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Bank Foundation Test 586
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Bank Foundation Test 586

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  • Question 1/6
    1 / -0.25

    Directions For Questions

    Direction: Read the sentence to find out whether there is any error in it. The error, if any, will be in one part of the sentence. The number corresponding to that part will be your answer. If the given sentence is correct as it is, mark the answer as ‘No error’. Ignore the errors of punctuation if any.

    ...view full instructions

    Police officers have refused on identify the bystander (1)/ who is the only eyewitness to the crime (2)/ but have said that the investigating team would explore (3)/ if he could be a witness in the case. (4)
    Solutions
    There is incorrect usage of the preposition 'on' in the first part of the statement; the correct usage would be 'to'. 'On' is generally followed by a noun (object) or pronoun, while 'to' should be used before a verb.
  • Question 2/6
    1 / -0.25

    Directions For Questions

    Direction: Read the sentence to find out whether there is an error in it. The error, if any, will be in one part of the sentence. The number of that part is your answer. If the given sentence is correct as it is, mark the answer as 'No error'. Ignore the errors of punctuation if any.

    ...view full instructions

    About twice every century, (1)/ one of the massive stars in our galaxy blows itself apart (2)/ to a supernova explosion that sends (3)/ massive quantities of radiation and matter into space. (4)
    Solutions
    'To' is incorrectly used in the third part and needs to be replaced with 'in'.
    'To' is used to describe or point in the direction of an event or an action, while 'in' can be used to point n the direction of a 'consequence'.
  • Question 3/6
    1 / -0.25

    Directions For Questions

    Direction: Read the following information carefully and answer the questions that follow:

    Seven friends – Chandani, Diksha, Hemant, Kashish, Mahesh, Nitin and Rohan are comparing their scores of an exam. Following is the information about their scores.

    (i) Each of them scored a distinct mark.
    (ii) Kashish scored the same marks as the average of the marks scored by Chandani and Diksha where Chandani scored more than Diksha.
    (iii) Both Mahesh and Nitin scored less than Hemant but more than Rohan and the marks scored by Rohan is not the least.
    (iv)The number of persons who scored more than Kashish is the same as the number of persons who scored less than Kashish.
    (v) Chandani scored less than Mahesh.

    ...view full instructions

    How many persons are there whose scores are between the scores of Nitin and Diksha?
    Solutions
    Persons: Chandani, Diksha, Hemant, Kashish, Mahesh, Nitin and Rohan
    1) The number of persons who scored more marks than Kashish is same as the number of persons who scored less marks than Kashish.
    So, Kashish scored fourth highest marks.

    2) Kashish scored the same marks as the average of the marks scored by Chandani and Diksha where Chandani scored more marks than Diksha. Chandani scored less marks than Mahesh.
    So, Mahesh > Chandani > Kashish > Diksha.
    3) Both Mahesh and Nitin scored less marks than Hemant but more than Rohan and the marks scored by Rohan is not the least.
    So, Hemant > Mahesh > Chandani > Kashish > Diksha and Nitin scored more marks than Rohan and the marks scored by Rohan is not the least.
    Thus, Hemant > Mahesh > Chandani > Kashish > Nitin > Rohan >Diksha.

    Hence, only Rohan scored between the scores of Nitin and Diksha.
  • Question 4/6
    1 / -0.25

    Directions For Questions

    Direction: Read the following information carefully and answer the questions that follow:

    Seven friends – Chandani, Diksha, Hemant, Kashish, Mahesh, Nitin and Rohan are comparing their scores of an exam. Following is the information about their scores.

    (i) Each of them scored a distinct mark.
    (ii) Kashish scored the same marks as the average of the marks scored by Chandani and Diksha where Chandani scored more than Diksha.
    (iii) Both Mahesh and Nitin scored less than Hemant but more than Rohan and the marks scored by Rohan is not the least.
    (iv)The number of persons who scored more than Kashish is the same as the number of persons who scored less than Kashish.
    (v) Chandani scored less than Mahesh.

    ...view full instructions

    Which of the following is true?
    Solutions
    Persons: Chandani, Diksha, Hemant, Kashish, Mahesh, Nitin and Rohan
    1) The number of persons who scored more marks than Kashish is same as the number of persons who scored less marks than Kashish.
    So, Kashish scored fourth highest marks.

    2) Kashish scored the same marks as the average of the marks scored by Chandani and Diksha where Chandani scored more marks than Diksha. Chandani scored less marks than Mahesh.
    So, Mahesh > Chandani > Kashish > Diksha.
    3) Both Mahesh and Nitin scored less marks than Hemant but more than Rohan and the marks scored by Rohan is not the least.
    So, Hemant > Mahesh > Chandani > Kashish > Diksha and Nitin scored more marks than Rohan and the marks scored by Rohan is not the least.
    Thus, Hemant > Mahesh > Chandani > Kashish > Nitin > Rohan >Diksha.

    Hence, Nitin scored more marks than Diksha.
  • Question 5/6
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    Ram completes 40% of a task in 32 days and then takes the help of Mayank and Virat. Mayank is 80% as efficient as Ram is and Virat is 50% as efficient as Mayank. In approximately how many more days will they complete the work?
    Solutions
    Assume that total work = 80 units. (We assumed this number to keep the calculation easy, as time taken by Ram to do 100% comes out to 80 days)


    Ram completes 40% of a task in 32 days.
    ∴ Ram completes 40% of 80 = 32 units of the task in 32 days.
    ∴ His efficiency = (32 ÷ 32) = 1 unit/day.
    Mayank is 80% as efficient as Ram is.
    ∴ Mayank’s efficiency = 0.8 unit/day.
    Virat is 50% as efficient as Mayank is.
    ∴ Virat’s efficiency = 0.4 unit/day.
    Total efficiency when they work together = (1 + 0.8 + 0.4) = 2.2 units/day
    Remaining work after 32 days = (80 – 32) = 48 units.
    Time required to complete this work when they work together = (48 ÷ 2.2) ≈ 21.8 days.
  • Question 6/6
    1 / -0.25
    A leaves X for Y at 9 am, and B leaves Y for X at 12 pm. If A reaches Y at 1 pm and B reaches X at 6 pm, then at what time do they meet?
    Solutions
    Time taken by A to reach the destination = 4 hours
    Time taken by B to reach the destination = 6 hours
    Let distance between X and Y = 12 km (LCM of 4 and 6)
    Speed of A = 12/4 = 3 kmph
    Speed of B = 12/6 = 2 kmph
    At 12 P.M. A covered the distance of 3 × 3 = 9 km
    now, remaining distance to cover by both A and B after 12 PM = 12 - 9 = 3 km
    Relative speed of A and B = 3 + 2 = 5 kmph
    Therefore, the time at which both will meet = 12 PM + 3/5 hours = 12:36 PM
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