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A bomber plane is moving horizontally with a speed of 500 m/s and a bomb released from it strikes the ground in 10 seconds. The angle with the horizontal at which the bomb strikes the ground is (g = 10 m/s2)
Let the vertical component of velocity when the bomb strikes the ground be Vv. Let the horizontal component of velocity when the bomb strikes the ground be VH. Vv = 0 + gt Where, t = 10 seconds, Vv = 10 x 10 = 100 m/s and VH = 500 m/s
It is found that (range)2 is 48 times the (maximum height)2 for a trajectory. Find the angle of projection.
The angle between two vectors A and B is θ. Vector R is the resultant of the two vectors. If R makes an angle θ/2 with A, then
The following question has four choices out of which ONLY ONE is correct.
For the angles of projection of a projectile as (45o - θ) and (45o + θ), the horizontal ranges described by the projectile are in the ratio
If a particle is projected with a velocity 'u' so that its horizontal range is twice the greatest height attained, then what is the horizontal range?
The air resistance causes a vertical retardation equal to the 10% of the acceleration due to gravity. The maximum height will be decreased by (Take g = 10 ms-2)
The following question has four choices, out of which ONLY ONE is correct.
A projectile can have the same range R for two angles of projection. If t1 and t2 be the time periods of the flights in two cases, what is the product of the two time periods of the flights proportional to?
If a ball is thrown vertically upwards with speed 'u', then the distance covered during the last 't' seconds of its ascent is
Alternative method: Distance covered during the last t seconds of ascent = distance covered during the first t seconds of descent
A ball falling from a tower of height 'h' covers a distance h/2 in the last second of its motion. What is the height of the tower? (Take g = 10 ms–2)
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