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SSC CGL 2025 Aptitude Test - 2
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SSC CGL 2025 Aptitude Test - 2
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  • Question 1/10
    2 / -0.5

    The difference between the compound and simple interest on a sum of 'P' Rs. at R% rate of interest after 2 years is '2.25P' Rs. If the simple interest on the same sum at the same rate of interest after one year is (S - 2.25P) Rs. then what is the compound interest on the same sum at the same rate of interest after 2 years?

    Solutions

    The difference between the compound and simple interest = P × (R/100)2

    ATQ, 2.25P = P × (R/100)2

    ⇒ R2 = 22500

    ⇒ R= 150%

    The simple interest on the same sum at the same rate of interest after one year is = (S - 2.25P) Rs.

    ⇒ (P × 150 × 1)/100 = S - 2.25P

    ⇒ 1.5P = S - 2.25P

    ⇒ S = 3.75P ...(I)

    The compound interest on the same sum at the same rate of interest after 2 years = P × [(1 + (150/100))2 - 1] = 5.25P

    Using (I)

    Required CI = 5.25 × (S/3.75) = 1.4S Rs.

    Hence, the correct answer is 1.4S Rs.

  • Question 2/10
    2 / -0.5

    The average of three numbers is 16. If two numbers are 18 and 12 then the third number is:

    Solutions

    Given:

    The average of three numbers = 16.

    Two of the numbers are 18 and 12.

    Formula used:

    Average = Sum of observations/Number of observations

    Calculation:

    Let the third number be x

    According to the question,

    16 = (18 + 12 + x)/3

    ⇒ 18 + 12 + x = 16 × 3

    ⇒ 30 + x = 48

    ⇒ x = 18

    ∴ The third number is 18.

  • Question 3/10
    2 / -0.5

    The area of the circle is 2464 cm2 and the ratio of the breadth of the rectangle to radius of the circle is 6:7. If the circumference of the circle is equal to the perimeter of the rectangle, then what is the area of the rectangle.

    Solutions

    Area of the circle=πr2

    2464 = 22/7 * r2

    Radius of the circle=28 cm

    Circumference of the circle = 2 * π* r = 2 * 22/7 * 28 

    = 176 cm

    Breadth of the rectangle = 6/7 * 28=24 cm

    Perimeter of the rectangle = 2 * (l + b)

    176 = 2 * (l + 24)

    Length of the rectangle=64 cm

    Area of the rectangle = l * b=24 * 64=1536 cm2

  • Question 4/10
    2 / -0.5

    What is the diameter (in cm) of a sphere of surface area 154 sq cm?

    Solutions

  • Question 5/10
    2 / -0.5

    Directions For Questions

    The following graph given the details of the male and female population (in thousands) across five places A, B, C, D and E.

    ...view full instructions


    Based on the information, the total number of females in all five places is approximately what percentage of the total number of males in all five places?

    Solutions

    Given:

    Total number of males in all five places = 35 + 32 + 30 + 45 + 40 = 182

    Total number of females in all five places = 28 + 40 + 35 + 42 + 32 = 177

    Formula:

    x as a percent of y = x/y × 100

    Calculation:

    Percentage of the total number of females in all five places approximately the total number of males in all five places is = (177/182) × 100 = 97%

  • Question 6/10
    2 / -0.5

    A invested (2X + 1) lakhs and B invested (4X + 9) lakhs in a partnership of 28 months and 30 months respectively. The ratio of their profits after their respective time period is 2:5. What is the investment of B ?

    Solutions

    Given:

    A invested (2X + 1) lakhs and B invested (4X + 9) lakhs in a partnership of 28 months and 30 months respectively

    The ratio of their profits after their respective time period is 2:5

    Formula used:

    Profit = Investment × Time

    Calculation:

    According to the question,

  • Question 7/10
    2 / -0.5

    In what ratio should rice costing Rs. 67.5 per kg be mixed with rice costing Rs. 60 per kg to get an average price of Rs. 64 per kg?

    Solutions

    Let’s carefully recheck step by step ✅

    Cheaper rice = ₹60/kg

    Costlier rice = ₹67.5/kg

    Mean price = ₹64/kg

    Using alligation rule:

    So,

    That means cheaper rice : costlier rice = 7:8.

    But the question asks: In what ratio should rice costing ₹67.5 (costlier) be mixed with rice costing ₹60 (cheaper)?

    That means we need Costlier : Cheaper, i.e. the reverse of above.

    So the ratio = 8 : 7

    Correct Answer: 8:7 ✔️

  • Question 8/10
    2 / -0.5

    If the six digit number 15x1y2 is divisible by 44, then (x + y) is equal to:

    Solutions

    Step 2: Divisibility by 11

    Rule: (Sum of digits in odd places) − (Sum of digits in even places) must be divisible by 11.

    Number = 1 5 x 1 y 2

  • Question 9/10
    2 / -0.5

    A cylinder which is open at the bottom is surmounted by a cone at the top. The common radius is 5.5 cm, the height of the cylinder is 19.1 cm and the total height of the structure is 32.3 cm. The surface area of the structure is?

    Solutions

    Given:

    Radius = 5.5 cm

    Total height of the structure = 32.3 cm

    Height of the cylinder = 19.1 cm

    Formula used:

    The surface area of the cone = π × radius × slant height

    The surface area of the cylinder = 2 × π × radius × height

    Calculation:

    Radius = 5.5 cm

    Height of the conical part = 13.2 cm

    Slant height of the conical part = √(Radius2 + Height2)

    ⇒ √(5.52 + 13.22) = √(30.25 + 174.24)

    ⇒ √(204.49) = 14.3 cm

    ∴ The surface area of the structure = Surface area of the conical part + surface area of the cylindrical part

    ⇒ π × radius × slant height of conical part + 2 × π × radius × height of the cylindrical part

    ⇒ (22/7 × 5.5 × 14.3) + (2 × 22/7 × 5.5 × 19.1)

    ⇒ 22/7 × 5.5 × (14.3 + 2 × 19.1)

    ⇒ 22/7 × 5.5 × 52.5 = 22 × 5.5 × 7.5

    ⇒ 907.5 cm2

    ∴ The Surface area of the structure is 907.5 cm2.

  • Question 10/10
    2 / -0.5

    Solutions

    ✅ Final Answer: 119/10

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