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SSC MTS 2024 Aptitude Test - 8
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SSC MTS 2024 Aptitude Test - 8
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  • Question 1/10
    3 / -0

    Solutions

    BODMAS Rule:

  • Question 2/10
    3 / -0

    Given that c is the third proportional of 15 and b. If b is the sum of first three odd natural numbers, then the value of c is:

    Solutions

    Given:

    c is the third proportional of 15 and b.

    b is the sum of first three odd natural numbers.

    Formula Used:

    Third Proportional, c = b2/a

    Calculation:

    b is the sum of first three odd natural numbers.

    ⇒ b = 1 + 3 + 5

    ⇒ b = 9

    Third Proportional, c = b2/a

    ⇒ c = 92/15

    ⇒ c = 27/5

    ∴ Option 3 is the correct answer.

  • Question 3/10
    3 / -0

    Compound interest on a sum, when interest is compounded annually, equals Simple interest if time is:

    Solutions

    Calculation:

    At time = 1 year, the compound interest and simple interest are equal.

    Let the principal be 100a

    Let the rate be 10% 

    Then for 1 year, CI = P[(1 + R/100)1 - 1]

    100a[(1 + 10/100) - 1]

    100a[(1 + 1/10) - 1]

    100a(1/10) = 10a      ......(1)

    Now, for 1 year, SI = PRT/100

    (100a × 10 × 1)/100 = 10a      ......(2)

    From eq (1) and (2), we can say that at time = 1 year, CI and SI are equal.

    Hence, the correct answer is 1 year.

  • Question 4/10
    3 / -0

    A line graph is given below, study the graph carefully and answer the following questions.

    According to the given graph, the highest earnings was on:

    Solutions

    The highest earning was on Thursday.

    Additional Information

    Earning Day- wise

    Sunday = Rs. 100 

    Monday = Rs. 500 

    Tuesday = Rs. 300 

    Wednesday = Rs. 600 

    Thursday = Rs. 650 

    Friday = Rs. 300 

    Saturday =  Rs. 350 

    ∴ The highest earning was on Thursday.

  • Question 5/10
    3 / -0

    Find the total surface area (in cm2) of a cuboid having dimensions 5 cm, 7 cm and 11 cm.

    Solutions

    Given:

    Dimensions of cuboid = 5 cm × 7 cm × 11 cm 

    Formula used:

    Total surface area of cuboid = 2(lb + bh + hl)

    Calculation:

    Total surface area of cuboid = 2(5 × 7 + 7 × 11 + 11 × 5)

    ⇒ 2(35 + 77 + 55)

    ⇒ 2 × 167

    ⇒ 334 cm2

    ∴ The required result is 334 cm2.

  • Question 6/10
    3 / -0

    Find the Compound Interest on Rs. 1000 for two years at 2% per annum.

    Solutions

    Given:

    Principal = Rs. 1000

    Time = 2 years

    Rate of interest = 2%

    Formula:

    C.I = P × [(1 + r/100)n – 1]

    Here,

    P = Principal Amount

    r = Rate of interest

    n = Time in years

    Calculation:

    We know that -

    C.I = P × [(1 + r/100)n – 1]

    According to the question,

    C.I = 1000 × [(1 + 2/100)2 – 1]

    ⇒ C.I = 1000 × [(1 + 1/50)2 – 1]

    ⇒ C.I = 1000 × [(51/50)2 – 1]

    ⇒ C.I = 1000 × 101/50 × 1/50

    ⇒ C.I = 40.4

    ∴ The Interest Amount will be Rs. 40.4.

  • Question 7/10
    3 / -0

    Akash bought an old phone for Rs. 3,450 and spent Rs. 450 on its repair. He sold it for Rs. 5,070. His profit percent is:

    Solutions

    Given:

    CP = 3450

    Repair Price = 450

    SP = 5070

    Formula used:

    Profit% = Profit/CP × 100

    Calculation:

    The total cost of old phone = 3450 + 450 = 3900

    Profit = 5070 - 3900 = 1170

    Profit% = 1170/3900 × 100 = 30%

    The answer is 30%.

  • Question 8/10
    3 / -0

    In what ratio must 2 varieties of coffee costing Rs. 330 and Rs. 440 per kg be mixed to get a mixture worth Rs. 363 per kg?

    Solutions

    Given:

    2 varieties of coffee costing Rs. 330 and Rs. 440 per kg be mixed to get a mixture worth Rs. 363 per kg

    Calculation:

    Since the price of 2 varieties is Rs. 330 per kg and Rs. 440 per kg,

    Mixture Price = Rs. 363

    Required ratio should be

    = 440 – 363 : 363 – 330

    = 77 : 33

    = 7 : 3

  • Question 9/10
    3 / -0

    Imran get successive discounts of 40% and then 10% on his food bill of Rs.4750. What is the amount paid by Imran?(in Rs)

    Solutions

    Given:

    Food Bill = Rs. 4,750, D1 = 40%, and D2 = 10%

    Calculation:

    Amount paid = 4750 × (100 - 40)% × (100 - 10)%

    ⇒ 4750 × 60% × 90%

    ⇒ 4750 × 0.6 × 0.9 = 2565

    ∴ The amount paid by Imran is Rs. 2565

  • Question 10/10
    3 / -0

    The efficiencies of A, B, and C are in the ratio 5 ∶ 3 ∶ 2. Working together, they can complete a task in 21 hours. In how many hours will B alone complete 40% of that task?

    Solutions

    Given:

    The ratio of the efficiencies of A, B and C = 5 : 3 : 2

    Time taken by them to complete the task = 21 hours

    Concept used:

    Work = Efficiency × Time

    Calculation:

    Total 1 hour work = 5d + 3d + 2d = 10d

    Work completed in 21 hours = (21 × 10d) = 210 d

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