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Solutions
Given: Nine persons namely P, Q, R, S, T, U, V, W and X
Born in the same month of different year i.e. 1970, 1976, 1985, 1989, 1995, 2000, 2009, 2015 and 2019.
Having base year 2024
1) V was born in an even number year, but not born in the year, which is divisible by 4. Q is 48 years old now.
2) There is a difference of six years between S and T, who is younger than S.

As the age of Q is 48 years which is clearly given in the question, CASE 2 cannot be possible. Thus, it gets eliminated.
3) The age of R is a multiple of 13. U, who is born in an even numbered year is not the eldest among all.
4) The difference between the ages of W and X is the square of the smallest even number. W is not the youngest person among all.

U is born in an even numbered and he is not the eldest among all, thus CASE 2(a) also cannot be the possible case and gets eliminated. The difference between the ages of W and X is 4 which is the square of smallest even number.
5) P was not born in even numbered year neither he is of the age of any prime number.

As P is not born in any even numbered year neither he is of prime number age, thus CASE 3 also gets eliminated. And we have the final arrangement in CASE 1

From the above arrangement all the other pairs apart from VQ are born in a odd number years.
Hence, the correct answer is "VQ".