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Solutions Test - 9
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  • Question 1/10
    1 / -0.25

    The relative lowering in vapour pressure is proportional to the ratio of number of

  • Question 2/10
    1 / -0.25

    Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1 g of Y in 20 g of liquid X. If molar mass of X is 200, what is the molar mass of Y?

  • Question 3/10
    1 / -0.25

    An aqueous solution of 2% non - volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute?

  • Question 4/10
    1 / -0.25

    In the graph plotted between vapour pressure (V.P) and temperature (T).

  • Question 5/10
    1 / -0.25

    A solution containing 12.5g of non-electrolyte substance in 185g of water shows boiling point elevation of 0.80K. Calculate the molar mass of the substance. (Kb ​= 0.52K kg mol−1 )

  • Question 6/10
    1 / -0.25

    If 1g of solute (molar mass = 50g mol−1 ) is dissolved in 50g of solvent and the elevation in boiling point is 1K. The molar boiling constant of the solvent is?

  • Question 7/10
    1 / -0.25

    2 g of sugar is added to one litre of water to give sugar solution. What is the effect of addition of sugar on the boiling point and freezing point of water?

  • Question 8/10
    1 / -0.25

    Sprinkling of salt helps in clearing the snow-covered roads in hills. The phenomenon involved in the process is

  • Question 9/10
    1 / -0.25

    Equimolar solutions in the same solvent have

  • Question 10/10
    1 / -0.25

    A 5% solution (w/W) of cane sugar (molar mass = 342 g mol-1 ) has freezing point of 271 K. What will be  the freezing point of a 5% glucose (molar mass = 18 g mol-1 ) in water if freezing point of pure water is 273.15 K?

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