000 × 96/ 100 = ₹ 38400
    B sold this computer to C for ₹ 40320
    ⇒ Gain to B= 40320 – 38400 = ₹ 1920
    ⇒ Gain percent= 1920 × 100 / 38400= 5%
  • Question 4/10
    1 / -0.25
    A dealer marks an article 40% above the cost price and sells it to a customer, allowing two successive discounts of 20% and 25% on the marked price. If he suffers a loss of 140 rupees, then the cost price (in rupees) of the article is:
    Solutions

    Let us suppose that the cost price of article be Rs 100.

    Then, Marked price of an article = 100 + (40/100)×100 = Rs 140

    Now discount offered = 20% and 25%

    Net discount = 20+25 - (20×25)/100= 40%

    Discount on marked Price = (40/100)×140 = 56

    Selling Price after discount = 140 – 56 = 84

    Loss = 100 – 84 = Rs 16

    ⇒ 16 units = Rs 140

    So, cost Price = 100 units = (140/16)×100 = Rs. 875

  • Question 5/10
    1 / -0.25
    A girl bought two cell phones for a total cost of Rs. 9000. She sold one cell phone for 4/5 of its cost and other for 5/4 of its cost and made a profit of Rs. 900 on the whole transaction. Find the cost price each cell phone.
    Solutions

    Let the CP of one cell phone = Rs. x

    Then CP of another cell phone = Rs. (9000 − x)

    A.T.Q.:
    ⇒ 
    ⇒ 

    ⇒ 
    ⇒ 
    ⇒ x = Rs. 3000 = Cost of one cell phone
    and 
    Cost of another cell phone = 9000 − x = Rs. 6000

  • Question 6/10
    1 / -0.25
    A herder sold a horse and a cow at the same rate. He gained 20 % on selling the horse while lost 20 % on selling cow. What is the overall loss or gain?
    Solutions
    Let the selling price of the both horse and cow be x
    then the cost price of the horse will be
    120CPhorse /100 = x
    CPhorse = 5x/6
    Similarly, for cow
    80CPcow /100 = x
    CPcow = 5x/4
    Total Cost of horse and cow = 5x/6 + 5x/4 = 25x/12
    Total loss = Total CP - Total SP = 25x/12 - 2x = x/12
    Loss % = (x/12)*100/(25x/12) = 4%
    Short trick:
    When the SP is same for two different articles and the profit percent and loss percent are same, then 
    Loss %
  • Question 7/10
    1 / -0.25
    Loss of 20% on selling price is equal to x% loss in cost price. What is x?
    Solutions
    Loss of 20% on SP = (1/5)
    Here let SP = Rs. 5 and loss = Rs. 1, then CP = SP + loss
    = 5 + 1
    = Rs. 6

  • Question 8/10
    1 / -0.25
    A shopkeeper uses 20% less weight while selling, but sold at 10% less than the cost price. How much profit he makes?
    Solutions

    Let CP of 1 kg (1000 gm) = Rs. 100


    CP of 20% less weight = CP of 800 gm=


    SP of 800 gm = 10% less than CP = Rs.90


    P% = [(90−80)/80]×100 = 12.5%

  • Question 9/10
    1 / -0.25
    A loss of 15% gets converted into a profit of 13% when the selling price is increased by Rs. 168. The cost price of the article is
    Solutions
    Given, 28% of cost price = Rs 168
    Hence, the cost price = (168/28) × 100 = Rs 600
  • Question 10/10
    1 / -0.25
    If the cost price of 15 books is equal to the selling price of 20 books, the loss percent is
    Solutions
    if the cost price of each book be ₹ 1 then,
    SP of 20 books = ₹ 15
    CP of 20 books= ₹ 20
    Loss % = (20-15) ×100/20
    =25%
    Hence option 4 is correct.
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