Please wait...
/
-
In the following questions, two statements numbered I and II are given. On solving them we get two quantities, quantity I and quantity II respectively. Solve for both the quantities and choose the correct option.
Quantity I: Selling price of a solution which is bought at Rs 200/litre, marked up by 40% and sold after providing a discount of 10%.
Quantity II: Cost price of a solution which is sold at Rs 240/litre, after providing a discount of 20%, mark-up on which was 20%.
Quantity I:
C.P = Rs 200/litre
M.P = 200(1 + 40/100) = Rs 280/litre
S.P = 280(1 - 10/100) = Rs 252/litre
Quantity II:
Let the C.P be Rs 100x/litre
M.P = 100x = 100x(1 + 20/100) = Rs 120x/litre
S.P = 120x(1 - 20/100) = Rs 96x/litre
96x = 240
=> x = 2.5
C.P = 100x = Rs 250/litre
Quantity I > Quantity II
A started a business with B such that investment made by him was three times the investment made by B and his period of invest is 5/4 times the period of investment of B. If A received Rs.3000, what is the total profit?
Investment ratio, A: B = 3: 1
Time ratio, A: B = 5: 4
Profit ratio, A: B = 5 x 3: 1 x 4 = 15: 4
Profit = (19/15) x 3000 = Rs.3800
Find the next term in the series.
735, 748, 759, 768, 775, ?
The pattern is as follows:
35 x 21 = 735
34 x 22 = 748
33 x 23 = 759
32 x 24 = 768
31 x 25 = 775
30 x 26 = 780
What value will come in place of question mark (?) in the following question?
? = 84 x (29/6) - √1296
= 14 x 29 - 36
= 406 - 36 = 370
In an examination, Rahul received 32% of the total marks and failed by 12 marks. The marks of Ravi were 40% more than that of Rahul's marks and received 52 more than the passing marks. In the examination, passing marks is how much less than that of the total marks?
In the examination, let the total marks = a
The marks received by Rahul = 32% of a = 0.32a
Passing marks = 0.32a + 12 -------- (i)
Ravi's marks = 140% of 0.32a = 0.448a
Passing marks = 0.448a - 52 -------- (ii)
Therefore, 0.32a + 12 = 0.448a - 52
0.128a = 64
a = 500
Passing marks = 0.32a + 12 = 172
The required answer = 500 - 172 = 328
37, 51, 67, 85, 105, ?
9 x 4 + 1 = 37
10 x 5 + 1 = 51
11 x 6 + 1 = 67
12 x 7 + 1 = 85
13 x 8 + 1 = 105
14 x 9 + 1 = 127
In the following questions two equations numbered I and II are given. You have to solve both the equations and choose the correct option.
I. x2 +30x +176 = 0
II. y2 +11y +28 = 0
From equation I:
x2 +30x +176 = (x + 22)(x + 8)= 0
=> x = -22, -8
From equation II:
y2 +11y +28 = (y + 7)(y + 4) = 0
=> y = -7, -4
Price of a gold increased by 20% in the year 2013 over price in the previous year, it is decreased by 10% in the year 2014 over price in the previous year and increases by 30% in 2015 over the price in the previous year. If price of gold per gram in year 2012 was Rs.3000, then price per gram of gold in year 2015 was how much more than price per gram of gold in year 2012?
Price of gold per gram in the year 2013 = 1.2 x 3000
Price of gold per gram in the year 2014 = 0.9 x 1.2 x 3000
Price of gold per gram in the year 2015 = 1.3 x 0.9 x 1.2 x 3000
= Rs.4212
Per gram increase in price = Rs.4212 -Rs.3000 = Rs.1212.
16.0, 24.0, 60.0, 210.0, 945.0, ?
16 x 1.5 = 24.0
24 x 2.5 = 60.0
60 x 3.5 = 210.0
210 x 4.5 = 945.0
945 x 5.5 = 5197.5
7529536, 537824, 38416, 2744, 196, ?
7529536/14 = 537824
537824/14 = 38416
38416/14 = 2744
2744/14 = 196
196/14 = 14
Correct (-)
Wrong (-)
Skipped (-)