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NEET Test 21
Result
NEET Test 21

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  • Question 1/20
    4 / -1

    Solutions

  • Question 2/20
    4 / -1

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  • Question 3/20
    4 / -1

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  • Question 4/20
    4 / -1

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  • Question 5/20
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  • Question 6/20
    4 / -1

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  • Question 7/20
    4 / -1

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    assuming charge on Proton as q and mass as m, above is the equation based on conservation of energy (decrease in potential energy is equal to increase in kinetic energy here) 

    therefore, uproton = √(2qV/m)

    As α particle has 2 protons and 2 neutrons, so charge = 2q and mass = 4m and the equation becomes

    2qV = 1/2 * 4m * u2

    So, uα = √(qV/m)

    Therefore, uα =  uproton / √2

     

  • Question 8/20
    4 / -1

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  • Question 9/20
    4 / -1

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  • Question 10/20
    4 / -1

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  • Question 11/20
    4 / -1

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  • Question 12/20
    4 / -1

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  • Question 13/20
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  • Question 14/20
    4 / -1

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  • Question 15/20
    4 / -1

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  • Question 16/20
    4 / -1

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  • Question 17/20
    4 / -1

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  • Question 18/20
    4 / -1

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  • Question 19/20
    4 / -1

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  • Question 20/20
    4 / -1

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