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Atomic Structure Test - 26
Result
Atomic Structure Test - 26

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  • Question 1/5
    1 / -0

    The ratio of charge to mass of an electron in coulombs per gram was determined by J.J. Thomson. He determined this ratio by measuring the deflection of cathode rays in electric and magnetic fields. What value did he find for this ratio?

    Solutions

    Charge of an electron is
    = −1.6 × 10−19C
    Mass of electron is
    9.1 × 10−31kg = 9.1 × 10−28g
    Thus, Charge/mass ratio is


    = −1.76 × 108 coulombs /g

  • Question 2/5
    1 / -0

    The number of electrons which will together weigh one gram is

    Solutions

    Mass of electron = 9.1096 x 10-31 kg

    = 1.098 x 1027 electrons

  • Question 3/5
    1 / -0

    How many number of electrons are present in a particle which carries a charge of 5.5 x 10-16 C?

    Solutions

    Charge carried by one electron
    = 1.6022 x 10-19 C
    Electrons presents in 5.5 x 10-16 C

  • Question 4/5
    1 / -0

    Which experiment is responsible for finding out the charge on an electron?

    Solutions

    The value (magnitude) of electron charge was determined by Millikan's oil drop experiment.
    Cathode ray discharge tube experiment gave the sign of electron charge Rutherford's experiment gave the presence of electrons around the dense nucleus
    Photoelectric experiment explained the production of electricity from light irradiation on the metal surface.

  • Question 5/5
    1 / -0

    Match the values of column II with column I and mark the appropriate choice.

    Solutions

    (A) Mass of electron = 9.1 × 10−31 Kg
    (B) Mass of proton = 1.673 × 10−27 kg
    (C) Charge of electron = −1.602 × 10−19 C
    (D) e/m for an electron = 1.76 × 108 C/g
    Thus option B is the correct answer.

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