Please wait...

SSC CGL 2025 Aptitude Test - 3
Menu grid icon
Result Result point icon
SSC CGL 2025 Aptitude Test - 3
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    2 / -0.5

    The distance between the centres of two circles touching extemally is 11 cm. If the sum of their areas is 73π cm 2, then the radius of the larger circle is

    Solutions

    Given:

    r + R = 11 cm

    Sum of area = 73π cm2

    Concept used:  

    Area of circle = π r2

    Calculation:

    Let, the radius of two circles be r and R.

    ⇒ r + R = 11 cm    

    ⇒ r = 11 - R → (1)

    ⇒ π r2+ π R2= 73 π 

    ⇒ r2+ R 2= 73

    On putting the value of r from equation (1) in equation (2),

    ⇒ (11 - R)2+ R 2= 73

    ⇒ 121 + 2R2- 22R = 73

    ⇒ 2R2- 22R + 48 = 0

    ⇒ R2- 11R + 24 = 0

    ⇒ R2- 3R - 8R + 24 = 0

    ⇒ R(R - 3) - 8(R - 3) = 0

    ⇒ (R - 3)(R - 8) = 0

    ⇒ R = 3 or 8

    The largest radius = 8 cm

    ∴ The radius of the larger circle is 8 cm

  • Question 2/10
    2 / -0.5

    The marked price of an article is Rs. 660. A shopkeeper allows a discount of 20% and still gets a profit of 10%. If he sells it for Rs. 470, his profit or loss per cent, correct to two decimal places will be:

    Solutions

    Let’s carefully solve step by step:

    Step 1: Find the cost price (C.P.) of the article.

    Marked Price (M.P.) = Rs. 660

    Discount = 20% → Selling Price after discount (S.P.) = 660 × (80/100) = 528

    At this selling price (528), shopkeeper still gains 10%.

    So, Cost Price = 528 ÷ 1.10 = 480

    Step 2: Now check when S.P. = Rs. 470

    C.P. = 480

    S.P. = 470

    Loss = C.P. – S.P. = 480 – 470 = 10

    Loss % = (Loss ÷ C.P.) × 100 = (10 ÷ 480) × 100 = 2.0833% ≈ 2.08%

    ✅ Answer: Loss 2.08%

  • Question 3/10
    2 / -0.5

    Calculate the trapezium’s area if length of its two parallel sides are a = 22.4 cm and b = 23.6 cm and distance between them is 10 cm.

    Solutions

  • Question 4/10
    2 / -0.5

    What will be the sum of all natural numbers lying between 100 to 200 which leave a remainder 2 when divided by 5 in each case?

    Solutions

  • Question 5/10
    2 / -0.5

    If the height is doubled and the base is decreased by 20%, then the ratio of old area of the triangle  and new area of the triangle is -

    Solutions

    Given:

    height is doubled and the base is decreased by 20%,

    Formula Used:

  • Question 6/10
    2 / -0.5

    Solutions

  • Question 7/10
    2 / -0.5

    The table below shows the passing percentage of four schools in four years.

    Name of school

    2012-13

    2013-14

    2014-15

    2015-16

    PQR

    27%

    31%

    45%

    67%

    ABC

    61%

    65%

    50%

    78%

    DEF

    95%

    86%

    80%

    70%

    XYZ

    92%

    82%

    78%

    71%

    The percentage of which school is increasing sequentially (gradually)?

    Solutions

    Answer: PQR

    Step-by-step

    Check year-on-year trend for each school:

    • PQR: 27 → 31 → 45 → 67 — increases every year ✅

    • ABC: 61 → 65 ↑, then 50 ↓, then 78 ↑ — not sequential

    • DEF: 95 → 86 → 80 → 70 — decreasing

    • XYZ: 92 → 82 → 78 → 71 — decreasing

    Only PQR shows a continuous (monotonic) increase across all four years.

    Quick Tip

    For “increasing/decreasing sequentially” questions, just scan differences between consecutive years:

    • If all differences are positive → increasing.

    • If all are negative → decreasing.

    • Any mix → not sequential.

  • Question 8/10
    2 / -0.5

    What is the digit in the unit place of (24)63 + (33)61 - (27)58?

    Solutions

    ✅ Final Answer: 8

  • Question 9/10
    2 / -0.5

    The sum of all even numbers between 1 and 55 is

    Solutions

    Formula used:

    Sum of n terms of an AP = (n/2) [a + l] = (n/2) [2a + (n - 1)d]

    Where n = number of terms, d = Common difference, l = Last term, and a = first term

    Calculation:

    Even numbers between 1 and 55

    a = 2, l = 54

    Sum of even numbers = (n/2) [a + l]

    Here, n is number of even terms  = 27

    ⇒ (27/2) [2 + 54]

    ⇒ 27 × 28

    ⇒ 756

    ∴ The sum of all even numbers between 1 and 55 is 756

  • Question 10/10
    2 / -0.5

    The given bar chart shows the number of students in a class who have secured marks in three ranges: > = 75%, 60% - 74% and <60%.

    From the given information, identify how much percent of girls got distinction. (Note - Distinction refers to marks that are equal to or more than 75%)

    Solutions

    Given:

    Number of girls who got marks (> = 75%) = 7

    Number of girls who got marks (60% - 74%) = 53

    Number of girls who got marks (<60%) = 5

    Calculation:

    Total number of girls = 7 + 53 + 5 = 65

    7 girls got distinction

    So, % of girl who got distinction

    ⇒ (7/65) × 100

    ⇒ 700/65

    ⇒ 10.76

    ⇒ Percentage = 10.76%

    ∴ 10.76% of girls got distinction

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now