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Electrostatics Test - 129
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Electrostatics Test - 129

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  • Question 1/10
    4 / -1
    Consider a parallel plate capacitor of 10µF (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant 4, as shown in the figure. The capacity of the capacitor changes to

    Solutions

  • Question 2/10
    4 / -1
    Thecombinationofcapacitorswith C1 = 3 µF, C2 = 4 µF and C3 = 2µF is charged by connecting AB to a battery.
    Consider the following statements
    I. Energy stored in C1 = Energy stored in C2+ Energy stored in C3
    II. Charge on C1 = Charge on C2 + Charge on C3
    III. Potential drop across C1= Potential drop across C2 = Potential drop across C3
    Which of these is/are correct?

  • Question 3/10
    4 / -1
    A 20 F capacitor is charged to 5V and isolated. It is then connected in parallel with an uncharged 30 F capacitor. The decrease in the energy of the system will be
    Solutions

  • Question 4/10
    4 / -1
    A parallel plate capacitor has capacitance C. If it is equally filled with parallel layers of materials of dielectric constants K1 and K2 its capacity becomes C1.
    The ratio of C1 to C is
    Solutions

  • Question 5/10
    4 / -1
    The equivalent capacitance between A and B is

    Solutions

  • Question 6/10
    4 / -1
    The effective capacity between A and Bin the figure given is

    Solutions

  • Question 7/10
    4 / -1
    Three capacitors of 2 µF,3 µF and 6 µF are joined in series the combination is charged by means of a 24 volt battery. The potential difference between the plates ofthe 6 µF capacitor is
    Solutions

  • Question 8/10
    4 / -1
    The charge on any one of the 2 µF capacitors and 1 µF capacitor will be given respectively (in µC) as

    Solutions

  • Question 9/10
    4 / -1
    When two identical capacitors are in series have 3 µF capacitance and when parallel 12 µF. What is the capacitance of each?
    Solutions

  • Question 10/10
    4 / -1
    Three capacitors each of capacity 4µF are to be connected in such a way that the effective capacitanceis 6µF. This can be done by
    Solutions

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