Given:

15, 16, 32, 35, 140, 145,?

Logic: Consecutive odd numbers are added alternatively and multiply by consecutive even numbers alternatively.

Here, '870' is the next number.

Hence, the correct answer is "Option (2)".

Given:

Week days: i.e., starting on Monday and ending on Saturday.

Number of fruits: 6

Name: Oranges, Apples, Coconut, Banana, Litchi and Mango.

Explanation:

i) The fruit banana is eaten on Monday.

ii) Mango is eaten on the third day after banana.

iii) Only one fruit is eaten between Mango and Litchi.

Case 1: 

Case 2: 

 iv) Coconut is eaten on the day just after the mango.​

Case 1: 

Case 2: 

v) Apple is eaten on the day immediately before Oranges.

Since Apple and oranges are eaten on consecutive days so this can be placed on Tuesday and Wednesday.

This eliminates Case1: 

So orange is eaten on Wednesday.

Hence, "Wednesday" is the correct answer.

Alphabets & their positional values:

The pattern followed here is:

First, second, fourth & fifth alphabets are decreased by - 2.

The third alphabet is increased by + 2.

Now, replacing the sign from left to right and using BODMAS rule, we get :

New equation : 4 × 12 + 18 - (72 ÷ 6) = ?

Calculation :

⇒ 4 × 12 + 18 - (72 ÷ 6) = ?

⇒ 4 × 12 + 18 - 12 = ?

⇒ 48 + 18 - 12 = ?

⇒ 66 - 12 = 54.

Hence, the correct answer is "Option 2".

The least possible Venn diagram for the given statements is as shown below :

Conclusions:

I. Some Bangles are Rings → Does not Follow (As some bangles are bracelets, some bracelets are chains and all chains are rings. So, it is possible but not definitely true)

II. Some Chains are Bangles → Does not Follow (As some bangles are bracelets, some bracelets are chains and all chains are rings. So, it is possible but not definitely true)

III. Some Rings are Bracelets → Follow (As some bracelets are chains and all chains are rings. So, as whole chains comes in rings which some part comes in bracelets therefore it is definitely true)

∴ Here, Only Conclusion III follows​

Hence, the correct answer is "Only Conclusion III follows"

The diagram below shows the path followed by Paras and Shyam:

Here, 'O' is the starting point from where both Paras and Shyam have started walking and Paras reached at point 'M' and shyam reached at point 'K'.

So, distance between Paras and Shyam = (90 + 20) = 110 m and Point 'K' is in East direction of point 'M'.

Hence, "110m East" is the correct answer.

In an ordinary year, there are 365 days and on dividing 365 by 7,

we get remainder = 1, so this extra one day is taken as an odd day.

Similarly, in a leap year, there are 366 days and on dividing 366 by 7,

we get remainder = 2, so these extra days are taken as the odd days.

Thus, the remainder, which we get after dividing the number of days by 7 is considered as odd days.

1666 = we find out the odd days (the nearest leap year + completing year) = 1600 + 65

In 1600 years the odd days = 0

In 65 years the odd days = 65/4 = 16 leap years and 49 normal years.

In 16 leap years the odd days = 32, and 49 normal years = 49

So total = 32 + 49 = 81 odd days i.e. 81/7 = 4 odd days (remainder)

Odd days in May = 145 days i.e. 5 odd days.

Total  = 4 + 5 = 9/7 = 2 odd days.

Tuesday of the week was 25 May 1666.

Hence, "option 1" is the correct answer.

Key Points

May 25, 1666 was the 145th day of the year 1666 in the Gregorian calendar. There were 220 days remaining until the end of the year. The day of the week was Tuesday.

The given codes are:

Mango is the king of fruit → @ $ % & H E.

The king lives in the palace → @ H U @ # !

Palace wise king → G H #

The logic follows here is:

Therefore, from the above codes, it is clear that the code for 'wise' is 'G' and the code for 'the' is '@'.

Hence, the correct answer is G @.

The pattern followed here is:

From the above figure, only option(3) shows the correct answer

Hence, the correct answer is option(3)

The logic followed here is:

Given Sequence: jtm _ r _ jt _ prs _ tmpr _ j _ mprs

Now, putting the letters in the blank spaces given in the option one by one:

Option 1) psmjst → j t m p r s / j t m p r s / J t m p r s / j t m p r s.

Here, 'Option 1' followed a pattern.

Option 2) pssjst → j t m p r s / j t s p r s / J t m p r s / j t m p r s.

Option 3) psmjts → j t m p r s / j t m p r s / J t m p r t / j s m p r s.

Option 4) pmsjst → j t m p r m / j t s p r s / J t m p r s / j t m p r s.

Hence, the correct answer is "Option 1".