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SSC MTS 2023 Aptitude Test - 2
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SSC MTS 2023 Aptitude Test - 2
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  • Question 1/10
    3 / -0

    If the cost price of 70 articles is equal to the selling price of 40 articles, what will be the profit percentage?

    Solutions

    According to the question:

    70 CP = 40 SP

    ⇒ CP / SP = 4 / 7

    = 75 %

  • Question 2/10
    3 / -0

    Suman borrowed a sum of Rs. 45000 on simple interest. Madhu also borrowed the same amount on compound interest. At the end of two years, both of them repaid their borrowed amounts. However, Madhu had to pay Rs. 648 more than Suman. Find the rate of interest:

    Solutions

    Let the rate of interest be x%

    = 45000 + 900x

    Now, as per question:

    Amount paid by Madhu – Amount paid by Suman = 648

    => 45000 + 900x + 4.5x2 – 45000 – 900x = 648

    => 4.5x2 = 648

    => x = 12

    Hence, they borrowed the funds at 12% interest rate.

  • Question 3/10
    3 / -0

    The length, breadth and height of a solid cuboid is 20 cm, 16 cm and 12 cm respectively. If cuboid is melted to form identical cubes of side 4 cm, then what will be the number of identical cubes?

    Solutions

    Let there are n number of identical cubes.

    According to the question,

    Volume of solid cuboid = n × volume of cubes

    (length × breadth × height) = n × (side)3

    ∴ (20×16×12) = n×(4×4×4)

    n = 3840/64 = 60

  • Question 4/10
    3 / -0

    The ratio of Asha’s age 4 years ago and Aisha’s age after 4 years is 1: 1. Presently, the ratio of their ages is 5: 3. Find the ratio between Asha’s age 4 years hence and Aisha’s age 4 years ago.

    Solutions

    Currently, the ratio of their ages is 5:3. Suppose, their ages are: 5x and 3x respectively

    Asha’s age 4 years ago = 5x - 4

    Aisha’s age after 4 years = 3x + 4

    Ratio of Asha’s age 4 years ago and Aisha’s age after 4 years is 1:1

    Therefore,

    Solving, we get x = 4

    We are required to find the ratio between Asha’s age 4 years hence and Aisha’s age 4 years ago.

    Asha’s age: 5x + 4

    Aisha’s age: 3x - 4

    Putting the value of x, we get:

    So, ratio will be 3:1

  • Question 5/10
    3 / -0

    X is 40% more efficient than Y, and Y alone can do a work in 45 days. Working together, X and Y will complete 80% of the same work in:

    Solutions

    Let the efficiency of Y = P

    Total work = P × 45 = 45P

  • Question 6/10
    3 / -0

    Rahul invested equal sums of money at compound interest under two schemes A and B. Under scheme A, the interest rate was 5% per annum and under scheme B, the interest rate was 17.5% p.a. The compound interest after two years on the sum invested in scheme A was ₹2460. How much is the interest earned under scheme B after two years, if the interest is compounded annually in both schemes?

    Solutions

    Effective interest rate under scheme A

    = 2 × 5% + 5% × 5% = 10% + .25% = 10.25%

    = 33135 – 24000 = ₹9135

  • Question 7/10
    3 / -0

    The average score of 84 students (boys and girls) in a test is 57. The ratio of the number of boys to that of girls is 10 : 11. The average score of boys is 20% less than that of girls. What is the average score of girls in the test?

    Solutions

    Given:

    Average score of 84 students (boys and girls) = 57

    Ratio of number of boys to that of girls = 10 : 11

    Sum of ratios = 10 + 11 = 21

    Number of girls = 84 – 40 = 44

    Let the average score of girls in the test be x.

    Then, average score of boys = (x) – (x) × 20% = x – 0.2x = 0.8x

    Now, total score of boys and girls = 84 × 57

    ⇒ 44x + 40 × (0.8x) = 4788

    ⇒ 44x + 32x = 4788

    ⇒ 76x = 4788

    ⇒ x = 4788/76 = 63

    Therefore, average score of girls in the test is 63.

  • Question 8/10
    3 / -0

    Solutions

    Given:

    = 1.3

    Hence, option D is correct.

  • Question 9/10
    3 / -0

    Profit of Rs 44,200 has to be divided between three partners P, Q and R in the ratio 4:5:8. How much (in Rs) does Q get?

    Solutions

    Given,

    P : Q : R = 4 : 5 : 8

    Sum of Ratios = 4 + 5 + 8 = 12

    Share of Q = 4

    Total Amount = 44200

  • Question 10/10
    3 / -0

    The average of present ages of A and C is 25 years and the average of present ages of B and D is also 25 years. If A is 10 years younger to C and D is 14 years younger to B, then what is the difference between the present ages of A and B?

    Solutions

    Let C’s present age be ‘x’ years, then A’s present age would be ‘x – 10’ years

    Let B’s present age be ‘y’ years, then D’s present age would be ‘y – 14’ years

    Given, the average of present ages of A and C is 25 years.

    So, (x − 10) + x = 25×2 = 50

    ⇒ x = 30 years

    And the average of present ages of B and D is also 25 years.

    So, (y − 14) + y = 25×2 = 50

    ⇒ y = 32 years

    Required difference = 32 – (30 – 10) = 32 – 20 = 12 years

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