Please wait...

SSC GD 2025 Aptitude Test - 7
Menu grid icon
Result Result point icon
SSC GD 2025 Aptitude Test - 7
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    2 / -0.5

    In union president election in a college between two candidates, the winner secured 85% of the total votes cast and wins by a margin of 5600 votes. How many votes did the losing candidate get?

    Solutions

    Given:

    the winner secured 85% of the total votes cast and wins by a majority of 5600 votes

    Calculation:

    let 100% be the total votes cast

    the winner secured 85% of the total votes cast,

    Winning Candidate = 85%

    Losing Candidate = 15%

    Winning Candidate wins by a majority of 5600 votes,

    Winning Candidate - Losing Candidate = 5600

    85% - 15% = 5600

    70% = 5600

    1% = 80

    Losing Candidate got 15%

    15% = 15 × 80

    = 1200 votes

    Answer is 1200.

  • Question 2/10
    2 / -0.5

    A person follows a strict diet and loses his weight from 80 kg to 72 kg in a month. The percent weight loss of the person is:

    Solutions

    Given:

    Initial weight = 80kg, Final weight = 72kg

    Concept:

    Percentage decrease = (Initial - Final) / Initial × 100%

    Calculation:

    ⇒ (80-72)/80 × 100% = 10%

    Therefore, the person's percent weight loss is 10%.

  • Question 3/10
    2 / -0.5

    A rectangular room is 12 meter long, 6 meter wide and 4 meter high. It has two doors of size 2 meter × 1 meter each and two windows of size 1.5 meter × 1 meter each. If the rate of paint (on the walls) is Rupees 15 per square meter, then total cost of painting the walls is - 

    Solutions

    Given:

    Length, breadth and height of a rectangular room are given as 12 m, 6 m and 4 m respectively.

    The room has two doors of size 2 m × 1 m.

    The room has two windows of size 1.5 m × 1 m.

    Rate of paint = 15 Rupees per meter

    Calculation:

    Area of walls = 2 h(l + b), where l = length, b = breadth and h = height

    Area of walls = 2 × 4(12 + 6)

    Area of walls = 144 m2
    So, area of walls including doors and windows = 144 m2

    Area of  door = l × b = 2 × 1 = 2 m

    Area of two doors= 2 × area of one door = 2 × 2 = 4 m2

    Area of window = l × b = 1.5 × 1 = 1.5 m2

    Area of two windows = 2 × area of one window = 2 × 1.5 = 3 m2

    So, area of walls excluding the two doors and two windows=

    144 - 4 - 3 = 137 m2

    Cost of painting the four walls = 137 × 15 = 2055 m2

    Hence, option 4 is correct.

  • Question 4/10
    2 / -0.5

    The amount received after 8 years on a certain sum of money invested at the rate of 18% simple interest per annum is Rs. 1,220. What was the initial sum invested?

    Solutions

    Given:

    Time = 8 years

    Interest rate = 18% p.a.

    Amount received after 8 years = Rs 1,220

    Concept Used:

    Simple Interest = P × R × T / 100

    Calculation:

    Let the sum of money invested be Rs x.

    SI = x × 18 × 8 / 100 = 36x / 25

    According to the question,

    ⇒ x + 36x / 25 = 1220

    ⇒ 25x + 36x = 1220 × 25

    ⇒ 61x = 30,500

    ⇒ x = 30500 ÷ 61 = 500

    Therefore, the sum of money invested is Rs 500.

  • Question 5/10
    2 / -0.5

    An article costs ₹750. It is marked up to give 30% profit. What is the selling price if a customer gets a discount of 15% on it?

    Solutions

    Given:

    An article costs ₹750. It is marked up to give 30% profit.

    Concept used:

    Selling price = Marked price × (100 - Discount)%

    Calculation:

    Marked up price = 750 × 130%

    ⇒ 975

    Now after discount the selling price of 975 × 85%

    ⇒ 828.75

    ∴ The selling price if a customer gets a discount of 15% on it will be ₹828.75.

  • Question 6/10
    2 / -0.5

    A police officer follows a thief who is at a distance of 800 m from him. If they run at a speed of 8 km/h and 7 km/h, respectively, how long does the police officer have to run to catch up with the thief?

    Solutions

    Given:

    Distance between the thief and the police officer = 800 m

    Speed of the police officer = 8 km/h = 8000 m/h

    Speed of the thief = 7 km/h = 7000 m/h

    Solution:

    ⇒ Relative speed of the police officer with respect to the thief = 8000 - 7000 = 1000 m/h

    ⇒ Time required to catch up with the thief = Distance/Relative speed = 800/(1000/3600) = 2880 seconds = 0.8 hours

    ⇒ Distance covered by the police officer = Speed × Time = 8000 × 0.8 = 6400 m

    Hence, the police officer has to run 6400 m to catch up with the thief.

  • Question 7/10
    2 / -0.5

    Speeds of a boat along the current and against the current are 16 km/hr and 12 km/hr respectively. What is the speed (in km/hr) of the current?

    Solutions

    Given,

    Speed downstream = 16km/hr

    Speed upstream = 12km/hr

    Formula used:

    Speed of the current = ½ × (speed downstream - speed upstream)

    Calculation:

    Speed of the current = ½ × (16 - 12) = 4/2 = 2

    ∴ Speed of the current is 2km/hr.

  • Question 8/10
    2 / -0.5

    Directions For Questions

    The following bar chart shows the runs given amd overs bowled by a bowler in 6 different matches.

    ...view full instructions


    What will be the economy rate of the bowler for all the 6 matches taken together? [Give your answer correct to 2 decimal places.]

    Solutions

    Calculation:

    Now, the economy rate of the bowler for all 6 matches taken together

    ⇒ 6.10 (approx)

    ∴ The economy rate of the bowler for all 6 matches taken together is 6.10.

  • Question 9/10
    2 / -0.5

    Kaushik bought a toy for Rs. 160 and sold it for Rs. 180. The rate of profit was _______%

    Solutions

    Selling Price = 180, Cost Price = 160

    Profit = SP - CP

    ⇒ 180 - 160 = 20

    Profit % = Profit/CP × 100

    ⇒ (20/160)× 100 = 12.5%

  • Question 10/10
    2 / -0.5

    By selling a computer for Rs. 30,875, a shopkeeper suffers a loss of 5%. At what price should he sell it to gain 7%?

    Solutions

    Given:

    SP = 30,875

    Loss = 5%

    Formula Used:

    SP = CP(100 - loss)/100

    SP = CP(100 + profit)/100

    Calculation:

    Find the CP at 5% Loss

    ⇒ 30875 = CP(100 - 5)/100

    ⇒ CP = (30875 × 100)/95

    ⇒ CP = 32500

    Find the SP at 7% Gain

    ⇒ SP = 32500(100 + 7)/100

    ⇒ SP = 325 × 107

    ⇒ SP = 34775

    ∴ Option 4 is the correct answer.

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)


  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now