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CAPF - Problem Based on Ages Test 1064
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CAPF - Problem Based on Ages Test 1064

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  • Question 1/5
    1 / -0.33
    Ratio of age of the two persons is 5:9 and one of them is 40 years older than the other find the sum of their ages?
    Solutions

  • Question 2/5
    1 / -0.33
    Two years ago, the age of A was three times the age of B . If B is currently 9 years old, then after how many years, the age of A will be double of the age of B?
    Solutions
    three years ago,

    Given that B = 9 then

    Let after x years the age of A will be double of the age of B

  • Question 3/5
    1 / -0.33
    One year ago, a father was four times as old as his son. After six years his age exceeds twice his son’s age by 9 years. The ratio of their present age is
    Solutions

    Let the age of father is X,

    Let the age of son is Y,

    One year ago, X-1=4(Y-1),

    X-4Y= -3……..(1),

    X+6= (Y+6)2+9,

    X+6 = 2Y+21,

    X-2Y= 15……..(2)

    By solving equation 1 and 2,

    4Y-3=2Y+15,

    2Y=18,

    Y=9 AND X=33,

    So 11:3

  • Question 4/5
    1 / -0.33
    One year ago, a father was four times as old as his son. After six years his age exceeds twice his son’s age by 9 years. The ratio of their present age is
    Solutions

    Let the current age of father is X,


    Current age of sun is Y,


    1 year ago, X-1=(Y-1)4,


    X=4Y-3…….(1)


    After 6 years , X+6=( Y+6)2+9,


    X+6=2Y+12+9,


    X-2Y=15……..(2),by solving equation 1 and 2,


    4Y-3=2Y+15,


    2Y=18,


    Y=9, X=33,


    So the ratio is, 33/9=11/3 that means 11::3.


  • Question 5/5
    1 / -0.33
    In a family, the age of father, mother, son and grandson are A, B, C and D, respectively. Given that, A - B = 3, B + C = 78, C + D = 33 and the average age of the family as 34 yr, then B - C is
    Solutions

    Give, the age of father, mother, son and grandson are- A, B, C and D

    A-B=3, B+C=78, C+D=33

    Average age of the family = 34 yr

    Then, A+B+C+D=34*4=136

    Put value, C+D=33

    A+B+33=136

    A+B=103

    A-B=3

    2B=100 subtracting both the equation

    B=50

    B+C=78, Then 50+C=78

    C=28

    Then, B-C=50-28=22

    B-C=22

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