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Reasoning Test 192
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Reasoning Test 192
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  • Question 1/10
    1 / -0.33

    Study the following arrangement of letters and symbols (from Left to Right) and answer the question that follows:

    (Left) Z D @ Y $ F M J % L R & G I O * A # N V @ P Q ^ E W U ? C (Right)

    How many symbols are there in this arrangement which is immediately preceded by a consonant?

    Solutions

    According to the given information,

    A symbol should be immediately preceded by a consonant.

    Pattern = Consonant → Symbol

    The symbols that are immediately preceded by a consonant are as shown below:

    (Left) Z D @ Y $ F M J % R & G I O * A # N V @ P Q ^ E W U ? C (Right)

    For the following combinations, the condition is satisfied:

    [D@], [Y$], [J%], [R&], [V@], [Q^]

    Thus, six symbols are immediately preceded by a consonant in the given series.

    Hence, ‘6’ is the correct answer.

    Mistake Points

    (Left) Z D @ Y $ F M J % L R & G I O * A # N V @ P Q ^ E W U ? C (Right)

    [A #] [U ?] are not the part of the sequence because A and U are vowels.

     

  • Question 2/10
    1 / -0.33

    If '+' means '÷' , '-' means '+', '×' means '-' and '÷' means '×', what will be the value of the following expression?

    [{(49 × 12) - (6 ÷ 2)} + (4 - 3)] ÷ 5

    Solutions

     

  • Question 3/10
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    If 21st June 2007 was a Thursday, then what was the day of the week on 21st June 2011 ?

    Solutions

    Given : 21st June 2007 was a Thursday

    • Total number of days in a normal year = 365 days
    • Number of odd days in a normal year = 365/7 = 1 day
    • Total number of days in a leap year = 366 days
    • Number of odd days in a leap year = 366/7 = 2 days
    • 21st June 2011 = Thursday + 2 (2008) + 1(2009) + 1(2010) + 1(2011) = Thursday + 5 odd days =  Tuesday

    Hence, 21st June 2011 held on Tuesday.

     

  • Question 4/10
    1 / -0.33

    Consider the given question and decide which of the following statements is/are sufficient to answer the question.

    P, Q, R, S, and T are sitting around a circular table facing inside the center. Who is sitting second to the right of R?

    Statements:

    I. R sits to the immediate right of P. Only two persons sitting between P and Q.

    II. Both R and S are immediate neighbour of Q. T sits second to the right of Q.

    Solutions

    Statements:

    I. R sits to the immediate right of P. Only two persons sitting between P and Q.

    According to the first statement, there will be 2 cases as follows:

    So, from this statement, we cannot be determined who sits second to the right of R.

    II. Both R and S are immediate neighbour of Q. T sits second to the right of Q.

    According to the second statement, there will be 2 cases as follows:

    So, from this statement, we cannot be concluded who is sitting second to the right of R.

    Combining both statements:

    Case - 1 of statement 1 and Case - 1 of statement 2 give the result:

    Hence, Data in both statements I and II together are sufficient to answer the question.

     

  • Question 5/10
    1 / -0.33

    Read the give statements and conclusions carefully. Decide which of the given conclusion(s) follow(s) based on the given statements.

    Statement:

    M ≤ N < O, A ≥ B < C = O

    Conclusions:

    I. N > B

    II. C > M

    Solutions

    Given: M ≤ N < O, A ≥ B < C = O

    The combined inequality can be represented as: A ≥ B < C = O > N ≥ M

    Explanation:

    I. N > B → False ( as N < O = C > B → a definite relation between N and B cannot be determined))

    II. C > M → True ( as C = O > N ≥ M is defined  relation between C and M)

    Hence, Only conclusion II follows.

     

  • Question 6/10
    1 / -0.33

    Which two signs should be interchanged to make the below equation mathematically correct?

    27 + 36 × 32 - 8 ÷ 20 = 151

    Solutions

    1. - and +

    27 - 36 × 32 + 8 ÷ 20 = 151

    ⇒ 27 - 1152 + 0.4 = 151

    ⇒ 27.4 - 1152 = 151

    ⇒ -1124.6 ≠ 151


    2. + and ×

    27 × 36 + 32 - 8 ÷ 20 = 151

    ⇒ 972 + 32 - 0.4 = 151

    ⇒ 1004 - 0.4 = 151

    ⇒ 1003.6 ≠ 151


    3. ÷ and -

    27 + 36 × 32 ÷ 8 - 20 = 151

    ⇒ 27 + 36 × 4 - 20 = 151

    ⇒ 27 + 144 - 20 = 151

    ⇒ 171 - 20 = 151

    ⇒ 151 = 151


    4. + and ÷

    27 ÷ 36 × 32 - 8 + 20 = 151

     0.75 × 32 - 8 + 20 = 151

    ⇒ 24 - 8 + 20 = 151

    ⇒ 44 - 8 = 151

    ⇒ 36 ≠ 151

    Hence, '÷ and -' is the correct answer.

     

  • Question 7/10
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    In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.

    Number/Symbol

    6

    8

    4

    +

    5

    #

    %

    2

    $

    1

    ^

    7

    9

    *

    @

    Code

    S

    U

    T

    W

    N

    P

    V

    D

    A

    Z

    J

    M

    O

    M

    Y

    Conditions:

    (i) If the first and last elements are numbers, then the last element will be replaced by the symbol @.

    (ii) If the first elements is a symbol, then the first element will be coded as ©.

    (iii) If both the first and second elements are numbers, then the third element will be coded as *.

    What will be the code for the following?

    6 % $ 8 5

    Solutions

    We follow the given table and code the given combination:

    Number/Symbol

    6

    8

    4

    +

    5

    #

    %

    2

    $

    1

    ^

    7

    9

    *

    @

    Code

    S

    U

    T

    W

    N

    P

    V

    D

    A

    Z

    J

    M

    O

    M

    Y

    Given combination: 6 % $ 8 5

    Since first and last elements are numbers, first condition will be applied which says 'If the first and last elements are numbers, then the last element will be replaced by the symbol @.' so the code will contain '@' at last.

    Now none of the other conditions apply so the code becomes:

    Hence, the correct answer is option 3).

     

  • Question 8/10
    1 / -0.33

    Given is a statement followed by two arguments numbered I and II. Consider the statement and the arguments and decide which of the arguments is strong.

    Statement:

    Is the choice of junk food a better option to create interest in eating in children?

    Arguments:

    I. Yes, the best way to create interest is to give the food a child likes.

    II. No, junk food is the reason behind obesity, heart diseases, diabetes and other health problems and it is important to induce healthy eating habits in children.

    Solutions

    Anything or everything that a child likes to eat might not be good for him. One such example being junk food.

    Therefore, the first argument is weak.

    The various health issues mentioned in the second argument strongly suggest that using junk food to lure children into eating is not a good option.

    Hence, only argument II is strong.

     

  • Question 9/10
    1 / -0.33

    In a certain code language, FLAME is written as 'LPGQK', and BURNT is written as 'HYXRZ'. How will 'FRIED' be written in the same code language?

    Solutions

    Logic : Alternately (6) and then (4) is added to the position value according to the English alphabetic series.

     

  • Question 10/10
    1 / -0.33

    Four figures have been given, out of which three are alike in some manner and one is different. Select the one that is different.

    Solutions

    LOGIC: Inner and Outer figure is the same but the inner figure is 45° anticlockwise rotated.

    The inner and Outer figure is theTriangle.

    Hence, option (4) is the correct answer.

    Important point

    Side of polygons and their name:

     

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