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SSC MTS 2024 Aptitude Test - 7
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SSC MTS 2024 Aptitude Test - 7
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  • Question 1/10
    3 / -0

    Simplify: 362 - [26 + {16 + 5(9 ÷ 3)}]

    Solutions

    BODMAS Rule:

    Given:

    To simplify 362 - [26 + {16 + 5(9 ÷ 3)}]

    Calculation:

    362 - [26 + {16 + 5(9 ÷ 3)}]

    or 362 - [26 + {16 + 15}]

    or 362 - [26 + 31]

    or 362 - 57

    or 305

    ∴ The answer is 305 .

  • Question 2/10
    3 / -0

    A, B and C can do a work in 8, 10 and 12 days, respectively. After completing the work together, they received Rs. 5,550. What is the share of B (in Rs.) in the amount received?

    Solutions

    Given:

    A, B, and C can do a work in 8, 10, and 12 days, respectively.

    Total amount received = Rs. 5550

    Concept used:

    Efficiency or wages ratio ∝ 1/Time taken

    Calculation:

    A, B, and C can do a work in 8, 10, and 12 days, respectively.

    The ratio = 8 : 10 : 12

    The efficiency ratio of A, B, and C = 1/8 : 1/10 : 1/12

    = 15 : 12 : 10

    So, their wages ratio = 15 : 12 : 10

    The share of B = (12/37) × 5550 = Rs. 1800

    ∴ The share of B (in Rs.) in the amount received is Rs. 1800

  • Question 3/10
    3 / -0

    The given pie chart shows the total sales by different mobile companies in the year 2017.

    If the total sales in the year 2017 were 5000 crores, then the sales made by Vivo company was ________ crores.

    Solutions

    Calculation:

    Total sales in the year = Rs. 5000 crores

    Total sales by Vivo company = 6%

    Now,

    ⇒ (6% of 5000)

    ⇒ (6/100 × 5000)

    ⇒ 300 crores

    ∴ The sales made by Vivo company is 300 crores.

  • Question 4/10
    3 / -0

    The longest side of a right angled triangle is 90 cm and one of its other two sides is 54 cm. Area of this triangle is:

    Solutions

    Given:

    Longest side of the right-angled triangle: 90 cm One of the other two sides: 54 cm

    Solution:

    According to the Pythagorean theorem, in a right-angled triangle:

    ⇒ c2 = a2 + b2

    In this case, we have: c = 90 cm a = 54 cm

    Using the Pythagorean theorem, we can find the value of "b":

    ⇒ 902  = 542 + b2   

    ⇒ 8100 = 2916 + b2 

    ⇒ b2 = 8100 - 2916

    ⇒ b2  = 5184

    ⇒ b = 72 cm

    Now, we can calculate the area of the right-angled triangle using the formula:

    Area = (1/2) ×  base × height

    Area  = (1/2) ×  54 cm ×  72 cm

    Area = 1944 cm2

    Therefore, the area of the right-angled triangle is 1944 cm2.

    The correct answer is option 4) 1944 cm2.

  • Question 5/10
    3 / -0

    Train travelling at a speed of 90 km/hr crosses a man standing on a platform in 8 seconds. Find the time taken by the train to cross the platform of length 250 mtrs.

    Solutions

    Given:

    Speed of train = 90 km/h

    Time to cross a standing man = 8 seconds.

    Length of platform = 250 meters.

    Formula used:

    Distance = Speed × Time

    Calculation:

    According to the questions:

    Speed of train = 90 km/h

    ⇒ 90 × (5/18) m/sec.

    ⇒ 25 m/sec

    We know that the distance covered by a train to cross a standing object is the length of the train itself.

    So, Distance (Length of the train) = Speed × Time

    ⇒ Length of train = 25 × 8 m

    ⇒ Length of train = 200 m.

    When the train crosses the platform of length 250 m,

    Total distance covered by train = (200 + 250) m

    ⇒ 450 m

    Now, Time to cross the platform = Distance/Speed

    ⇒ Time to cross the platform = 450/25

    ⇒ Time to cross the platform = 18 seconds.

