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Home
Thermodynamics Test - 37
Thermodynamics Test - 37
Result
Thermodynamics Test - 37
/
Score
-
Rank
Time Taken:
-
Question
1/10
4 / -1
Consider the following reactions at 1100°C
(I) 2C + O
2
→ 2CO, ∆G° = - 460 kJ mol
-1
(II) 2Zn + O
2
→ 2 ZnO, ∆G° = - 360 kJ mol
-1
Based on these, select correct alternate.
Correct
Wrong
Skipped
A
Zinc can be oxidised by CO
Correct
Wrong
Skipped
B
Zinc oxide can be reduced by carbon
Correct
Wrong
Skipped
C
Both are correct
Correct
Wrong
Skipped
D
None of the above is correct
Solutions
Question
2/10
4 / -1
For which reaction change of entropy will be positive ?
Correct
Wrong
Skipped
A
H
2
(g) + I
2
(g) ⇌ 2HI (g)
Correct
Wrong
Skipped
B
HCl (g) + NH
3
(g) ⇌ NH
4
Cl (s)
Correct
Wrong
Skipped
C
NH
4
NO
3
(s) ⇌ N
2
O (g) + 2H
2
O (g)
Correct
Wrong
Skipped
D
MgO (s) + H
2
(g) ⇌ Mg (s) + H
2
O (
l
)
Question
3/10
4 / -1
The value of log K
c
for a reaction
A ⇌ B is (Given, ∆
r
H° 298 K = - 54.07 kJ mol
-1
, ∆
r
S ° 298 K =10 JK
-1
mol
-1
and R = 8.314 JK
-1
mol
-1
2.303 × 8.314 × 298 = 5705)
Correct
Wrong
Skipped
A
5
Correct
Wrong
Skipped
B
10
Correct
Wrong
Skipped
C
95
Correct
Wrong
Skipped
D
100
Question
4/10
4 / -1
Enthalpy is equal to
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
Question
5/10
4 / -1
In an irreversible process taking place at constant T and p and in which only pressure-volume work is being done, the change in Gibbs free energy (dG) and change in entropy (dS ), satisfy the criteria.
Correct
Wrong
Skipped
A
(dS)
V ,E
< 0, (dG)
T ,p
< 0
Correct
Wrong
Skipped
B
(dS)
V ,E
> 0, (dG)
T ,p
< 0
Correct
Wrong
Skipped
C
(dS)
V ,E
= 0, (dG)
T ,p
= 0
Correct
Wrong
Skipped
D
(dS)
V ,E
= 0, (dG)
T ,p
> 0
Question
6/10
4 / -1
For the reaction at 298 K
A(g) + B(g) ⇌ C(g) + D(g)
∆H° = - 29.8 kcal , ∆S° = - 0.100 kcal K
-1
What is the value of ∆G° ?
Correct
Wrong
Skipped
A
1
Correct
Wrong
Skipped
B
0
Correct
Wrong
Skipped
C
2
Correct
Wrong
Skipped
D
4
Question
7/10
4 / -1
The direct conversion of A to B is difficult, hence it is carried out by the following shown path
Correct
Wrong
Skipped
A
+ 100 eu
Correct
Wrong
Skipped
B
+ 60 eu
Correct
Wrong
Skipped
C
- 100 eu
Correct
Wrong
Skipped
D
- 60 eu
Solutions
Question
8/10
4 / -1
The internal energy of one mole of a monoatomic gas is
Correct
Wrong
Skipped
A
Correct
Wrong
Skipped
B
Correct
Wrong
Skipped
C
Correct
Wrong
Skipped
D
Solutions
Question
9/10
4 / -1
The correct relationship between ∆H and ∆E for an ideal gas at constant temperature is
Correct
Wrong
Skipped
A
∆H = ∆E – P∆V
Correct
Wrong
Skipped
B
∆H = ∆E + P∆V
Correct
Wrong
Skipped
C
∆H = ∆E + ∆P. ∆V
Correct
Wrong
Skipped
D
∆H = E + P∆V
Question
10/10
4 / -1
You are given the following two reactions:
(i)CH
4
(g) + 20
2
(g) → CO
2
(g) + 2H
2
O(g), ∆H = - 890.4 kJ.
(ii)2HgO(s) → 2Hg(
l
) + O
2
(g) – 181.6 kJ
Which one of the following statements is correct
Correct
Wrong
Skipped
A
Both reactions are exothermic
Correct
Wrong
Skipped
B
Both reactions are endothermic
Correct
Wrong
Skipped
C
Reaction (i) is endothermic and (ii) is exothermic
Correct
Wrong
Skipped
D
Reaction (i) is exothermic and (ii) is endothermic
Re-attempt
-
Correct (
-
)
Wrong (
-
)
Skipped (
-
)
1
2
3
4
5
6
7
8
9
10
Re-attempt
-
Correct (
-
)
Wrong (
-
)
Skipped (
-
)
1
2
3
4
5
6
7
8
9
10
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