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SBI Clerk 2020 Aptitude Test - 17
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  • Question 1/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    747.03 ÷ √6890 + √170 * 16.91 – 26.16 * √65 =?

  • Question 2/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    (13.07)2 + (29.93)2 - (23.314)2 =?

  • Question 3/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    (1710.01 ÷ √3250) – (13.19 * 1.991) =? ÷ √65

  • Question 4/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    29.91% of 580.07 + 21.181 % of 199.91 =? + √2115

  • Question 5/10
    1 / -0

    What approximate value should come in the place of (?) in the following questions?

    38.91 * 4.99 – 12.04 * √35 + 9.14 * 2.902 =?

  • Question 6/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 + 13x + 22 = 0

    II) y2 + 15y + 26 = 0

  • Question 7/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) 5x2 - 15x + 10 = 0

    II) y2 - 5y + 6 = 0

  • Question 8/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 – 12x + 32 = 0

    II) y2 – 17y + 72 = 0

  • Question 9/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 – 32x + 252 = 0

    II) y2 – 26y + 168 = 0

  • Question 10/10
    1 / -0

    Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

    I) x2 + 13x + 40 = 0

    II) y2 + 19y + 90 = 0

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