    ∴ The time taken to cross the platform is 18 seconds.

  • Question 6/10
    3 / -0

    The volume of a solid cone is 96 π cm3 and its height is 8 cm. What is its total surface area (in cm²)?

    Solutions

    Given:

    The volume of a solid cone is 96 π cm3

    Height = 8 cm

    Formula used:

    Volume of a cone = (1/3)πr2h

    Total surface area = πr(r + l)

    l = √(r2 + h2)

    Here,

    r = radius

    h = height

    l = slant height

    Calculation:

    Let the radius be r

    According to the question,

    (1/3)πr2 × 8 = 96π

    ⇒ (1/3)r= 12

    ⇒ r2 = 36

    ⇒ r = 6

    Now,

    l = √(62 + 82)

    ⇒ l = √(36 + 64)

    ⇒ l = √100

    ⇒ l = 10

    Total surface area = π × 6(6 + 10)

    ⇒ π × 6 × 16

    ⇒ 96π

    ∴ Its total surface area (in cm²) is 96π.

  • Question 7/10
    3 / -0

    Solutions

    Calculation:

    Here, we have (32/243)k = 8/27

    As, we can write 32 as 25 , 243 = 35

    Also 8 = 23 and 27 = 33

    ⇒ (2/3)5k = (2/3)3 

    ⇒ 5k = 3

    ⇒ k = 3/5

    Hence, the required value of k is 3/5.

  • Question 8/10
    3 / -0

    Ram's average mark in 5 subjects is 80. how much he must score in his next subject to get average marks of 82.

    Solutions

    Given:

    Ram's average mark in 5 subjects is 80,

    Ram's average mark in 6 subjects is 82.

    Formula used:

    Sum of n numbers = (Average of n numbers) × n

    Calculation:

    Average marks scored in 5 subjects = 80

    Total marks obtained in all 5 subjects = 80 × 5 = 400

    Total number of subjects = 6

    Average marks scored in 6 subjects = 82

    Total marks obtained in all 6 subjects = 82 × 6 = 492

    Therefore,

    Marks obtained in 6th subject = 492 - 400 = 92

    Therefore, '92' is the required answer.

    Alternate Method

    Ram's average mark in m subjects is x. he must score n marks in his next subject to get average marks of y.

    Therefore, 

    n = m × (y - x) + y

    According to the question,

    ⇒ n = 5 × (82 - 80) + 82

    ⇒ n = 5 × 2 + 82

    ⇒ n = 10 + 82

    ⇒ n = 92

    So, he must score 92 marks in his next subject to get an average mark of 82.

    Therefore, '92' is the required answer.

  • Question 9/10
    3 / -0

    Deepak's salary is 20 percent more than Raju's salary. If Deepak saves ₹18000 which is 48 percent of his salary, then what is Raju's salary?

    Solutions

    Given:

    Deepak's salary = 120% of Raju's salary

    Deepak's savings = Rs. 18000 = 48% of his salary

    Calculation:

    Let, Raju's salary = 100 unit

    According to the question,

    Deepak's salary = 120% × 100 = 120 unit

    Deepak's savings = 48% × 120 = 57.6 unit

    Now,

    ⇒ 57.6 unit = 18000

    ⇒ 1 unit = 18000/(57.6)

    ⇒ 1 unit = 18000 × 10/576 = Rs. 312.5

    So, Raju's salary = 312.5 × 100 = Rs. 31250

    ∴ Raju's salary is Rs. 31250.

  • Question 10/10
    3 / -0

    The least square number divisible by 5, 6, and 10 is

    Solutions

    Given:

    Numbers = 5, 6, and 10

    Concept used:

    The least common multiple (LCM) of two or more numbers is the smallest number that is a multiple of all of the numbers.

    Calculation:

    Factors(5) = 5

    Factors(6) = 2 x 3

    Factors(10) = 2 x 5

    ⇒ LCM(5, 6, 10) = 2 x 3 x 5

    ⇒ 30

    Square of 30 = 30 x 30

    ⇒ 900

    ∴ The least square number divisible by 5, 6, and 10 is 900.

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