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Magnetic Effects Of Current Test - 8
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Magnetic Effects Of Current Test - 8
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  • Question 1/10
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    A particle consisting of two electrons is moving in a magnetic field of (3i+2j)T a velocity  The magnetic force acting on the particle will be

    Solutions

     

  • Question 2/10
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    What is the net force on the square coil

    Solutions

    Force on side BC and AD are equal but opposite so their net will be zero.

     

  • Question 3/10
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    A proton is to circulate the earth along the equator with a speed of 1⋅0×107ms−1. Find the minimum magnetic field which should be created at the equator for this purpose. The mass of proton = 1⋅7×10−27kg and radius of earth = 6⋅37×106m

    Solutions

     

  • Question 4/10
    1 / -0

    An α-particle is describing a circle of radius 0.45 m in a field of magnetic induction 1.2 weber/m2. The potential difference required to accelerate the particle, so as to give this much energy to it (The mass of α-particle is 6.8 × 10-27 kg and its charge is 3.2 × 10–19 coulomb.) will be- 

    Solutions

    If V is accelerating potential of α-particle, then Kinetic energy = qV 14 × 106 eVolt = 2eV (since charge on α-particle = 2e)

     

  • Question 5/10
    1 / -0

    An electron beam passes through a magnetic field of 2×10−3 weber/m2 and an electric field of 1⋅0×104Vm−1 both acting simultaneously. The path of electrons remaining undeviated, calculate the speed of the electrons. If the electric field is removed what will be the radius of the electron path?

    Solutions

     

  • Question 6/10
    1 / -0

    A one meter long wire is lying at right angles to the magnetic field. A force of 1 kg wt is acting on it in a magnetic field of 0.98 Tesla. The current flowing in it will be

    Solutions

    F = Bil ⇒ 1 × 9.8 = 0.98 × i × 1 ⇒ i = 10A

     

  • Question 7/10
    1 / -0

    A circular coil of radius 4 cm and 20 turns carries a current of 3 ampere. It is placed in a magnetic field of 0.5 T. The magnetic dipole moment of the coil is

    Solutions

     

  • Question 8/10
    1 / -0

    A circular coil of radius 4 cm has 50 turns. In this coil a current of 2 A is flowing. It is placed in a magnetic field of 0.1 weber/m2. The amount of work done in rotating it through 180° from its equilibrium position will be

    Solutions

    Work done in rotating a coil through an angle θ from it's equilibrium position is W = MB(1 – cosθ) where θ = 180°  and M

    = W = 0.1 j

     

  • Question 9/10
    1 / -0

    The deflection in a moving coil galvanometer is

    Solutions

    The deflection of the coil of moving coil galvanometer is given by:

    ⇒ θ ∝ N (Number of turns)

     

  • Question 10/10
    1 / -0

    A moving coil galvanometer has a coil of effective area A and number of turns N. The magnetic field B is radial. If a current I is passed through the coil, the torque acting on the coil is.

    Solutions

    Let l and b be the length and breadth of the coil respectively. Effective area =A

    If θ is the angle formed by direction of magnetic field with normal drawn on the plane of coil , then

    Torque τ = NIBA sin θ

    With radial magnetic field θ = 90

    τ = NABI

     

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