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SSC MTS 2023 Aptitude Test - 5
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SSC MTS 2023 Aptitude Test - 5

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  • Question 1/10
    3 / -0

    The expenses of a family on wheat, vegetables and oil are in the ratio 12 : 8 : 5 . The prices of these items increased by 50%, 25% and 40%, respectively. The total expenses of the family on these items increased by:

    Solutions

    Let the expenses of a family on wheat, vegetables and oil are in the ratio 12x, 8x and 5x respectively.

    Total expense = 12x + 8x + 5x = 25x

    Total increased expense = 6x + 2x + 2x = 10x

    ∴ Total expenses of the family on these items increased by

  • Question 2/10
    3 / -0

    The given pie charts show the number of start-ups in various industries since 2010 and the number of successful start-ups in those industries.

    Study the charts and answer the question that follows.

    Start-ups in various industries started since 2010

    What should be the increase in the number (to the nearest integer) of successful start-ups in the industry of Health & Sports, so that its success percentage is the same as that of Education?

    Solutions

    Let (300 + x) be the number of successful start-ups in Health & Sports so that its success percentage become equal to that of Education start-ups.

    ⇒ 300 + x = 426.56

    ⇒ x ≈ 127

    Hence, the correct answer is option D.

  • Question 3/10
    3 / -0

    A policeman noticed a thief from a distance of 400 m. The policeman runs to catch a thief. The thief and policeman run at 10 km and 11 km per hour respectively. What is the distance between them after 12 minutes?

    Solutions

    Relative speed between them= 11−10 = 1 km/hr

    ∵ Distance covered by them in 12 minutes

    = 12×1/60 = 200 m

    So distance between them

    = 400−200 = 200 m

    Hence, option D is the correct answer.

  • Question 4/10
    3 / -0

    The ratio of the ages of two friends is 7 : 9, while after 10 years it will become 19 : 23. What will be their average age 7 years from now?

    Solutions

    Let the age of friends be 7x and 9x years respectively.

    According to the question,

    After 7 years age of younger friend = 7x + 7 = 28 + 7 = 35 years

    After 7 years age of elder friend = 9x + 7 = 36 + 7 = 43 years

    Average age = (35 + 43)/2 = 78/2 = 39 years

  • Question 5/10
    3 / -0

    Present ages of A and B are in the ratio of 4: 5 respectively. Present ages of C and D are in the ratio of 5: 6 respectively. The present average age of A, B, C, and D is 40 years and 6 months. Age of A after 2 years will be half the age of D 6 years hence. Find the present average age of B and C:

    Solutions

    Let the present ages of A and B are 4x and 5x years respectively and the present ages of C and D are 5y and 6y years respectively.

    So, sum of the ages of A, B, C and D = 4x + 5x + 5y + 6y = 40.5 × 4

    So, 9x + 11y = 162

    Also given that,

    2 x (4x+2) = 6y + 6

    So, 4x – 3y = 1

    From both the equation, we get,

    x = 7 and y = 9

    So, the present ages of A, B, C and D are 28, 35, 45 and 54 respectively.

    Present average age of B and C = (35+45)/2 = 40years

  • Question 6/10
    3 / -0

    Directions For Questions

    Direction: Study the following bar-graph carefully and answer the following questions.

    Earning (in rupees) of three different persons on four different days.

    ...view full instructions

    What is the ratio of R’s earning on Monday, Wednesday and Thursday?

    Solutions

    Required ratio = 360:120:160 = 9:3:4

  • Question 7/10
    3 / -0

    If A can complete 1/9 part of the work in 5 days and B can complete the 5/18 part of same work in 10 days. If A and B work on alternate days, starting with A. Then, on which date they will complete the work if they start the work from 2nd March?

    Solutions

    A does 1/9 work in 5 days so, 1 work = 9×5 = 45 days

    B does 5/18 work in 10 days so, 1 work = (18/5)×10 = 36 days

    Total work = LCM of 45,36= 180 unit

    A’s 1 day work = 180/45= 4 units

    B’s 1 day work = 180/36= 5 units

    A starts the work on 1st day= 4 units and B starts the work on 2nd days = 5 units

    Total work done by A and B in 2 days= 4 + 5= 9 units

    So, time Taken to complete 180 units of work = 180/9 × 2= 40 days

    The work starts on 2nd March so the work will be completed on 10th April.

  • Question 8/10
    3 / -0

    Find the value of the following expression:

    372 ÷ 56 × 7 – 5 + 2

    Solutions

    The value of 372 ÷ 56 × 7 – 5 + 2

    By using BODMAS rules –

  • Question 9/10
    3 / -0

    The ratio of copper and zinc in a 72 kg alloy is 5:4. Some quantity of copper is extracted from it and then the ratio of the alloy becomes 3:4. What quantity of copper is taken out?

    Solutions

    Let the weights of copper and zinc are 5x and 4x respectively.

    ∴ 5x + 4x = 72

    ⇒ 9x = 72 ⇒ x = 8

    ∴ weight of copper = 5x = 5 × 8 = 40 kg

    and weight of zinc = 4x = 4 × 8 = 32 kg

    Now, let quantity of copper extracted is y.

    ∴ According to the question,

    ⇒ 40 – y = 24 ⇒ y = 16 kg

    Hence, option B is the correct answer.

  • Question 10/10
    3 / -0

    Two trains P and Q start from stations X and Y towards each other. Trains take 5 hours and 4 hours 3 minutes to reach Y and X respectively after they meet. If speed of train P is 54 km/hr, then what is the speed (in km/hr) of the train Q?

    Solutions

    5 Hour = 300 Minutes

    4 Hours 3 minutes = 243 Minutes

    ⇒ S2 = (10×54)/9

    ⇒ S2 = 60 km/hr.

    Hence, option A is the correct answer.

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