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What will be the wavenumber of yellow radiation having wavelength 240 nm?
Wavelength of yellow light = 240 nm240 x 10-9 m
What will be the energy of one photon of radiation whose frequency is 5 × 1014 Hz?
The energy of one photon is given by the expression, E = hνwhere, h = 6.626 × 10−34 Js and ν= 5 × 1014 s−1E = 6.626 × 10−34 × 5 × 1014 = 3.313 × 10−19J
The energy of a photon is given as 3.03 x 10-19 J/atom. The wavelength of the photon is
What will be the energy of a photon which corresponds to the wavelength of 0.50 Å?
E = hv = hc/λ
Compare the energies of two radiations E1 with wavelength 800 nm and E2 with wavelength 400 nm.
Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?
λ = 242 nm = 242 x 10-9 mEnergy required to ionise one atom of Na, E = hc/λ
The energy difference between the ground state of an atom and its excited state is 3 x 10-19 J. What is the wavelength of the photon required for this transition?
ΔE = hc/λ
A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb.
Power of the bulb = 100 watt = 100 J s-1 Energy of one photon E = hv = hc/λNumber of photons emitted
Mark the incorrect statement regarding the photoelectric effect.
The number of electrons ejected is directly proportional to the intensity of light
A certain metal when irradiated by light (v = 3.2 x 1016 Hz) emits photoelectrons with twice K.E. as did photoelectrons when the same metal is irradiated by light (v = 2.0 x 1016 Hz). The v0 of the metal is
(K.E.)1 = hv1 - hv0(K.E)2 = hv2 - hv0 As (K.E)1 = 2 x (K.E.)2∴ (hv1 - hv0)0) = 2(hv2 - hv0)or v0 = 2v2 - v1= 2 x (2 x 1016) - (3.2 x 1016) = 0.8 x 1016 Hz or 8 x 1015 Hz
The spectrum of white light ranging from red to violet is called a continuous spectrum because
In a continuous spectrum, the colours merge into each other in a continuous pattern.
The emission spectrum of hydrogen is found to satisfy the expression for the energy change ΔE (in joules) such that where n1 = 1, 2, 3,.... and n2 = 2, 3, 4. The spectral lines corresponds to Paschen series if
For Paschen series, n1 = 3 and n2 = 4,5, 6...
The wavelength of visible light is
Visible light wavelength is from 380 nm to 760 nm.
Which of the following types of spectrum is best depicted by the given figure?
Since the sample is an 'Excited sample', therefore this can not be absorption spectra but is an emission spectrum. Also, the light disperses from the sample towards the detector direction.
Match the constants given in column I with their values given in column II and mark the appropriate, choice.
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