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And water in the mixtue = 80 – 20 = 60
Let litres of water is added in the mixture, so
Final quantity =
C→ capacity of vessel
x→ Quantity taken out at a time
n→ No. of process
Final Quantity
=
=12.8 litres
Required ratio
=12.8 : 20
= 128 : 200
= 16 : 25
According to question
LCM (5,10,15) = 30
Hence, Required Ratio = 5 : 4
Alloy A contains 30% tin while Alloy B contains 10% of tin
So Alloy A Alloy B
1 : 1
So, both alloys should mixed in 1:1 so that in new mixture % of tin will be 20%
Correct (-)
Wrong (-)
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