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R = {(x, y) | x, y are real numbers and x = wy for some rational number w}
where m, n, p, q are integers such that n q ≠ 0 and qm = pn}
Statement - 1: S is an equivalence relation but R is not an equivalence relation.
Statement - 2: R and S both are symmetric.
If f : I → I be defined by f(x) = x + i, where i is a fixed integer, then f is
f(x1) = f(x2)
⇒ x1 + i = x2 + i
⇒ x1 = x2 and for any integer y, y = x + i
⇒ x = y - i, i.e. f(y - i) = y
Hence, f is both one-one and onto.
Part of the domain of the function f (x) lying in the interval [- 1, 6] is
The domain of the function
The domain of the real-valued function f(x)
Directions: The following question has four choices, out of which ONE or MORE is/are correct.
A function f is defined by where [.] denotes g.i.f., then the function is
Let R be the set of all real numbers. The function
Which of the following functions is not one-one?
Correct (-)
Wrong (-)
Skipped (-)