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SUPER 10 Quant Test 522
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SUPER 10 Quant Test 522

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  • Question 1/10
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    A man can row to a place 66 km downstream and then comes back in  hours. If he can row the boat downstream at a speed of 6 km/hr, then what will be the speed of the boat in still water?
    Solutions

    Downstream speed of the boat = 6 km/hr, then 
    Time taken in travelling 66 km downstream = 66/6 = 11 hr
    Time taken in travelling 66 km upstream =  – 11 = (33/2)  hr
    Upstream speed of the boat = 66/(33/2) = 4 km/hr
    So, the speed of boat in still water = (Downstream + Upstream)/2 = (6 + 4)/2 = 5 km/hr.

  • Question 2/10
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    A man takes thrice as long to row a distance against the stream as to row the same distance in favour of stream. Find the ratio of speed of boat in still water to the speed of the stream.
    Solutions

    As we know,

    Speed =

    Here, ratio of speed of upstream to downstream = 1 : 3

    Let us assume the speed of upstream = x

    So, the speed of the downstream = 3x

    Since, speed of boat in still water – speed of stream = x

    speed of boat in still water + speed of stream = 3x

    2 × Speed of boat in still water = 3x + x

    Speed of boat in still water = 2x

    Ratio of speed of boat in still water to the speed of the stream = 2x : x

    = 2 : 1

  • Question 3/10
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    A boatman goes 2.25 km downstream in 7 minutes and 19 km upstream in 2.5 hours. How long the boatman will take to go 192 km in still water?
    Solutions

    Let the speed of boatman in still water = x km/h

    Let the speed of the current = y km/h


    According to the question,

    x + y =  ⇒ x + y = 18 …..(1)

    x – y =  ⇒ x – y =  …..(2)

    Solving eq. 1 & eq. 2, we get x = 12.8 & y = 5.2

    Time taken by the boat to cover 192 km in still water =  = 15 hours

  • Question 4/10
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    Directions For Questions

    Direction: Each question is followed by two statements I and II. You have to study the question and decide whether the information given in the statements are sufficient for answering the question. Read all the statements carefully and seek all the possible combinations which could be sufficient for answering the question.

    ...view full instructions

    How much profit did Anand make by selling a bed?

    Statement I: He bought the bed with 40% discount on the labelled price.

    Statement II: He sold it with 20% profit on the labelled price.

    Solutions

    Let the labelled price be Rs. x


    From Statement I:

    From Statement II:

    From Statement I and II together:

    Thus, even statement I and II together do not give the answer

    Hence, option D is the answer.

  • Question 5/10
    1 / -0.25

    Directions For Questions

    Direction: Each question is followed by three statements I, II, III. You have to study the question and decide whether the information given in the statements are sufficient for answering the question. Read all the statements carefully and seek all the possible combinations which could be sufficient for answering the question.

    ...view full instructions

    What is the monthly income of Mr. Taneja?

    Statement I: Monthly expenditure of Mr Taneja is Rs. 28000

    Statement II: Mr. Taneja deposits 50% of his income in PPF and his expenditure on food is Rs. 8000

    Statement III: Mr. Taneja saves 20% of his salary

    Solutions

    From I and III:

    ∴ Salary= Rs. 35000

    From II, we get no information

    Hence, E is the answer

  • Question 6/10
    1 / -0.25

    Directions For Questions

    Direction: Each question is followed by three statements I, II, III. You have to study the question and decide whether the information given in the statements are sufficient for answering the question. Read all the statements carefully and seek all the possible combinations which could be sufficient for answering the question.

    ...view full instructions

    A, B and C together start a business with a total investment of Rs. 15000. At the end of the year, the total profit is Rs. 3000. What is A’s share in the profit if all three persons invest for 1 year?

