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AFCAT - 2D Mensuartion Test 1187
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AFCAT - 2D Mensuartion Test 1187
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  • Question 1/5
    1 / -0.33
    An equilateral triangle circumscribes all the circles, each with radius 20 cm. what is the perimeter of the equilateral triangle?

    Solutions

    Given, Radius of each circle = 20 cm

    BC =CF + FG + GB = CF + 20+40+20 + GB

    Now in triangle DFC

    ⇒

    ⇒

    Similarly, GB =

    Hence, BC =CF + FG + GB = CF + 20+40+20 + GB =

    So, Side of equilateral triangle =

    Perimeter of equilateral triangle =

  • Question 2/5
    1 / -0.33
    Area of circle is equal to the area of a rectangle having perimeter of 92 cm and length is more than the breadth by 2 cm. what is the radius of the circle?
    Solutions

    Let the breadth of the rectangle be x cm

    Length of the rectangle = (x+2) cm

    Area of circle is equal to the area of a rectangle.

    ⇒  

    Area of circle =  = 528

    ⇒

    ⇒

  • Question 3/5
    1 / -0.33
    Consider an equilateral triangle having side of unit length. A new equilateral triangle is formed by joining the mid-points of the first-one, then a third equilateral triangle is formed by joining the mid-points of second-one. The process is continued to infinity. Then the sum of perimeters of all the triangles, thus formed is
    Solutions

    Sum of perimeter of all the triangles will be equal to (3x1) + (3x0.5) + (3x0.25) +………..

    Then , it will be equal to 3 + 1.5 + 0.75 + 0.375

    It is nothing but a G.P giving first term (a) = 3 &common ratio (r)=

    Then, sum of infinite term of a G.P = units

    So, option B is correct.

  • Question 4/5
    1 / -0.33
    How many cubic metres of the earth is to be dug out to dig a well of radius 1.4 m and depth 5 m ?
    Solutions

    When we dug in such a way, then it makes a cylinder

    The cubic metre volume of earth to be dig is

  • Question 5/5
    1 / -0.33
    If the diagonals of a rhombus are x and y, then what is its area?
    Solutions

    Let a rhombus which diagonals are x and y. Since the diagonal of rhombus cut each other at right angle and at the midpoint. Then area of the rhombus

     

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