Please wait...

Coordination Compounds Test - 12
Result
Coordination Compounds Test - 12

  • /

    Score

  • -

    Rank
Time Taken: -
  • Question 1/10
    1 / -0

    When SCN- is added to an aqueous solution containing Fe(NO3)3, the complex ion produced is

    Solutions

    Fe3+ + SCN- + H2O → [Fe (OH2)5SCN] 2+

     

  • Question 2/10
    1 / -0

    Which of the following complexes are heteroleptic?

    a. [Cr(NH3)6]3+
    b. [Fe(NH3)4Cl2]+
    c. [Mn(CN)6]4-
    d. [Co(NH3)4Cl2]+

    Solutions

    Complexes in which a metal is bound to more than one kind of donor groups, e.g. [Co(NH3)4Cl2]+ and [Fe(NH3)4Cl2]+, are known as heteroleptic.

     

  • Question 3/10
    1 / -0

    The correct IUPAC name of the complex [Co(NH3)4(H2O)Cl]Cl2 is

    Solutions

    The correct IUPAC name of the complex [Co(NH3)4(H2O)Cl]Cl2 is tetraammineaquachloridocobalt(III) chloride.

     

  • Question 4/10
    1 / -0

    The formula of dichlorobis(urea) copper (II) is

    Solutions

    The formula of dichlorobis(urea) copper (II) is [CuCl2{O=C(NH2)2}2].

     

  • Question 5/10
    1 / -0

    Which of the following will give the maximum number of isomers?

    Solutions

    [Cr(SCN)2(NH3)4]+ shows linkage, geometrical and optical isomers.

     

  • Question 6/10
    1 / -0

    Square planar complexes of the type MABXL (A, B, X and L are unidentates) show

    Solutions

    Square planar complexes of the type MABXL (where A, B, X, L are unidentates) show three isomers - two cis and one trans.

     

  • Question 7/10
    1 / -0

    The complexes [Co(NH3)6][Cr(CN)6] and [Cr(NH3)6][Co(CN)6] are the examples of which type of isomerism?

    Solutions

    Coordination isomerism occurs in compounds containing both cationic and anionic entities and the isomers differ in the distribution of ligands in the coordination entity of cationic and anionic parts. For example, [Co(NH3)6][Cr(CN)6] and [Cr(NH3)6][Co(CN)6].

     

  • Question 8/10
    1 / -0

    An aqueous pink solution of cobalt(II) chloride changes to deep blue on addition of excess of HCl. This is because

    a. [Co(H2O)6]2+ is transformed into [CoCl6]4-
    b. [Co(H2O)6]2+ is transformed into [CoCl4]2-
    c. tetrahedral complexes have smaller crystal field splitting than octahedral complexes
    d. tetrahedral complexes have larger crystal field splitting than octahedral complexes

    Solutions

    An aqueous pink solution of cobalt(II) chloride changes to deep blue on addition of excess of HCl. This is because tetrahedral complexes have smaller crystal field splitting than octahedral complexes. Hence, light of longer wave lengths is absorbed and that of shorter ave length (shades of blue) is transmitted.

     

  • Question 9/10
    1 / -0

    Match the following:

    Column I (Complex ion) Column II (Colour)
    A. [Co(NH3)6]3+ 1. Violet
    B. [Ti(H2O)6]3+ 2. Green
    C. [Ni(H2O)6]2+ 3. Pale blue
    D. [Ni(H2O)4(en)]2+ (aq) 4. Yellowish-orange
    5. Blue
    Solutions
    Column I (Complex ion) Column II (Colour)
    [Co(NH3)6]3+ Yellowish-orange
    [Ti(H2O)6]3+ Pale blue
    [Ni(H2O)6]2+ Green
    [Ni(H2O)4(en)]2+ (aq) Violet


     

  • Question 10/10
    1 / -0

    Metal-carbon bond in metal carbonyls possesses

    Solutions

    The metal-carbon bond in metal carbonyls possesses both s and p characters. The M–C s bond is formed by the donation of lone pair of electrons on the carbonyl carbon into a vacant orbital of the metal. The M–C p bond is formed by the donation of a pair of electrons from a filled d-orbital of metal into the vacant antibonding p * orbital of carbon monoxide. The metal to ligand bonding creates a synergic effect which strengthens the bond between CO and the metal.

     

User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Click on Allow to receive notifications
×
Open Now