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Aptitude Test 229
Result
Aptitude Test 229

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  • Question 1/10
    1 / -0.33

    Solutions

     

  • Question 2/10
    1 / -0.33

    Rs 5625 are divided among A, B and C such that A may receive one – half as much as B and C together receive and B receive one-fourth of what A and C together receive .The share of A is more than that by B.

    Solutions

    AT.Q A+B+C=5625…….(i)

    B=1/4(A+C)⇒A+C=4B

    putiting eqn (i)

    ⇒B+4B=5625

    ∴B=1125

    &A=1/2(B+C)

    ⇒B+C=2A

    putiting eqn (i)

    ⇒A+2A=5625

    A=1875

    A-B = 1875 - 1125 = 750

     

     

  • Question 3/10
    1 / -0.33

    If each side of a square is increased by 20% . What is the increase % in its area?

    Solutions

     

  • Question 4/10
    1 / -0.33

    Rohit buys two packets of balls. One contains 40 orange colour balls and other contains 60 yellow colour balls. After reaching his home, he finds that 10% of orange colour balls and 20% of yellow colour balls are defective. Find the percentage of balls that are not defective.

    Solutions

    Total number of balls bought by Rohit = 60 + 40 = 100

    Number of defective orange colour balls =10% of 40 = 0.1 X 40 = 4

    Number of defective yellow colour balls = 20% of 60 = 0.2 X 60 =12

    Total number of defective balls = 12 + 4 = 16

    Total numbers of balls that are not defective  = 100 - 16 =84

    Therefore, the percentage of fruits those are not defective   = 84/100 × 100 = 84%

     

  • Question 5/10
    1 / -0.33

    If three coins are tossed simultaneously, what is the probability of getting at least two heads?

    Solutions

    Atleast 2 head = Exactly 2 heads + all 3 heads

    All three heads is (1/2)*(1/2)*(1/2)=1/8

    Exactly 2 heads = probability of 2 heads and 1 tail* the order they can show up

    =(1/2)*(1/2)*(1/2)*3C2=3/8

    Hence, Total probability=(1/8)+(3/8)=1/2

     

  • Question 6/10
    1 / -0.33

    Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.

    Solutions

    Let the past age of son = x

    Let the past age of father = 7x

    So,

    Present ages are x+5 and 7x+5

    Future age of son = x+10

    Future age of father = 7x+10

    Given

    7x+10 = 3*(x+10)

    7x+10 = 3x+30

    7x-3x = 30-10

    4x = 20

    x = 20/4

    x = 5

    7x = 35

    Son's present age=x+5 = 10

    Father's present age=7x+5 = 40

     

  • Question 7/10
    1 / -0.33

    Manu sold a dozen watches for Rs.1454.64 per watch and made a profit of 16%. Find the cost price of a watch?

    Solutions

     

  • Question 8/10
    1 / -0.33

    If by selling 20 cycles Vinay incurs a loss equal to the selling price of 2 cycles, find his loss percentage.

    Solutions

    Let SP of one cycle=Rs.1

    Then SP of 20cycle=Rs.20

    Loss=Rs.2

    We know that

    Loss =CP-SP

    2=CP-20

    CP=Rs.22

     

  • Question 9/10
    1 / -0.33

    What will Rs. 40,000 amount to in 2 years at the rate of 20% p.a., if interest is compounded yearly?

    Solutions

     

  • Question 10/10
    1 / -0.33

    How long will a sum of money take to double, if it is invested at 9.09% p.a. simple interest?

    Solutions

    Let Principal =P

    Considered principal = 100

    So for every year ordinary interest = 9.09

    That's why, after the first year, the amount of money = Rs. 109.09

    Money after the second year = 109.09 + 9.09 = 118.08 Rs ........... and so on

    After 11 years the money will be = 100 + 11 x 9.09 = 100 + 99.99 = 200

     

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