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Time & Work Test 212
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Time & Work Test 212

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  • Question 1/10
    1 / -0.33
    A can complete a piece of work in 10 days and B can complete the same work in 15 days. They complete the whole work in 4 days with the help of C, then what is the share of C in wages of Rs 1500?
    Solutions

    Let the total Work = LCM of (10, 15, 4) = 60 units

    Since A can complete the work in 10 days.
    Efficiency of A = 60/10 = 6 units/day
     
    Similarly,
    Efficiency of B = 60/15 = 4 units/day

    Efficiency of A+B+C = 60/4 = 15 units/day

    so,
    Efficiency of C = 15 − (6+4) = 5 units/day

    Now,
    The wages will be divided in the ratio of Efficiency.

    Share of C = (Efficiency of C/Efficiency of A+B+C)×Total wages
    Share of C = (5/15)×1500 = 500

    Hence, D is the correct answer.

  • Question 2/10
    1 / -0.33
    Antony and Vikash together can complete a piece of work in 20 days and Vikash alone can complete it in 25 days. In how many days, can Antony alone complete the same work?
    Solutions

    Let the total work be LCM of 20 and 25 = 100 units

    Vikas’s one day’s work = 100/25 = 4 units

    Antony’s and Vikas’s one day’s work = 100/20= 5 units

    Antony’s one day’s work = 5 – 4 = 1 unit

    So, Antony’s alone can complete the 100 units work = 100 days.

  • Question 3/10
    1 / -0.33
    A, B and C can do a job in 6 days, 12 days and 15 days respectively. C works till of the work is completed and then leaves. Rest of the work is done by A and B together. Time taken to finish the remaining work by A & B together is how much?
    Solutions
    Remaining work

    Time taken in doing part of work
  • Question 4/10
    1 / -0.33
    A and B can do a job in 10 days and 5 days, respectively. They worked together for two days, after which B was replaced by C and the work was finished in the next three days. How long will C alone take to finish 60% of the job?
    Solutions

    Let the total work be 10x.

    Then efficiency of A =  = x

    And that of B =  = 2x

    Now, work done by A & B together in 2 days = 2 × (x + 2x) = 6x

    Remaining work = 10x – 6x = 4x (finished in 3 days by A & C)

    Work done by A in 3 days = 3x

    Therefore, work done by C in 3 days = 4x – 3x = x

    Now, time taken by C to finish 60% of work =  = 18 days

  • Question 5/10
    1 / -0.33
    To do a certain work, the ratio of efficiencies of A and B is 10 : 7. Working together, they can complete the task in 8 days. A alone will complete 87.5% of the same work in:
    Solutions

    Let the efficiency of A be 10x.

    Then, efficiency of B =  = 7x

    Efficiency of A and B together = 10x + 7x = 17x

    Therefore, total work = (17x) × 8 = 136x

    Time taken by A to complete 87.5% of the same work

    =  =  = 11.9 days

  • Question 6/10
    1 / -0.33
    Three persons undertake to complete a piece of work for ₹ 1, 200. The first person can complete the work in 8 days, the second person in 12 days, and the third person in 16 days. They complete the work with the help of a fourth person in 3 days. What does the fourth person get?
    Solutions
  • Question 7/10
    1 / -0.33
    To do a certain work, the ratio of the efficiencies of A and B is 7:5. Working together, they can complete the same work in  days. A alone will complete 60% of the same work in:
    Solutions

    Let the efficiencies of A and B be 7x and 5x respectively.

    then, total work = (7x + 5x) ×  = (12x) ×  = 210x unit

    Here, 60% of total work = (210x) × 60% = 126x unit

    Time taken by A to complete 60% work =  = 18 days

  • Question 8/10
    1 / -0.33
    X and Y together can do a work in  days, Y and Z together can do the same work in 3 days, and X and Z together can do the same work in 4 days. The time taken by X, Y and Z together to do the same work is:
    Solutions

    Let the total work is x.

    Work done by x and Y together in 1 day =  =

    Work done by Y and Z together in 1 day =

    Work done by X and Z together in 1 day =

    Total work done by x, Y and z in 1 day =  =  =

    Therefore, required time taken by X, Y and Z =  = 2 days.

  • Question 9/10
    1 / -0.33
    Individually A, B and C can complete a piece of work in 20 days, 24 days and 16 days respectively. B and C started the work and worked for 4 days and left. Remaining work was finished by A alone. Find the number of days A worked.
    Solutions

    Let the total work be 240x.

    Then efficiency of A =  = 12x

    Efficiency of B =  = 10x

    Efficiency of C =  = 15x

    Cumulative efficiency of B and C = 10x + 15x = 25x

    Work done by B and C in 4 days = (25x) × 4 = 100x

    Remaining work = 240x – 100x = 140x

    Time taken by A to complete the work (i.e. no. of days A worked)

    =  =  days

  • Question 10/10
    1 / -0.33
    Persons A, B and C can complete a task together in 81 days. A and B can complete the same task together in 97.2 days. B and C cancomplete the same task together in 162 days. In how many days can B alone complete the task?
    Solutions

    B’s efficiency=6-(3+1)=6-4=2

    ∴ Time taken by B will be

    = = 243

    Hence, option A is the correct answer.

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