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From figure AP BQ
Draw a line MN parallel to AP and BQ.
Because AP MN
⇒ ∠ APR = ∠ PRN = (alternate angles)
And MN BQ
⇒ ∠ BQR = ∠ QRN = (alternate angles)
⇒ ∠PRQ = ∠PRN + ∠NRQ =
Now y = ∠PRQ =
In
Hence,
Now in
Given that,
∝ = k and β = 5k
Or complementary angles, ∝ =90° - β
K = 90° - 5k
K = 15°
∝ = 15° and β = 75°
Difference between angles = 75°-15°=60°
Since, AB||DE,
Now,
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