Please wait...

SSC MTS 2024 Aptitude Test - 11
Menu grid icon
Result Result point icon
SSC MTS 2024 Aptitude Test - 11
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    3 / -0

    The line chart given below shows the income and expenditure of a company in five years.

    The income in years P and Q together is how much percent more than the expenditure in years S and T together?

    Solutions

    Calculation:

    Income of P and Q  = 650 + 450 = 1100

    Expenditure of S and T = 150 + 100 = 250

    According to the question:

    (1100 - 250)250 × 100

    850/250 × 100

    85 × 4 = 340%

    ∴ Option 4 is the correct answer.

  • Question 2/10
    3 / -0

    The difference between the 25% of a number and 30% of that number is 500. Then, what is the value of 20% of that number?

    Solutions

    Given: 

    The difference between the 25% of a number and 30% of that number = 500

    Calculation:

    Let the number be X

    According to the question, we have

    (30% of X) - (25% of X) = 500

    ⇒ 5% of X = 500

    ⇒ X = (500 × 100)/5

    ⇒ X = 10000

    Now,

    20% of X = (20/100) × 10000

    ⇒ 2 × 1000

    ⇒ 2000

    ∴ The value of 20% of the number is 2000.

  • Question 3/10
    3 / -0

    Ratio of three numbers is of 7 : 3 : 5. If their sum is 7200, then what is the sum of the largest and the smallest number?

    Solutions

    Given:

    Ratio of three numbers = 7 : 3 : 5

    Sum of the three numbers = 7200

    Calculation:

    Let the numbers be 7x, 3x and 5x

    Then, according to the question,

    7x + 3x + 5x = 7200

    ⇒ 15x = 7200

    ⇒ x = 480

    ⇒ 7x = 3360, 3x = 1440

    7x + 3x = 4800

    ∴ Sum of the largest and smallest number = 4800

  • Question 4/10
    3 / -0

    By selling 24 items, a shopkeeper gains the selling price of 4 items. His gain percentage is:

    Solutions

    Given:

    Gain on selling 24 items = SP of 4 items

    Concept Used:

    Calculation:

    ⇒ Let the SP of an item be Rs 100.

    ⇒ Total SP of 24 items = 24 × 100 = Rs 2,400

    ⇒ Gain = 4 × 100 = Rs 400

    ⇒ Cost Price of 24 items = 2400 – 400 = Rs 2,000

    Therefore, the gain percentage is 20%.

  • Question 5/10
    3 / -0

    3 men or 7 women finish a work in 32 days. 7 men and 5 women together will finish the twice of this work in

    Solutions

    Given:

    3 men can complete the work = 32 days 

    7 women can complete the work = 32 days 

    Formula Used:

    Work = time × efficiency 

    Calculation:

     Let the efficiency of men and women be M and W 

    ⇒ Work by men = work by women 

    ⇒ 3M × 32 = 7W × 32 

    ⇒ M : W = 7 : 3 

    ⇒ Total work = 3 × 7 × 32 = 672 units

    The efficiency of man = 7 units per day, so the efficiency of 7 men = 7 x 7 = 49 units

    similarly, the efficiency of woman = 3 units , so the efficiency of 5 women = 5 x 3 = 15 units

    Work = time × efficiency

    ⇒ 7 Men and 5 women can do twice of work = (672× 2)/(49 + 15) = 1344/64 = 21 days

  • Question 6/10
    3 / -0

    If a number is divided by 136 the remainder gets 36, then if the number is divided by 17. What will be the remainder?

    Solutions

    Given,

    1 Divisor = 136

    2 Divisor = 17

    1 Remainder = 36

    Formula Used:

    Dividend = Divisor × Quotient + Remainder

    Calculation -

    Let the given number divided by 136 gives the quotient K and remainder 36

    ⇒ The given number = (136K + 36)

    ⇒ (17 × 8K) + (17 × 2) + 2

    ⇒ 17(8K + 2) + 2

    Hence the given number is divided by 17 and the remainder will get = 2

  • Question 7/10
    3 / -0

    A 440 m long train crosses another 160 m long train in 120 seconds. Both trains are moving in the same direction. If the speed of first train is 50 m/s, find the speed of other train.

    Solutions

    Given:

    Length of two train = 440 m and 160 m

    Time = 120 seconds

    Speed of one train = 50 m/s

    Formula used:

    When the two objects are moving in the same direction, then their relative speed is the difference of their speeds,.hence,

    Time = (length of train (1) + length of train(2)/[(Speed of train(1) - Speed of train (2)]

    Calculation:

    Let the speed of other train be x m/s.

    120 = (440 + 160)/(50 - x)

    ⇒120 = 600/(50 - x)

    ⇒ 6000 - 120x = 600

    ⇒ 5400 = 120x

    ⇒ 5400/120 = x

    ⇒ 45 m/s = x

    ∴ Speed of other train is 45 m/s

  • Question 8/10
    3 / -0

    A man increases his speed to 11/6 times of his original speed. By doing this he reaches his office 20 minutes before the usual time. Find the time he usually takes.

    Solutions

    GIVEN:

    Man speed increases to 11/6 times his original speed

    Difference in time before and after increasing speed is 20 min

    FORMULA USED:

    Distance = Speed × Time

    CALCULATION:

    Let the distance be d

    Let the original speed be 6x

    New speed = 11/6 × 6x = 11x

    Now, according to the given question we have

    d/6x - d/11x = 20

    ⇒ ( 11d - 6d) /66x = 20

    ⇒ 5d/66x = 20

    ⇒ 5d = 1320x  ⇔ d = 264x

    Now, original time = distance/ original speed

    ⇒ d/6x = 264x/6x = 44  minutes ......[d = 264x]

    Hence, original time taken is 44 minutes.

  • Question 9/10
    3 / -0

    Solutions

  • Question 10/10
    3 / -0

    If the edge of a cube is increased by 2 cm, the volume will increase by 488 cm3. What then will be the length of each edge of the cube?

    Solutions

    Let the length of the cube be x cm

    ⇒ The length after 2 cm increase = x + 2 m

    ⇒ Initial volume = x3

    ⇒ Volume after increasing side = (x + 2)3

    ⇒ (x + 2)3 – x3 = 488

    ⇒ x3 + 6x2 + 12x + 8 – x3 = 488

    ⇒ 6x2 + 12x – 480 = 0

    ⇒ x2 + 2x – 80 = 0

    ⇒ (x – 8) (x + 10) = 0

    ⇒ x = 8, -10

    ⇒ x = 8 cm

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)


  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now