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SSC GD 2025 Aptitude Test - 5
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SSC GD 2025 Aptitude Test - 5
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  • Question 1/10
    2 / -0.5

    One round of a circular park having radius 21 m is the same as that of a square park. What is the length of the side of the square park?

    Solutions

    Given:

    One round of a circular park having a radius of 21 m is the same as that of a square park. 

    Concept used:

    The circumference of a circle = 2πR (R being the Radius)

    The perimeter of a square = 4 × side

    Calculation:

    One round of a circular park is the same as that of a square park means the perimeter of the square park and the circumference of the circular park is the same.

    Circumference of the circular park = 2π × 21 = 132 m

    Now, the length of the side of the square park = 132/4 = 33 m

    ∴ The length of the side of the square park is 33 m.

  • Question 2/10
    2 / -0.5

    What is the simple interest (in Rs) on a principal of Rs. 1800 at the rate of 8% per annum for 3 years?

    Solutions

    Let P = principle, N = time and R = rate percent per annum

    Then,

    Simple interest = (P × N × R)/100

    Given,

    P = 1800, R = 8% and N = 3

    Simple interest =

    = (1800 × 8 × 3)/100

    = 432

    ∴ Simple interest is Rs.432 on a principal of Rs. 1800 at the rate of 8% per annum for 3 years.

  • Question 3/10
    2 / -0.5

    In a class out of 90 students, 60% are girls and the rest of boys. If the average marks of girls are 62 and the average marks of boys are 70, then find the average of all the students in the class.

    Solutions

    Given:

    Total student = 90

    Average marks of girls = 62

    Average marks of boys = 70

    Formula used:

    Average = Sum of Data/Number of data

    Calculation:

    Girls in the class =  60% of 90 = 54

    Boys in the class = 90 - 54 = 36

    Average of all student = [54 × 62 + 36 × 70]/90

    =(3348+2520)/90

    ⇒ 5868/90 = 65.2

    ∴ The average marks of all student is 65.2

  • Question 4/10
    2 / -0.5

    A train 130 m long crosses a 110 m long bridge in 7.5 seconds. What is the speed of the train in km/h?

    Solutions

    Given:

    Length of train = 130 m

    Length of bridge = 110 m

    Time taken to cross to bridge = 7.5 seconds

    Concept:

    The length calculated to cross the bridge is the length of the train and the bridge added together.

    Formula used:

    Speed = Distance/Time

    Conversion from m/s to km/h = Multiply with 18/5

    Calculation:

    The total distance travelled by the train = 130 m + 110 m

    ⇒ 240 m

    Speed of the train while crossing the bridge = 240/7.5 m/s

    ⇒ 32 m/s

    Speed of the train in km/h = {32 × (18/5)} km/h

    ⇒ 115.2 km/h

    ∴ The speed of the train is 115.2 km/h.

  • Question 5/10
    2 / -0.5

    What will be the highest four-digit number which when divided by 3, 7, and 21 leaves the remainder 2?

    Solutions

    Given:

    The highest four-digit number which when divided by 3, 7, and 21 leaves the remainder 2.

    Concept used:

    Concept of LCM

    Calculation:

    According to the questions,

    The highest four-digit number = 9999

    L. C. M of  3, 7, and 21 = 21

    ⇒ 9999 ÷  21 

    Remainder = 3

    Now, 

    Divisible number = 9999 – 3 = 9996

    The required number that will leave the remainder 2

    ⇒ 9996 + 2 = 9998

    ∴ The highest four-digit number is 9998.

  • Question 6/10
    2 / -0.5

    If the price of a Pen is reduced by 30 Percent, it enables the customer to buy 5 more pens for Rs. 140. Find the reduced rate of Pen.

    Solutions

    Given:

    The price of pens was reduced by 30% due to which students bought 5 more pens.

    Total money spent on purchasing pens = Rs. 140

    Concept used:

    Total expenditure = Price × Quantity

    Calculation:

    Let the price of one pen be Rs. x and the number of pens purchased be Rs. y.

