The plates of parallel plate capacitor are charged upto 100V. A 2mm thick plate is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by 1.6 mm. The dielectric constant of the plate is

A capacitor with air as the dielectric is charged to a potential of 100 volts. If the space between the plates is now filled with a dielectric of dielectric constant 10, the potential difference between the plates will be

The capacitance of a metallic sphere will be 1µF , if its radius is nearly

A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then slipped between the plates, which results in

The insulated spheres of radii R₁ and R₂ having charges Q₁ and Q₂ respectively are connected to each other. There is

Separation between the plates of a parallel plate capacitor is d and the area of each plate is A. When a slab of material of dielectric constant k and thickness t (t < d) is introduced between the plates, its capacitance becomes

If the dielectric constant and dielectric strength be denoted by k and x respectively, then a material suitable for use as a dielectric in a capacitor must have

The area of each plate of a parallel plate capacitor is 100cm² and the distance between the plates is 1nm. It is filled with mica of dielectric 6. The radius of the equivalent capacity of the sphere will be

The capacity of a parallel plate condenser is 10µF without dielectric. Dielectric of constant 2 is used to fill half the distance between the plates, the new capacitance in µF is

The capacity of pure capacitor is 1 farad. In D.C. circuit, its effective resistance will be