Hence, option C is the correct answer.

Checking option C,

2014 – 2003 = 11 odd days.

Also, Quotient (14/4) – Quotient (03/4) = 3 – 0 = 3 odd days

11 + 3 = 14 odd days and Remainder (14/7) = 0

Thus, the calendar of 2003 can be used in 2014.

Hence, option C is the correct answer.

Today = Friday

Odd Days = 55/7 = 6 odd days

After 55 days = Friday + 6 = Thursday.

Hence, option C is the correct answer.

30/01/2010 = Saturday

Odd days of the year till 30/01/2011 = 1

Days left in 2011 –

Jan – 1

Feb – 0

Mar – 1

Total odd days = 3

Saturday + 3 = Tuesday

Hence, option B is the correct answer.

There are 4 odd days remaining in 2012.

2013, 2014 and 2015 being normal years will have 1 odd day each = 3 odd days

2016 will have 31 days in January and 1 day in Feb = 4 odd days.

Total odd days = 4 + 3 + 4 = 11 and Remainder (11÷7) = 4

Thus, Thursday + 4 = Monday

Hence, option B is the correct answer.

20/02/2013 – Wednesday

Number of odd days for 3 years passed (till 20/02/2016) – 3

Number of days after 20/02/2016 – 8

Total = 3 + 8 = 11 and Remainder (11 ÷ 7) = 4

Thus, Wednesday + 4 = Sunday

Hence, option B is the correct answer.

20 July 2021 = Tuesday

28 Nov 2021 = ?

Number of days between 20 july and 28 November = 11 + 31 + 30 + 31 + 28 = 131

Number of odd days = 131/7 = 5

28 Nov 2021 = Tuesday + 5 = Sunday

Hence, option A is the correct answer.

28 Feb 2017 = Tuesday

28 Feb 2019 = ?

Odd days between 2017 to 2019 = 1 + 1 = 2

28 Feb 2019 = Tuesday + 2 = Thursday

Hence, option A is the correct answer.

11 July 2020 = Monday

Odd days between 11 july 2020 and 11 july 2028 = 10 = 10 /7 = 3

11 july 2028 = Monday + 3 = Thrusday

Days between 11 july 2028 and 14 october 2028 = 20 + 31 + 30 + 14 = 95

Odd days = 95/7 = 4

14 october 2028 = Thrusday + 4 = Monday

Hence, option B is the correct answer.

Since, 2020 was a leap year, 3^rd March 2019 would have been a Sunday.

(Tuesday – 2 = Sunday)

Now, from 3^rd Feb 2019 to 3^rd March 2019 –

Feb – 25 days

Mar – 3 days

Total 28 days, Remainder (28÷7) = 0

Thus, 3^rd Feb 2019 would also have been a Sunday.

Hence, option C is the correct answer.