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Mechanical Properties of Solids Test - 21
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Mechanical Properties of Solids Test - 21

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  • Question 1/10
    4 / -1
    The area of cross-section of a steel wire (Y = 2.0 × 1011 N/m2) is 0.1 cm2. The force required to double its length will be
    Solutions

  • Question 2/10
    4 / -1
    Two identical wires of rubber and iron are stretched by the same weight, then the number of atoms in the iron wire will be
  • Question 3/10
    4 / -1
    Two wires A and B are of same materials. Their lengths are in the ratio 1 : 2 and diameters are in the ratio 2 : 1 when stretched by force FA and FB respectively they get equal increase in their lengths. Then the ratio FA/FB should be
    Solutions

  • Question 4/10
    4 / -1
    After effects of elasticity are maximum for
  • Question 5/10
    4 / -1
    A force of 200 N is applied at one end of a wire of length 2 m and having area of cross-section 102 cm–2. The other end of the wire is rigidly fixed. If coefficient of linear expansion of the wire a= 8 × 10–6/°C and Young\'s modulus Y = 2.2 × 1011 N/m2 and its temperature is increased by 5°C, then the increase in the tension of the wire will be
    Solutions

  • Question 6/10
    4 / -1
    A uniform plank of Young\'s modulus Y is moved over a smooth horizontal surface by a constant horizontal force F. The area of cross section of the plank is A. The compressive strain on the plank in the direction of the force is
    Solutions

  • Question 7/10
    4 / -1
    The length of a wire is 1.0 m and the area of cross-section is 1.0 × 10–2 cm2. If the work done for increase in length by 0.2 cm is 0.4 J, then Young\'s modulus of the material of the wire is
    Solutions

  • Question 8/10
    4 / -1
    Young\'s modulus of rubber is 104 N/m2 and area of cross-section is 2 cm2. If force of 2 × 105 dynes is applied along its length, then its initial length L becomes
    Solutions

  • Question 9/10
    4 / -1
    A copper wire of length 4.0 m and area of cross-section 1.2 cm2 is stretched with a force of 4.8 × 102 N. If Young\'s modulus for copper is 1.2 × 1011 N/m2, the increase in the length of the wire will be
    Solutions

  • Question 10/10
    4 / -1
    If the interatomic spacing in a steel wire is 3.0 A and Ysteel = 20 × 1010 N/m2, then force constant is
    Solutions

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