    Statement I: A’s contribution is 3/2 times B’s

    Statement II: B’s contribution is twice that of C

    Statement III: A’s contribution is thrice that of C

    Solutions

    Let C’s contribution be Rs. x

    From I and II, we get:

    From II and III, we get:

    From I and III, we get:

    A’s share =

    Thus, any two of the three give the answer.

    ∴ Hence option D

  • Question 7/10
    1 / -0.25

    Directions For Questions

    Direction: Each question is followed by two statements I and II. You have to study the question and decide whether the information given in the statements are sufficient for answering the question. Read all the statements carefully and seek all the possible combinations which could be sufficient for answering the question.

    ...view full instructions

    A and B together can complete a task in 7 days. B alone can do it in 20 days. What part of the work was carried out by A?

    Statement I: A completed the job alone after A and B worked together for 5 days.

    Statement II: Part of the work done by A could have been done by B and C together in 6 days.

    Solutions

    Let the total work be 140 units.
    Combined efficiency of A and B = 140/7 = 20 units
    Efficiency of B = 140/20 = 7 units
    Efficiency of A = 20 − 7 = 13 units

    From I:
    Work done by A and B together in 5 days = 20 × 5 = 100 units
    Work done by A in 5 days = 13 × 5 = 65 units
    Total work done by A = 65 + 40 = 105 units (remaining work is done by A)
    Part of work done by A = 105/140 = 3/4

    Statement II is irrelevant.

    ∴ Correct answer is option A

  • Question 8/10
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    Directions For Questions

    Direction: In the following question two Quantities i.e., Quantity I and Quantity II are given. You have to determine the relation between Quantity I and Quantity II.

    ...view full instructions

    Quantity I: Time taken by car B to reach point X from point Y.

    Two cars A and B leave at the same time from points X and Y respectively for points Y and X respectively. They meet at point Z. After meeting, car A took 6 hours to reach point Y and car B took 24 hours to reach point X.

    Quantity II: 32 hours

    Solutions

    Quantity I:

    Let the time taken by car A and B to reach point Z be ‘t’ hours.

    t × t = 24 × 6 = 144

    ⇒ t = 12 hours

    Required time = 12 + 24 = 36 hours

    Quantity II:

    32 hours

    Here, Quantity-I > Quantity-II. Hence, the answer is option A.

  • Question 9/10
    1 / -0.25

    Directions For Questions

    Direction: In the following question two Quantities i.e., Quantity I and Quantity II are given. You have to determine the relation between Quantity I and Quantity II.

    ...view full instructions

    Quantity I: Time in which 16 women would be able to complete  of the work.

    10 men can complete a work in 12 days. Efficiency of a woman is half the efficiency of a man.

    Quantity II: Time taken by 12 children to complete a work.

    The efficiency of a child is less than the efficiency of a woman. 10 women complete a work in 11 days.

    Solutions

    Quantity I:

    Total work = 10 × 12 = 120 units

    Required time = 120 ×  ÷ = 10 days

    Quantity II:

    Total work = 10 × 11 = 110 units

    Required time > or 9.17 days

    Here, no relation can be established. Hence, the answer is option E.

  • Question 10/10
    1 / -0.25

    Directions For Questions

    Direction: In the following question two Quantities i.e., Quantity I and Quantity II are given. You have to determine the relation between Quantity I and Quantity II.

    ...view full instructions

    Quantity I: Speed of train in km/hr if its length is 180 m and it passes a pole in 20 seconds.


    Quantity II:     Usual speed of car in km/hr. If Amit drove a car at a speed of 10 km/hr less than usual, he took 30 mins more than usual to reach office. Amit usually took 2 hours to reach his office.

    Solutions

    Quantity I:

    Speed of train = ×  = 32.4 km/hr

    Quantity II:

    Let the Initial speed of car be x km/hr.

    (x – 10)(2.5) = (x)(2)

    ⇒ 2.5x – 25 = 2x

    ⇒ x = 50 km/hr

    Here, Quantity-I < Quantity-II. Hence, the answer is option B.

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