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Solution
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Q.54 Correct
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Q.54 Unattempt

The electric field of a uniform plane wave traveling along the negative z-direction is given by the following equation:

\({\rm{\vec E}}_{\rm{w}}^{\rm{i}} = \left( {{{{\rm{\hat a}}}_{\rm{x}}} + {\rm{j}}{{{\rm{\hat a}}}_{\rm{y}}}} \right){{\rm{E}}_0}{{\rm{e}}^{{\rm{jkz}}}}\)

This wave is incident upon a receiving antenna placed at the origin and whose radiated electric field towards the incident wave is given by the following equation:

\({\rm{\vec E}}_{\rm{a}}^{\rm{i}} = \left( {{{{\rm{\hat a}}}_{\rm{x}}} + {\rm{j}}{{{\rm{\hat a}}}_{\rm{y}}}} \right){{\rm{E}}_{\rm{I}}}\frac{1}{{\rm{r}}}{\rm{\;}}{{\rm{e}}^{{\rm{-jkr}}}}\)

The polarization of the incident wave, the polarization of the antenna and losses due to the polarization mismatch are, respectively,

The electric field of a uniform plane wave traveling along the negative z-direction is given by the following equation:

\({\rm{\vec E}}_{\rm{w}}^{\rm{i}} = \left( {{{{\rm{\hat a}}}_{\rm{x}}} + {\rm{j}}{{{\rm{\hat a}}}_{\rm{y}}}} \right){{\rm{E}}_0}{{\rm{e}}^{{\rm{jkz}}}}\)

This wave is incident upon a receiving antenna placed at the origin and whose radiated electric field towards the incident wave is given by the following equation:

\({\rm{\vec E}}_{\rm{a}}^{\rm{i}} = \left( {{{{\rm{\hat a}}}_{\rm{x}}} + {\rm{j}}{{{\rm{\hat a}}}_{\rm{y}}}} \right){{\rm{E}}_{\rm{I}}}\frac{1}{{\rm{r}}}{\rm{\;}}{{\rm{e}}^{{\rm{-jkr}}}}\)

The polarization of the incident wave, the polarization of the antenna and losses due to the polarization mismatch are, respectively,

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