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CAPF - Circle Test 1208
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CAPF - Circle Test 1208
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  • Question 1/5
    1 / -0.33
    A square is inscribed in a circle of diameter 2a and another square is circumscribing the circle. The difference between the areas of the outer and inner squares is
    Solutions

    Area or outer square = 2a x 2a = 4a2

    In△BAD

    (BD)2=(AD)2+(AB)2

    (2a)2=x2+x2

    4a2=2x2

    2a2=x2

    x=√2a.

    Area of inner square =√2a x √2a=2a2

    Difference between the areas of the outer and inner square =2a2

  • Question 2/5
    1 / -0.33
    Consider the following statements

    I. Area of a segment of a circle is less than area of its corresponding sector.

    II. Distance travelled by a circular wheel of diameter 2d cm in one revolution is greater than 6d cm?

    Which of the following statement(s) is/are correct?

    Solutions

    I. We know that,

    Area of segment PRQP = Area of segment OPRQO - Area of ∆OPQ

    =

    So, the area of a segment of a circle is always less than area of its corresponding sector.

    II. Distance travelled by a circular wheel of diameter 2d cm in one revolution = 2

    = 2 × 3.14 × d = 6.28d

  • Question 3/5
    1 / -0.33
    In a triangle ABC, AB = BC. A circle through A intersects AB at P and touches BC at its mid-point D. What is AB equal to?
    Solutions

    D is midpoint of BC. Therefore, BD = DC. We know that,





  • Question 4/5
    1 / -0.33
    In the given figure AP and PE are the angle bisectors of and such that Find
    Solutions
  • Question 5/5
    1 / -0.33
    The distance between the centres of two circles having radii 9 cm and 4 cm is 13 cm. What is the length of the direct common tangent of these circles?
    Solutions
    Given that radius of first circle(R) = 9 cm
    radius of second circle(r) = 4 cm
    Distance between the centers of two circles(d) = 13 cm
    The length of the direct common tangent of these circles =
    = = = = 12 cm
    Hence option (a)
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