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BODMAS Rule:
Given that c is the third proportional of 15 and b. If b is the sum of first three odd natural numbers, then the value of c is:
Given:
c is the third proportional of 15 and b.
b is the sum of first three odd natural numbers.
Formula Used:
Third Proportional, c = b2/a
Calculation:
⇒ b = 1 + 3 + 5
⇒ b = 9
⇒ c = 92/15
⇒ c = 27/5
∴ Option 3 is the correct answer.
Compound interest on a sum, when interest is compounded annually, equals Simple interest if time is:
At time = 1 year, the compound interest and simple interest are equal.
Let the principal be 100a
Let the rate be 10%
Then for 1 year, CI = P[(1 + R/100)1 - 1]
100a[(1 + 10/100) - 1]
100a[(1 + 1/10) - 1]
100a(1/10) = 10a ......(1)
Now, for 1 year, SI = PRT/100
(100a × 10 × 1)/100 = 10a ......(2)
From eq (1) and (2), we can say that at time = 1 year, CI and SI are equal.
Hence, the correct answer is 1 year.
A line graph is given below, study the graph carefully and answer the following questions.
According to the given graph, the highest earnings was on:
The highest earning was on Thursday.
Additional Information
Earning Day- wise
Sunday = Rs. 100
Monday = Rs. 500
Tuesday = Rs. 300
Wednesday = Rs. 600
Thursday = Rs. 650
Friday = Rs. 300
Saturday = Rs. 350
∴ The highest earning was on Thursday.
Find the total surface area (in cm2) of a cuboid having dimensions 5 cm, 7 cm and 11 cm.
Dimensions of cuboid = 5 cm × 7 cm × 11 cm
Formula used:
Total surface area of cuboid = 2(lb + bh + hl)
Total surface area of cuboid = 2(5 × 7 + 7 × 11 + 11 × 5)
⇒ 2(35 + 77 + 55)
⇒ 2 × 167
⇒ 334 cm2
∴ The required result is 334 cm2.
Find the Compound Interest on Rs. 1000 for two years at 2% per annum.
Principal = Rs. 1000
Time = 2 years
Rate of interest = 2%
Formula:
C.I = P × [(1 + r/100)n – 1]
Here,
P = Principal Amount
r = Rate of interest
n = Time in years
We know that -
According to the question,
C.I = 1000 × [(1 + 2/100)2 – 1]
⇒ C.I = 1000 × [(1 + 1/50)2 – 1]
⇒ C.I = 1000 × [(51/50)2 – 1]
⇒ C.I = 1000 × 101/50 × 1/50
⇒ C.I = 40.4
∴ The Interest Amount will be Rs. 40.4.
Akash bought an old phone for Rs. 3,450 and spent Rs. 450 on its repair. He sold it for Rs. 5,070. His profit percent is:
CP = 3450
Repair Price = 450
SP = 5070
Profit% = Profit/CP × 100
The total cost of old phone = 3450 + 450 = 3900
Profit = 5070 - 3900 = 1170
Profit% = 1170/3900 × 100 = 30%
The answer is 30%.
In what ratio must 2 varieties of coffee costing Rs. 330 and Rs. 440 per kg be mixed to get a mixture worth Rs. 363 per kg?
2 varieties of coffee costing Rs. 330 and Rs. 440 per kg be mixed to get a mixture worth Rs. 363 per kg
Since the price of 2 varieties is Rs. 330 per kg and Rs. 440 per kg,
Mixture Price = Rs. 363
Required ratio should be
= 440 – 363 : 363 – 330
= 77 : 33
= 7 : 3
Imran get successive discounts of 40% and then 10% on his food bill of Rs.4750. What is the amount paid by Imran?(in Rs)
Food Bill = Rs. 4,750, D1 = 40%, and D2 = 10%
Amount paid = 4750 × (100 - 40)% × (100 - 10)%
⇒ 4750 × 60% × 90%
⇒ 4750 × 0.6 × 0.9 = 2565
∴ The amount paid by Imran is Rs. 2565
The efficiencies of A, B, and C are in the ratio 5 ∶ 3 ∶ 2. Working together, they can complete a task in 21 hours. In how many hours will B alone complete 40% of that task?
The ratio of the efficiencies of A, B and C = 5 : 3 : 2
Time taken by them to complete the task = 21 hours
Concept used:
Work = Efficiency × Time
Total 1 hour work = 5d + 3d + 2d = 10d
Work completed in 21 hours = (21 × 10d) = 210 d
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