    Original expenditure = Price × Quantity

    ⇒ x × y = Rs. 140

    Reduced price/new price of pen = x – 30% of x

    ⇒ 70% of x

    ⇒ 0.70x

    New expenditure = 0.70x × (y + 5)

    ⇒ 0.70xy + 3.5x = Rs. 140

    ⇒ 0.70 × 140 + 3.5x = Rs. 140

    ⇒ 98 + 3.5x = Rs. 140

    ⇒ 3.5x = 42

    ⇒ x = Rs. 12

    Reduced rate of pen = 0.70x

    = 0.70 × Rs. (12)

    ⇒ Rs. 8.4

    ∴ The reduced price of the pen is Rs. 8.4.

  • Question 7/10
    2 / -0.5

    One single discount which is equivalent to 20%, 10% and 5% is given by:

    Solutions

    GIVEN:

    Successive discounts = 20% , 10% and 5% 

    FORMULA USED:

    Successive discount = X + Y - (XY)/100

    Where,

    X = First discount

    Y = Second discount.

    CALCULATION:

    Let us take first two discounts i.e. X = 20%, Y = 10%.

    ⇒ Successive  discount

    ⇒ X + Y - (X Y)/100

    ⇒ 20 + 10 - (20 × 10 )/100 = (30 - 2) = 28%.

    Now, Again X = 28% , Y = 5% 

    Successive discount

    ⇒ X + Y - (X × Y)/100 

    ⇒ 28 + 5 - (140/100) = (33 - 1.4) = 31.6%.

    Hence, one single equivalent discount is 31.60%.

    Shortcut Trick

    Let MP be 100

    SP after discount = 100 × 80% × 90% × 95%

    ⇒ 68.4.

    Hence, Discount = 100 - 68.4 = 31.6

    ∴ Discount% = 31.6%

  • Question 8/10
    2 / -0.5

    If 40% of a number is less than its 60% by 30, then the 20% of that number is:

    Solutions

    Given:

    40% of a number is less than its 60% by 30.

    Formula:

    x% of a number = Actual number × (x/100)

    Calculation:

    Let a number be x, then

    According to the question

    x × (60/100) - x × (40/100) = 30

    ⇒ x × (20/100) = 30

    ⇒ x = 30 × 5

    ⇒ x = 150

    Hence, 20% of 150

    ⇒ 150 × (20/100)

    ⇒ 30

    Shortcut Trick

    60% of a number - 40% of a number = 30

    ⇒ 20% of that number = 30

  • Question 9/10
    2 / -0.5

    20 - 2[25% of (15 × 8 ÷ 6 + 12)] = ______

    Solutions

    Concept Used:

    Calculation:

    ⇒ 20 - 2[25% of (15 × 8 ÷ 6 + 12)]

    ⇒ 20 - 2[25% of (15 ×4/3 + 12)]

    ⇒ 20 - 2[25% of (5 × 4 +12)]

    ⇒ 20 - 2[25% of (20 + 12)]

    ⇒ 20 - 2[25% of 32]

    ⇒ 20 - 16

    ∴ 4

  • Question 10/10
    2 / -0.5

    Namitha gives a 20% discount on all things in her shop and yet makes a profit of 12%. What is the cost price of an item with marked price of ₹280?

    Solutions

    Given:

    Profit = 12%

    Discount = 20%

    Marked Price = ₹280

    Formula Used:

    MP/CP = (100 + Profit%)/(100 - Discount%)

    Calculations:

    MP/CP = (100 + Profit%)/(100 - Discount%)

    ⇒ 280/CP = (100 + 12)/(100 - 20)

    ⇒ 280/CP = (112)/(80)

    ⇒ 280/CP = 7/5

    ⇒ CP = 5/7 × 280

    ⇒ CP = ₹200

    ∴ The answer is ₹200.

    Shortcut Trick

    Discount % = 20% = 1/5

    Ratio of M.P. to S.P. = 5 : 4  }×7

    Profit % = 12% = 3/25

    Ratio of C.P. to S.P. = 25 : 28

    So, combined ratio of C.P: S.P : M.P. = 25 : 28 : 35

    ⇒ 35 units = Rs. 280

    ⇒ 25 units = (280/35) × 25 = Rs. 200

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