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Vector Test - 5
Result
Vector Test - 5

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  • Question 1/10
    1 / -0

    Solutions

     

  • Question 2/10
    1 / -0

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  • Question 3/10
    1 / -0

    If px4 + qx3 + rx2 + sx + t =  then what is the value of p

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  • Question 4/10
    1 / -0

    If A and B are symmetric matrices of the same order and X = AB + BA and Y = AB – BA, then (XY)T is equal to

    Solutions

    X = AB + BA ⇒ XT = X and Y = AB – BA ⇒ YT = – Y

    Now, (XY)T = YT × XT = – YX.

     

  • Question 5/10
    1 / -0

     

    If A is a symmetric matrix and then A" is

  • Question 6/10
    1 / -0

    If , then A is

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  • Question 7/10
    1 / -0

  • Question 8/10
    1 / -0

    Solutions

     

  • Question 9/10
    1 / -0

     is equal to

    Solutions

     

  • Question 10/10
    1 / -0

    The distance of a point B with position vector i + 2j + 3k from the line passing through the point A with position vector 4i + 2j + 2k and parallel to the vector 2i + 3j + 6k is

    Solutions

    AB = – 3i + k. 

    Since AB(2i + 3j + 6k) = – 6 + 6 = 0, so AB is perpendicular to the given line. Thus, the required distance is equal to 

     

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